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bharath.e

  • 3 years ago

hydrogen behaves as an oxidising agent in its reaction with a,chlorine b,pottasium c,nitrogen d,sulphur

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  1. chmvijay
    • 3 years ago
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    no it act as reducing agent not as oxidising agent !!!!

  2. panlac01
    • 3 years ago
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    http://chemed.chem.purdue.edu/genchem/topicreview/bp/ch19/oxred_3.php

  3. agentx5
    • 3 years ago
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    L E O (Loosing Electrons, Oxidized) = Reducing Agent G E R (Gaining Electrons, Reduced) = Oxidizing Agent Process of elimination makes this easy: Chlorine is missing 1 valence electron of a full outer set Potassium has 1 extra valence electron; if it looses it, it'll be at a full outer set Nitrogen is missing 3 or has 5 extra depending on how you look at it. Sulfur is missing 2 valence electrons of a full outer set If that wasn't clear which one of these things is not like the others, then I will show you an example of each (sorry @chmvijay , but there are exceptions to the rule) L E O reaction for hydrogen (hydrogen is stripped of it's electron) H\(_2\)(g) + Cl\(_2\)(g) \(\rightarrow\) 2 HCl(g) G E R reaction for hydrogen (hydrogen picks up potassium's extra electron) 2 K(s) + H\(_2\)(g) \(\rightarrow\) 2 KH(s) By definition. :-)

  4. agentx5
    • 3 years ago
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    Make sense now @bharath.e ?

  5. agentx5
    • 3 years ago
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    http://en.wikipedia.org/wiki/Potassium_hydride

  6. bharath.e
    • 3 years ago
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    so wats d answere @agentx5

  7. agentx5
    • 3 years ago
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    I think it's pretty clear what the answer is going to be... Did you read what I wrote? :-/ Also, I know you're new here but, read please: http://openstudy.com/code-of-conduct

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