anonymous
  • anonymous
hydrogen behaves as an oxidising agent in its reaction with a,chlorine b,pottasium c,nitrogen d,sulphur
Chemistry
katieb
  • katieb
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chmvijay
  • chmvijay
no it act as reducing agent not as oxidising agent !!!!
anonymous
  • anonymous
http://chemed.chem.purdue.edu/genchem/topicreview/bp/ch19/oxred_3.php
anonymous
  • anonymous
L E O (Loosing Electrons, Oxidized) = Reducing Agent G E R (Gaining Electrons, Reduced) = Oxidizing Agent Process of elimination makes this easy: Chlorine is missing 1 valence electron of a full outer set Potassium has 1 extra valence electron; if it looses it, it'll be at a full outer set Nitrogen is missing 3 or has 5 extra depending on how you look at it. Sulfur is missing 2 valence electrons of a full outer set If that wasn't clear which one of these things is not like the others, then I will show you an example of each (sorry @chmvijay , but there are exceptions to the rule) L E O reaction for hydrogen (hydrogen is stripped of it's electron) H\(_2\)(g) + Cl\(_2\)(g) \(\rightarrow\) 2 HCl(g) G E R reaction for hydrogen (hydrogen picks up potassium's extra electron) 2 K(s) + H\(_2\)(g) \(\rightarrow\) 2 KH(s) By definition. :-)

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anonymous
  • anonymous
Make sense now @bharath.e ?
anonymous
  • anonymous
http://en.wikipedia.org/wiki/Potassium_hydride
anonymous
  • anonymous
so wats d answere @agentx5
anonymous
  • anonymous
I think it's pretty clear what the answer is going to be... Did you read what I wrote? :-/ Also, I know you're new here but, read please: http://openstudy.com/code-of-conduct

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