Can someone help me solve this calc problem? It's attached.

- anonymous

Can someone help me solve this calc problem? It's attached.

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- jamiebookeater

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- anonymous

##### 1 Attachment

- anonymous

Sample problem:

##### 1 Attachment

- anonymous

you have the solution with the explanation, so what else do you need?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

I have a sample problem. I've tried applying the steps to the actual problem but it's confusing.

- anonymous

So instead of substituting 6 and 1 into the v's, you'll substitute 5 and 2.

- anonymous

The substitution takes place at the part where the expression is in square brackets. [ ]

- anonymous

You'll plug in 5 first and evaluate. Keep that answer on the side somewhere.
Then you'll go back to the square brackets again, plug in 2 and evaluate. Whatever you get as the answer, you'll subtract that from the answer you got when you plugged in 5.

- anonymous

Can you wait while I do it, and tell me if it's correct?

- anonymous

Yes.

- anonymous

I got 77.5 when I plugged in 5.

- anonymous

I got -7.5

- anonymous

There's an extra negative sign next to the red negative sign. Ignore the extra one.

- anonymous

\[{-3(5)^{2}\over 2}+6(5)\]

- anonymous

Okay, so if I plug in 1, I'll get -3/2+8 = 6.5

- anonymous

No. 4.5.

- anonymous

Look at the equation I wrote above.

- anonymous

What do you get when you evaluate that expression?

- anonymous

Oh, I forgot to square it.

- anonymous

Then I get: (-7.5+4.5) - (-3/2 +8) = -9.5 or -19/2.

- anonymous

It's cool.

- anonymous

It's not correct though.

- anonymous

You're doing more than what it's asking for. The only values you're evaluating are 5 and 2. Not 6 and 1.

- anonymous

6 and 1 are solely used in the example.

- anonymous

You never answered my question. What do you get when you evaluate the expression I wrote above?

- anonymous

-7.5

- anonymous

Awesome. Now imagine the 5 is gone and a 2 is in its place in the expression above. What do you get now?

- anonymous

Replace BOTH 5s with 2s. Not just the one on the left.

- anonymous

6

- anonymous

Perfect. Now the last step is subtracting that 6 from -7.5:
-7.5 - 6 =

- anonymous

-13.5

- anonymous

Awesome : )

- anonymous

But if you look at the sample problem, they subtracted another part too.

- anonymous

They subtracted the value of the expression when a 1 was plugged in.
We subtracted the value of the expression when a 2 was plugged in.

- anonymous

I got -8 and it's still wrong.

- anonymous

-8 on which problem?

- anonymous

Ugh. It's + 8 not +6

- anonymous

\[{-3v ^{2} \over 2}+8v\]

- anonymous

Answer: -7.5 or -15/2

- anonymous

Okay

- anonymous

Sorry. I thought the expressions were the same in the example and actual problems.

- anonymous

It's okay. Can you help with another problem?

- anonymous

If you're not busy?

- anonymous

Sure.

- anonymous

##### 1 Attachment

- anonymous

Sample:

##### 1 Attachment

- anonymous

4/3

- anonymous

Start off exactly as the example starts by dividing u and -4 by the square root of u.
This gives you:
\[\int\limits_{1}^{9}u ^{1/2}-4u ^{-1/2}\]

- anonymous

Then integrate each term.

- anonymous

\[[{2 \over 3}u ^{3/2}-8u ^{1/2}]\]

- anonymous

Plug in 9 first, and evaluate.
Plug in 1 afterwards, then evaluate.
Subtract the second answer from the first one.

- anonymous

Take care and don't forget to mark a Best Response. Thank you

Looking for something else?

Not the answer you are looking for? Search for more explanations.