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hiralpatel121

  • 2 years ago

Can someone help me solve this calc problem? It's attached.

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  1. hiralpatel121
    • 2 years ago
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  2. hiralpatel121
    • 2 years ago
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    Sample problem:

  3. myko
    • 2 years ago
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    you have the solution with the explanation, so what else do you need?

  4. hiralpatel121
    • 2 years ago
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    I have a sample problem. I've tried applying the steps to the actual problem but it's confusing.

  5. coreylvaughn
    • 2 years ago
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    So instead of substituting 6 and 1 into the v's, you'll substitute 5 and 2.

  6. coreylvaughn
    • 2 years ago
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    The substitution takes place at the part where the expression is in square brackets. [ ]

  7. coreylvaughn
    • 2 years ago
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    You'll plug in 5 first and evaluate. Keep that answer on the side somewhere. Then you'll go back to the square brackets again, plug in 2 and evaluate. Whatever you get as the answer, you'll subtract that from the answer you got when you plugged in 5.

  8. hiralpatel121
    • 2 years ago
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    Can you wait while I do it, and tell me if it's correct?

  9. coreylvaughn
    • 2 years ago
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    Yes.

  10. hiralpatel121
    • 2 years ago
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    I got 77.5 when I plugged in 5.

  11. coreylvaughn
    • 2 years ago
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    I got -7.5

  12. coreylvaughn
    • 2 years ago
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    There's an extra negative sign next to the red negative sign. Ignore the extra one.

  13. coreylvaughn
    • 2 years ago
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    \[{-3(5)^{2}\over 2}+6(5)\]

  14. hiralpatel121
    • 2 years ago
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    Okay, so if I plug in 1, I'll get -3/2+8 = 6.5

  15. coreylvaughn
    • 2 years ago
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    No. 4.5.

  16. coreylvaughn
    • 2 years ago
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    Look at the equation I wrote above.

  17. coreylvaughn
    • 2 years ago
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    What do you get when you evaluate that expression?

  18. hiralpatel121
    • 2 years ago
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    Oh, I forgot to square it.

  19. hiralpatel121
    • 2 years ago
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    Then I get: (-7.5+4.5) - (-3/2 +8) = -9.5 or -19/2.

  20. coreylvaughn
    • 2 years ago
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    It's cool.

  21. hiralpatel121
    • 2 years ago
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    It's not correct though.

  22. coreylvaughn
    • 2 years ago
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    You're doing more than what it's asking for. The only values you're evaluating are 5 and 2. Not 6 and 1.

  23. coreylvaughn
    • 2 years ago
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    6 and 1 are solely used in the example.

  24. coreylvaughn
    • 2 years ago
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    You never answered my question. What do you get when you evaluate the expression I wrote above?

  25. hiralpatel121
    • 2 years ago
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    -7.5

  26. coreylvaughn
    • 2 years ago
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    Awesome. Now imagine the 5 is gone and a 2 is in its place in the expression above. What do you get now?

  27. coreylvaughn
    • 2 years ago
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    Replace BOTH 5s with 2s. Not just the one on the left.

  28. hiralpatel121
    • 2 years ago
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    6

  29. coreylvaughn
    • 2 years ago
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    Perfect. Now the last step is subtracting that 6 from -7.5: -7.5 - 6 =

  30. hiralpatel121
    • 2 years ago
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    -13.5

  31. coreylvaughn
    • 2 years ago
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    Awesome : )

  32. hiralpatel121
    • 2 years ago
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    But if you look at the sample problem, they subtracted another part too.

  33. coreylvaughn
    • 2 years ago
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    They subtracted the value of the expression when a 1 was plugged in. We subtracted the value of the expression when a 2 was plugged in.

  34. hiralpatel121
    • 2 years ago
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    I got -8 and it's still wrong.

  35. coreylvaughn
    • 2 years ago
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    -8 on which problem?

  36. coreylvaughn
    • 2 years ago
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    Ugh. It's + 8 not +6

  37. coreylvaughn
    • 2 years ago
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    \[{-3v ^{2} \over 2}+8v\]

  38. coreylvaughn
    • 2 years ago
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    Answer: -7.5 or -15/2

  39. hiralpatel121
    • 2 years ago
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    Okay

  40. coreylvaughn
    • 2 years ago
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    Sorry. I thought the expressions were the same in the example and actual problems.

  41. hiralpatel121
    • 2 years ago
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    It's okay. Can you help with another problem?

  42. hiralpatel121
    • 2 years ago
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    If you're not busy?

  43. coreylvaughn
    • 2 years ago
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    Sure.

  44. hiralpatel121
    • 2 years ago
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  45. hiralpatel121
    • 2 years ago
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    Sample:

  46. coreylvaughn
    • 2 years ago
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    4/3

  47. coreylvaughn
    • 2 years ago
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    Start off exactly as the example starts by dividing u and -4 by the square root of u. This gives you: \[\int\limits_{1}^{9}u ^{1/2}-4u ^{-1/2}\]

  48. coreylvaughn
    • 2 years ago
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    Then integrate each term.

  49. coreylvaughn
    • 2 years ago
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    \[[{2 \over 3}u ^{3/2}-8u ^{1/2}]\]

  50. coreylvaughn
    • 2 years ago
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    Plug in 9 first, and evaluate. Plug in 1 afterwards, then evaluate. Subtract the second answer from the first one.

  51. coreylvaughn
    • 2 years ago
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    Take care and don't forget to mark a Best Response. Thank you

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