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jimmy2016 Group Title

V=(1/3)pie r^2h solve for r

  • 2 years ago
  • 2 years ago

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  1. Romero Group Title
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    that means that we want r by itself. So everything on the right hand side must go away except the r

    • 2 years ago
  2. Romero Group Title
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    \[V=\frac{1}{3}\pi r^2h\] What do you want to get rid of first?

    • 2 years ago
  3. jimmy2016 Group Title
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    um 1/3

    • 2 years ago
  4. Romero Group Title
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    great that's division. Opposite of division is multiplication so we have to multiply both sides by 3\[3*V=3*\frac{1}{3}πr^2h\]\[3*V=πr^2h\]

    • 2 years ago
  5. Romero Group Title
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    now we must get rid of pi and h so we have to divide both sides by pi and h....what do you get then?

    • 2 years ago
  6. jimmy2016 Group Title
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    y by three

    • 2 years ago
  7. Romero Group Title
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    can you write it again?

    • 2 years ago
  8. jimmy2016 Group Title
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    |dw:1343255379829:dw|

    • 2 years ago
  9. Romero Group Title
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    \[\frac{3∗V}{\pi h }=\frac{πhr^2}{\pi h}\]

    • 2 years ago
  10. Romero Group Title
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    great now we need to square root both sides.

    • 2 years ago
  11. jimmy2016 Group Title
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    i dont know how

    • 2 years ago
  12. Romero Group Title
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    ok square root takes away the squared part in r^2 watch \[\frac{3V}{\pi h}=r^2\]\[\sqrt{\frac{3V}{\pi h}}= \sqrt{r^2}\]\[\sqrt{\frac{3V}{\pi h}}= r\]

    • 2 years ago
  13. Romero Group Title
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    but wait we square root both sides so we need the plus or minus\[\pm \sqrt{\frac{3V}{\pi h}} =r\]

    • 2 years ago
  14. jimmy2016 Group Title
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    huh

    • 2 years ago
  15. jimmy2016 Group Title
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    what does that mean

    • 2 years ago
  16. jimmy2016 Group Title
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    so whats the answer because i got confused

    • 2 years ago
  17. Romero Group Title
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    it's that. You have two answers one that is positive and one that is negative

    • 2 years ago
  18. Romero Group Title
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    that's what this sign means\[\pm \]

    • 2 years ago
  19. jimmy2016 Group Title
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    ohhhhhh okay wow thanks i didnt know that I am just going to high school so this is new

    • 2 years ago
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