jimmy2016
V=(1/3)pie r^2h solve for r



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Romero
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that means that we want r by itself. So everything on the right hand side must go away except the r

Romero
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\[V=\frac{1}{3}\pi r^2h\]
What do you want to get rid of first?

jimmy2016
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um 1/3

Romero
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great that's division. Opposite of division is multiplication so we have to multiply both sides by 3\[3*V=3*\frac{1}{3}πr^2h\]\[3*V=πr^2h\]

Romero
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now we must get rid of pi and h so we have to divide both sides by pi and h....what do you get then?

jimmy2016
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y by three

Romero
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can you write it again?

jimmy2016
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dw:1343255379829:dw

Romero
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\[\frac{3∗V}{\pi h }=\frac{πhr^2}{\pi h}\]

Romero
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great now we need to square root both sides.

jimmy2016
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i dont know how

Romero
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ok square root takes away the squared part in r^2 watch
\[\frac{3V}{\pi h}=r^2\]\[\sqrt{\frac{3V}{\pi h}}= \sqrt{r^2}\]\[\sqrt{\frac{3V}{\pi h}}= r\]

Romero
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but wait we square root both sides so we need the plus or minus\[\pm \sqrt{\frac{3V}{\pi h}} =r\]

jimmy2016
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huh

jimmy2016
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what does that mean

jimmy2016
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so whats the answer because i got confused

Romero
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it's that. You have two answers one that is positive and one that is negative

Romero
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that's what this sign means\[\pm \]

jimmy2016
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ohhhhhh okay wow thanks i didnt know that I am just going to high school so this is new