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jimmy2016
 2 years ago
V=(1/3)pie r^2h solve for r
jimmy2016
 2 years ago
V=(1/3)pie r^2h solve for r

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Romero
 2 years ago
Best ResponseYou've already chosen the best response.1that means that we want r by itself. So everything on the right hand side must go away except the r

Romero
 2 years ago
Best ResponseYou've already chosen the best response.1\[V=\frac{1}{3}\pi r^2h\] What do you want to get rid of first?

Romero
 2 years ago
Best ResponseYou've already chosen the best response.1great that's division. Opposite of division is multiplication so we have to multiply both sides by 3\[3*V=3*\frac{1}{3}πr^2h\]\[3*V=πr^2h\]

Romero
 2 years ago
Best ResponseYou've already chosen the best response.1now we must get rid of pi and h so we have to divide both sides by pi and h....what do you get then?

jimmy2016
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1343255379829:dw

Romero
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{3∗V}{\pi h }=\frac{πhr^2}{\pi h}\]

Romero
 2 years ago
Best ResponseYou've already chosen the best response.1great now we need to square root both sides.

Romero
 2 years ago
Best ResponseYou've already chosen the best response.1ok square root takes away the squared part in r^2 watch \[\frac{3V}{\pi h}=r^2\]\[\sqrt{\frac{3V}{\pi h}}= \sqrt{r^2}\]\[\sqrt{\frac{3V}{\pi h}}= r\]

Romero
 2 years ago
Best ResponseYou've already chosen the best response.1but wait we square root both sides so we need the plus or minus\[\pm \sqrt{\frac{3V}{\pi h}} =r\]

jimmy2016
 2 years ago
Best ResponseYou've already chosen the best response.0so whats the answer because i got confused

Romero
 2 years ago
Best ResponseYou've already chosen the best response.1it's that. You have two answers one that is positive and one that is negative

Romero
 2 years ago
Best ResponseYou've already chosen the best response.1that's what this sign means\[\pm \]

jimmy2016
 2 years ago
Best ResponseYou've already chosen the best response.0ohhhhhh okay wow thanks i didnt know that I am just going to high school so this is new
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