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RomeroBest ResponseYou've already chosen the best response.1
that means that we want r by itself. So everything on the right hand side must go away except the r
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
\[V=\frac{1}{3}\pi r^2h\] What do you want to get rid of first?
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
great that's division. Opposite of division is multiplication so we have to multiply both sides by 3\[3*V=3*\frac{1}{3}πr^2h\]\[3*V=πr^2h\]
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
now we must get rid of pi and h so we have to divide both sides by pi and h....what do you get then?
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
can you write it again?
 one year ago

jimmy2016Best ResponseYou've already chosen the best response.0
dw:1343255379829:dw
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
\[\frac{3∗V}{\pi h }=\frac{πhr^2}{\pi h}\]
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
great now we need to square root both sides.
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
ok square root takes away the squared part in r^2 watch \[\frac{3V}{\pi h}=r^2\]\[\sqrt{\frac{3V}{\pi h}}= \sqrt{r^2}\]\[\sqrt{\frac{3V}{\pi h}}= r\]
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
but wait we square root both sides so we need the plus or minus\[\pm \sqrt{\frac{3V}{\pi h}} =r\]
 one year ago

jimmy2016Best ResponseYou've already chosen the best response.0
so whats the answer because i got confused
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
it's that. You have two answers one that is positive and one that is negative
 one year ago

RomeroBest ResponseYou've already chosen the best response.1
that's what this sign means\[\pm \]
 one year ago

jimmy2016Best ResponseYou've already chosen the best response.0
ohhhhhh okay wow thanks i didnt know that I am just going to high school so this is new
 one year ago
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