Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

How can I solve the following? (attached)

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

Sample problem:
What step are you confused on the sample problem?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

I understand the sample problem. I just don't know how to use it for the actual problem.
do the same...instead of using 7 use 5
I did, but it shows up as wrong when I put it in.
then you did something wrong. me the steps
what is the final answer that you got when you did the problem?
Nevermind, I found my error, instead of 2/9 I put 2/5. Sorry. Can you help me with another problem though?
yes sure....remember to follow all the steps and make sure you don't make a mistake. One small mistake can make the answer wrong
What's the first step? Let's make the square root into an exponent \[\int\limits_{3}^{7}\frac{1}{\sqrt{6x+7}}dx\]\[\int\limits_{3}^{7}\frac{1}{(6x+7)^\frac{1}{2}}dx\]
then we bring the denominator to the top. But in order to do this we have to make the exponent a negative. Then we get \[\int\limits_{3}^{7}(6x+7)^{-\frac{1}{2}}dx\]
You just integrate what's inside first....can you tell me what you get?
No that's not it. Look back in the problem you did before and see how they integrated a square root after it became \[(-------)^\frac{1}{2}\]
you have to do the chain rule.
Try it one more time....what is the integral?
I have no idea here..
I thought you know how to integrate something that was a square root. Look at the example problem you did before and see what happens.
Would it be: 1/12 root of 6x+7?
Is the answer 1/4? If yes, then I've done my work correct.
I think you made a mistake \[\frac{1}{6} *\frac{1}{2}=\frac{1}{12}\] that's how you got the 12 right?
it's suppose to be\[\frac{1}{6}*2=\frac{2}{3}=\frac{1}{3}\]
1/3 root of 6x+7 not 1/12 root of 6x+7
Oh, so then the answer would be: 1.
what no I got something else
can you do the rest?
Yes, I got it.
what did you get?
Im doing the math right now.
ok tell me what you get just to check if you got it right.
yeah that's what I got good job.
If you have more problems post them in a different question.
I want to give you more medals :) for the good job

Not the answer you are looking for?

Search for more explanations.

Ask your own question