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take the integral from 0 to 90

ya take the integral!

I don't know how to do that.

hahaa

\[\int\limits_{0}^{\pi/2}x+ \cos(x)\]

ya this is the way!

then you have \[x ^{2}/2 + \sin(x) + c\]

now put the limits!

you dont need c

well ye u dont but i put it anyways just so it looks smart

got the answer?

I still don't realize what the next step will be after.

what? just put in the values!

I suck at trigs!

its easy want to learn it this is just the basics!

i feel like i did something wrong...

I have no idea..

no its wrong

oh i found my error now

divide it by 4

not 2

\[((\pi/2)^{2}/2) + 1\]

ya thats right!

So that's what I put down for the answer?

it reduces to \[(\pi ^{2}/4) + 1\]

Okay, thanks. I need help with just one more problem.