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hiralpatel121

  • 2 years ago

I need help with the problem attached.

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  1. hiralpatel121
    • 2 years ago
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  2. mandonut
    • 2 years ago
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    take the integral from 0 to 90

  3. rainaby
    • 2 years ago
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    ya take the integral!

  4. hiralpatel121
    • 2 years ago
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    I don't know how to do that.

  5. rainaby
    • 2 years ago
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    hahaa

  6. Goten77
    • 2 years ago
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    \[\int\limits_{0}^{\pi/2}x+ \cos(x)\]

  7. rainaby
    • 2 years ago
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    ya this is the way!

  8. Goten77
    • 2 years ago
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    then you have \[x ^{2}/2 + \sin(x) + c\]

  9. rainaby
    • 2 years ago
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    now put the limits!

  10. mandonut
    • 2 years ago
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    you dont need c

  11. Goten77
    • 2 years ago
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    well ye u dont but i put it anyways just so it looks smart

  12. rainaby
    • 2 years ago
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    got the answer?

  13. hiralpatel121
    • 2 years ago
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    I still don't realize what the next step will be after.

  14. rainaby
    • 2 years ago
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    what? just put in the values!

  15. hiralpatel121
    • 2 years ago
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    I suck at trigs!

  16. rainaby
    • 2 years ago
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    its easy want to learn it this is just the basics!

  17. Goten77
    • 2 years ago
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    i feel like i did something wrong...

  18. hiralpatel121
    • 2 years ago
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    I have no idea..

  19. rainaby
    • 2 years ago
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    no its wrong

  20. Goten77
    • 2 years ago
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    oh i found my error now

  21. rainaby
    • 2 years ago
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    divide it by 4

  22. rainaby
    • 2 years ago
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    not 2

  23. Goten77
    • 2 years ago
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    \[((\pi/2)^{2}/2) + 1\]

  24. rainaby
    • 2 years ago
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    ya thats right!

  25. hiralpatel121
    • 2 years ago
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    So that's what I put down for the answer?

  26. Goten77
    • 2 years ago
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    it reduces to \[(\pi ^{2}/4) + 1\]

  27. hiralpatel121
    • 2 years ago
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    Okay, thanks. I need help with just one more problem.

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