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hiralpatel121

I need help with the problem attached.

  • one year ago
  • one year ago

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  1. hiralpatel121
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    • one year ago
  2. mandonut
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    take the integral from 0 to 90

    • one year ago
  3. rainaby
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    ya take the integral!

    • one year ago
  4. hiralpatel121
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    I don't know how to do that.

    • one year ago
  5. rainaby
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    hahaa

    • one year ago
  6. Goten77
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    \[\int\limits_{0}^{\pi/2}x+ \cos(x)\]

    • one year ago
  7. rainaby
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    ya this is the way!

    • one year ago
  8. Goten77
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    then you have \[x ^{2}/2 + \sin(x) + c\]

    • one year ago
  9. rainaby
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    now put the limits!

    • one year ago
  10. mandonut
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    you dont need c

    • one year ago
  11. Goten77
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    well ye u dont but i put it anyways just so it looks smart

    • one year ago
  12. rainaby
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    got the answer?

    • one year ago
  13. hiralpatel121
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    I still don't realize what the next step will be after.

    • one year ago
  14. rainaby
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    what? just put in the values!

    • one year ago
  15. hiralpatel121
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    I suck at trigs!

    • one year ago
  16. rainaby
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    its easy want to learn it this is just the basics!

    • one year ago
  17. Goten77
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    i feel like i did something wrong...

    • one year ago
  18. hiralpatel121
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    I have no idea..

    • one year ago
  19. rainaby
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    no its wrong

    • one year ago
  20. Goten77
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    oh i found my error now

    • one year ago
  21. rainaby
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    divide it by 4

    • one year ago
  22. rainaby
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    not 2

    • one year ago
  23. Goten77
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    \[((\pi/2)^{2}/2) + 1\]

    • one year ago
  24. rainaby
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    ya thats right!

    • one year ago
  25. hiralpatel121
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    So that's what I put down for the answer?

    • one year ago
  26. Goten77
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    it reduces to \[(\pi ^{2}/4) + 1\]

    • one year ago
  27. hiralpatel121
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    Okay, thanks. I need help with just one more problem.

    • one year ago
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