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I need help with the problem attached.

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take the integral from 0 to 90
ya take the integral!

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Other answers:

I don't know how to do that.
\[\int\limits_{0}^{\pi/2}x+ \cos(x)\]
ya this is the way!
then you have \[x ^{2}/2 + \sin(x) + c\]
now put the limits!
you dont need c
well ye u dont but i put it anyways just so it looks smart
got the answer?
I still don't realize what the next step will be after.
what? just put in the values!
I suck at trigs!
its easy want to learn it this is just the basics!
i feel like i did something wrong...
I have no idea..
no its wrong
oh i found my error now
divide it by 4
not 2
\[((\pi/2)^{2}/2) + 1\]
ya thats right!
So that's what I put down for the answer?
it reduces to \[(\pi ^{2}/4) + 1\]
Okay, thanks. I need help with just one more problem.

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