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tanyahosler

i have a problems with my algebra homework

  • one year ago
  • one year ago

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  1. inkyvoyd
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    Okay, post it here :)

    • one year ago
  2. shruti
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    okay. now post your problem here.

    • one year ago
  3. zscdragon
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    take you time baby, relax ;)

    • one year ago
  4. Hero
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    It's Yao Ming!

    • one year ago
  5. tanyahosler
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    it is 4x to the 4th power - 7x to the 3rd power - 12x to the 4th power +6x to the 3rd power

    • one year ago
  6. inkyvoyd
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    \(4x^4-7x^3-12x^4+6x^3\)?

    • one year ago
  7. tanyahosler
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    yes

    • one year ago
  8. inkyvoyd
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    what you ned to do is combine like terms. Let me rewrite it a little for you \(4x^4-12x^4-7x^3+6x^3\)

    • one year ago
  9. inkyvoyd
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    @zscdragon , please read the code of conduct. http://openstudy.com/code-of-conduct We are here to help people, not give them the answers...

    • one year ago
  10. inkyvoyd
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    By the way, my post lagged, so somehow it came out after @zscdragon 's did. But, essentially, we did the same thing.

    • one year ago
  11. inkyvoyd
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    Actually because my internet is being slow. And I was serious about giving the answers. We are here to teach, not to cheat.

    • one year ago
  12. inkyvoyd
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    More importantly, @tanyahosler , do you understand?

    • one year ago
  13. inkyvoyd
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    I mean the problem xD

    • one year ago
  14. tanyahosler
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    what about helping me with this one -5a to the 2nd power; a=-2 can someone help me thru this one

    • one year ago
  15. tanyahosler
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    yeah i got it i understand how they got it

    • one year ago
  16. inkyvoyd
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    replace the a with a negative 2

    • one year ago
  17. inkyvoyd
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    Right now you have \(-5a^2\), put in a -2 (with parenthesis!) inside, and tell me what you get

    • one year ago
  18. tanyahosler
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    3

    • one year ago
  19. inkyvoyd
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    Did you read http://openstudy.com/code-of-conduct @zscdragon ? We are not supposed to nor allowed to just give answers like that.

    • one year ago
  20. tanyahosler
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    3 squared

    • one year ago
  21. inkyvoyd
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    @tanyahosler , how did you get that answer?

    • one year ago
  22. tanyahosler
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    subtracted it

    • one year ago
  23. tanyahosler
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    was i right

    • one year ago
  24. inkyvoyd
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    No :( Uh, let me show you what I meant

    • one year ago
  25. tanyahosler
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    ok

    • one year ago
  26. inkyvoyd
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    So, we have \(-5a^2\) instead of \(a\), we want (-2). So just put it in. \(-5*(-2)^2\) Exponents first Can you try to do the rest?

    • one year ago
  27. tanyahosler
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    so 10squared

    • one year ago
  28. inkyvoyd
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    No - square what's inside the parenthesis

    • one year ago
  29. tanyahosler
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    ok i'm lost

    • one year ago
  30. inkyvoyd
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    Exponents are before multiplcation and division, always!

    • one year ago
  31. tanyahosler
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    i'm lost

    • one year ago
  32. zscdragon
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    @tanyahosler look relax, everything's fine, just look at what I'll say

    • one year ago
  33. inkyvoyd
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    Here, should look like this \(-5*(\text{ }(-2)^2\text{ })\)

    • one year ago
  34. zscdragon
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    \[-5 * a^2\] is the equation, now what if you replace 'a' by -2

    • one year ago
  35. inkyvoyd
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    @zscdragon , Please do not curse on this site. I'm reporting you for foul language.

    • one year ago
  36. tanyahosler
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    i am still a lil confused

    • one year ago
  37. inkyvoyd
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    tanya, you want to "square" the a. The a is -2 in this case . What's negative 2 squared?

    • one year ago
  38. zscdragon
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    @tanyahosler , ok don't listen to that @inkyvoyd, he's all confused and doesn't know his material

    • one year ago
  39. tanyahosler
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    please guys i need help i have to have this in by saturday

    • one year ago
  40. inkyvoyd
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    @tanyahosler , It's okay. I'll help you by personal message, because zsc is being distracting. Why don't you tell me what you don't understand in a message :)

    • one year ago
  41. tanyahosler
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    ok

    • one year ago
  42. tanyahosler
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    it isn't a test it is homework and i don't know how to put the problems in here right

    • one year ago
  43. inkyvoyd
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    It's alright, I'll spend time to explain it. I have a few hours on hand, and I'm willing to use them :)

    • one year ago
  44. tanyahosler
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    ok i'm not sure how to do algebra anymore been 22 yrs since school

    • one year ago
  45. tanyahosler
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    the next one is going to be really difficult for me to put in cause i don't know how

    • one year ago
  46. inkyvoyd
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    Press the equation button. It should help.

    • one year ago
  47. inkyvoyd
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    Other wise you could try taking a screenshot, and uploading it.

    • one year ago
  48. tanyahosler
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    ok it is in my textbook

    • one year ago
  49. tanyahosler
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    but i wanna get this one done

    • one year ago
  50. inkyvoyd
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    Hm. Try using the equation button. Tell me if you have trouble.

    • one year ago
  51. tanyahosler
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    i don't know how to enter it in there

    • one year ago
  52. inkyvoyd
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    I see that you have gone from insulting language to stalking. I am slightly annoyed, but more so amused. I do request that if you want to publicly "embarrass" me, that you DO NOT POST HERE AND HIJACK SOMEONE'S THREAD. Please post it in chat. Thank you.

    • one year ago
  53. Mayah3
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    O_O!!!!!!!!!!!!!!!!!

    • one year ago
  54. inkyvoyd
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    I'm going to completely ignore you, not because I don't want to answer, but because this isn't your thread to hijack (nor is it mine). If you have a problem with me, let's fight it out in chat, instead of hijacking tanya's post.

    • one year ago
  55. tanyahosler
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    \[\sqrt{b ^{2-4ac;b=3,a=-1,c=-2}}\]

    • one year ago
  56. tanyahosler
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    not sure if i did that right

    • one year ago
  57. Mayah3
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    Can You Like Build A Bridge And Get Over It?

    • one year ago
  58. inkyvoyd
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    Oh, I know what you are trying to post. Is it \(\sqrt{b^2-4ac};b=3,a=-1,c=-2\)

    • one year ago
  59. Carniel
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    @Zscdragon Stop trolling or I will report you

    • one year ago
  60. inkyvoyd
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    @Mayah3 , My side's open, but I don't think his is. :(

    • one year ago
  61. zscdragon
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    @Carniel everything I said is based on reason, please re-read that a few times

    • one year ago
  62. tanyahosler
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    yes that is it inkyvoyd

    • one year ago
  63. inkyvoyd
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    Okay @tanyahosler . Put in what you are given for the letters. \(\sqrt{b^2-4ac}\) a=-1, b=-2, and c=3

    • one year ago
  64. inkyvoyd
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    @zscdragon , Please don't use this thread to insult me. Please insult me in chat. You are being incredibly rude and disruptive to the OP.

    • one year ago
  65. Carniel
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    Again your getting out of hand.

    • one year ago
  66. tanyahosler
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    b = 3, a=-1, c= -2

    • one year ago
  67. inkyvoyd
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    a=-1, b=-2, and c=3 Put (-1) for all the a's you see. Like this. \(\sqrt{b^2-4(-1)c}\) That make sense to you?

    • one year ago
  68. zscdragon
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    @inkyvoyd i never insulted you. all i write are facts and truths, nothing less, nothing more. u dont like it, dont read it ;)

    • one year ago
  69. tanyahosler
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    yes

    • one year ago
  70. inkyvoyd
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    Now, try the same for b.

    • one year ago
  71. inkyvoyd
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    \(\sqrt{b^2-4(-1)c}\) b=-2 here. Remember, just put the negative 2 in parenthesis, and square it. ignore the square root for now, and just type in what you get without the square root. Try using "Draw" if you have to.

    • one year ago
  72. tanyahosler
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    9

    • one year ago
  73. Mayah3
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    can he just shut up?

    • one year ago
  74. inkyvoyd
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    @zscdragon , I'd be happy to answer any of your comments if you post them in the appropriate math chat. What you are discussing does not pertain to what Tanya is trying to learn about, and thus is going to be ignored completely by me. Again, post it in chat, and I will answer. This is the last time I will reply to you on this thread because you are not being productive. Thank you.

    • one year ago
  75. Carniel
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    Your posting in a OQ he is trying to answer. Anything else out of you and I will report you

    • one year ago
  76. tanyahosler
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    |dw:1343280511266:dw|

    • one year ago
  77. inkyvoyd
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    Yes. But put the "a" and "b" in :)

    • one year ago
  78. inkyvoyd
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    |dw:1343280648000:dw|

    • one year ago
  79. Mayah3
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    Dude ! Shut Up Okay? Dang. No One Cares About Your Comments. You're Making A Fool Out Of Yourself -___-

    • one year ago
  80. tanyahosler
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    i'm just trying to get help so i understand and thats all dang

    • one year ago
  81. Carniel
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    Im done trying to negotiate im reporting

    • one year ago
  82. inkyvoyd
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    @tanyahosler , Mayah was not talking to you :)

    • one year ago
  83. tanyahosler
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    oh ok

    • one year ago
  84. tanyahosler
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    leave me out of your little battle here so he is helping me i don't care who went where as long as they are explaining it to me so i can get the help i need

    • one year ago
  85. Mayah3
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    Ohh You've Just Been Told

    • one year ago
  86. inkyvoyd
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    \(\sqrt{ (-2)^2-4(-1)(3)}\)

    • one year ago
  87. inkyvoyd
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    See? All I did was replace a, b, and c, with what they were as numbers :)

    • one year ago
  88. panlac01
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    the competition going on in helping is actually getting in the way of helping.

    • one year ago
  89. inkyvoyd
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    There actually is no competition, @panlac01 . zsc stopped helping her a long time ago. I switched to messaging her because he was harassing us too badly, and it was getting distracting. We are almost done with a third problem.

    • one year ago
  90. panlac01
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    is she looking for an answer? because Khan academy would be better off for her to get her quick lessons.

    • one year ago
  91. tanyahosler
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    no just help

    • one year ago
  92. panlac01
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    k

    • one year ago
  93. panlac01
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    do you go over your lectures and textbook?

    • one year ago
  94. inkyvoyd
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    @panlac01 , a lot of the original posts of zsc got deleted, so it might not make much sense. We are fine though, just finishing a problem.

    • one year ago
  95. tanyahosler
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    yes but i got confused

    • one year ago
  96. tanyahosler
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    ok i understand it a lil bit

    • one year ago
  97. inkyvoyd
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    \(\sqrt{ (-2)^2-4(-1)(3)}\) So, just evaluate straight through. Try it yourself once, tell me what you get...

    • one year ago
  98. panlac01
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    what level of algebra are you tackling? because the problems being posted are rather easy so long as your fundamentals are solid. practice 3-5 hours a day on top of your lessons. if you think you're lagging, seek the help of your professor. some textbooks are pretty helpful like Practical Algebra a self-teaching guide by Peter Selby et al.

    • one year ago
  99. tanyahosler
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    9

    • one year ago
  100. tanyahosler
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    intermediate algebra

    • one year ago
  101. panlac01
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    good luck. go over all your notes and examples provided by your professor and specially the textbook.

    • one year ago
  102. inkyvoyd
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    @panlac01 , can you help her out if she has anymore questions? I just finished the problem, but I must go to sleep now.

    • one year ago
  103. panlac01
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    she will be fine.

    • one year ago
  104. tanyahosler
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    i get confused on story problems and that is what my other 2 is would anyone like to help me on these

    • one year ago
  105. panlac01
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    check the textbook that I mention. it has a good lesson for you to tackle word problems in math. majority of the keywords are discussed in details

    • one year ago
  106. panlac01
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    it is less than 15 bucks in barnes and noble or even cheaper if you bought it online as used

    • one year ago
  107. tanyahosler
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    ok i understand that part but it is telling me to find the amount of aspirin to give a 10 yr old of and adult dosage of 325 milligrams it confuses me

    • one year ago
  108. tanyahosler
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    ok i will check that book out but i got to figure these out before saturday

    • one year ago
  109. panlac01
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    in pharmacology, the adult dosage is always 1.5 or twice the pediatric's

    • one year ago
  110. panlac01
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    that's the rule of thumb. but there are factors to consider, such as (BMI) or weight of the person, age, and gender

    • one year ago
  111. tanyahosler
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    so half of that then right

    • one year ago
  112. tanyahosler
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    it only says the age not the weight or the gender

    • one year ago
  113. tanyahosler
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    my question is Find the amount of aspirin to give a child of age 10 if the usual adult dosage is 325 milligrams

    • one year ago
  114. tanyahosler
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    so i'm confused

    • one year ago
  115. panlac01
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    try half that amount.

    • one year ago
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