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anonymous
 4 years ago
i have a problems with my algebra homework
anonymous
 4 years ago
i have a problems with my algebra homework

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay. now post your problem here.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0take you time baby, relax ;)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is 4x to the 4th power  7x to the 3rd power  12x to the 4th power +6x to the 3rd power

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3\(4x^47x^312x^4+6x^3\)?

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3what you ned to do is combine like terms. Let me rewrite it a little for you \(4x^412x^47x^3+6x^3\)

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3@zscdragon , please read the code of conduct. http://openstudy.com/codeofconduct We are here to help people, not give them the answers...

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3By the way, my post lagged, so somehow it came out after @zscdragon 's did. But, essentially, we did the same thing.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3Actually because my internet is being slow. And I was serious about giving the answers. We are here to teach, not to cheat.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3More importantly, @tanyahosler , do you understand?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what about helping me with this one 5a to the 2nd power; a=2 can someone help me thru this one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah i got it i understand how they got it

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3replace the a with a negative 2

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3Right now you have \(5a^2\), put in a 2 (with parenthesis!) inside, and tell me what you get

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3Did you read http://openstudy.com/codeofconduct @zscdragon ? We are not supposed to nor allowed to just give answers like that.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3@tanyahosler , how did you get that answer?

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3No :( Uh, let me show you what I meant

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3So, we have \(5a^2\) instead of \(a\), we want (2). So just put it in. \(5*(2)^2\) Exponents first Can you try to do the rest?

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3No  square what's inside the parenthesis

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3Exponents are before multiplcation and division, always!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@tanyahosler look relax, everything's fine, just look at what I'll say

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3Here, should look like this \(5*(\text{ }(2)^2\text{ })\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[5 * a^2\] is the equation, now what if you replace 'a' by 2

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3@zscdragon , Please do not curse on this site. I'm reporting you for foul language.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i am still a lil confused

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3tanya, you want to "square" the a. The a is 2 in this case . What's negative 2 squared?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@tanyahosler , ok don't listen to that @inkyvoyd, he's all confused and doesn't know his material

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0please guys i need help i have to have this in by saturday

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3@tanyahosler , It's okay. I'll help you by personal message, because zsc is being distracting. Why don't you tell me what you don't understand in a message :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it isn't a test it is homework and i don't know how to put the problems in here right

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3It's alright, I'll spend time to explain it. I have a few hours on hand, and I'm willing to use them :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok i'm not sure how to do algebra anymore been 22 yrs since school

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the next one is going to be really difficult for me to put in cause i don't know how

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3Press the equation button. It should help.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3Other wise you could try taking a screenshot, and uploading it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok it is in my textbook

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but i wanna get this one done

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3Hm. Try using the equation button. Tell me if you have trouble.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i don't know how to enter it in there

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3I see that you have gone from insulting language to stalking. I am slightly annoyed, but more so amused. I do request that if you want to publicly "embarrass" me, that you DO NOT POST HERE AND HIJACK SOMEONE'S THREAD. Please post it in chat. Thank you.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3I'm going to completely ignore you, not because I don't want to answer, but because this isn't your thread to hijack (nor is it mine). If you have a problem with me, let's fight it out in chat, instead of hijacking tanya's post.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{b ^{24ac;b=3,a=1,c=2}}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0not sure if i did that right

Mayah3
 4 years ago
Best ResponseYou've already chosen the best response.0Can You Like Build A Bridge And Get Over It?

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3Oh, I know what you are trying to post. Is it \(\sqrt{b^24ac};b=3,a=1,c=2\)

Carniel
 4 years ago
Best ResponseYou've already chosen the best response.0@Zscdragon Stop trolling or I will report you

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3@Mayah3 , My side's open, but I don't think his is. :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Carniel everything I said is based on reason, please reread that a few times

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes that is it inkyvoyd

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3Okay @tanyahosler . Put in what you are given for the letters. \(\sqrt{b^24ac}\) a=1, b=2, and c=3

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3@zscdragon , Please don't use this thread to insult me. Please insult me in chat. You are being incredibly rude and disruptive to the OP.

Carniel
 4 years ago
Best ResponseYou've already chosen the best response.0Again your getting out of hand.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3a=1, b=2, and c=3 Put (1) for all the a's you see. Like this. \(\sqrt{b^24(1)c}\) That make sense to you?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@inkyvoyd i never insulted you. all i write are facts and truths, nothing less, nothing more. u dont like it, dont read it ;)

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3Now, try the same for b.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3\(\sqrt{b^24(1)c}\) b=2 here. Remember, just put the negative 2 in parenthesis, and square it. ignore the square root for now, and just type in what you get without the square root. Try using "Draw" if you have to.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3@zscdragon , I'd be happy to answer any of your comments if you post them in the appropriate math chat. What you are discussing does not pertain to what Tanya is trying to learn about, and thus is going to be ignored completely by me. Again, post it in chat, and I will answer. This is the last time I will reply to you on this thread because you are not being productive. Thank you.

Carniel
 4 years ago
Best ResponseYou've already chosen the best response.0Your posting in a OQ he is trying to answer. Anything else out of you and I will report you

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1343280511266:dw

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3Yes. But put the "a" and "b" in :)

Mayah3
 4 years ago
Best ResponseYou've already chosen the best response.0Dude ! Shut Up Okay? Dang. No One Cares About Your Comments. You're Making A Fool Out Of Yourself ___

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i'm just trying to get help so i understand and thats all dang

Carniel
 4 years ago
Best ResponseYou've already chosen the best response.0Im done trying to negotiate im reporting

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3@tanyahosler , Mayah was not talking to you :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0leave me out of your little battle here so he is helping me i don't care who went where as long as they are explaining it to me so i can get the help i need

Mayah3
 4 years ago
Best ResponseYou've already chosen the best response.0Ohh You've Just Been Told

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3\(\sqrt{ (2)^24(1)(3)}\)

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3See? All I did was replace a, b, and c, with what they were as numbers :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the competition going on in helping is actually getting in the way of helping.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3There actually is no competition, @panlac01 . zsc stopped helping her a long time ago. I switched to messaging her because he was harassing us too badly, and it was getting distracting. We are almost done with a third problem.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is she looking for an answer? because Khan academy would be better off for her to get her quick lessons.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do you go over your lectures and textbook?

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3@panlac01 , a lot of the original posts of zsc got deleted, so it might not make much sense. We are fine though, just finishing a problem.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes but i got confused

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok i understand it a lil bit

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3\(\sqrt{ (2)^24(1)(3)}\) So, just evaluate straight through. Try it yourself once, tell me what you get...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what level of algebra are you tackling? because the problems being posted are rather easy so long as your fundamentals are solid. practice 35 hours a day on top of your lessons. if you think you're lagging, seek the help of your professor. some textbooks are pretty helpful like Practical Algebra a selfteaching guide by Peter Selby et al.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0good luck. go over all your notes and examples provided by your professor and specially the textbook.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.3@panlac01 , can you help her out if she has anymore questions? I just finished the problem, but I must go to sleep now.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i get confused on story problems and that is what my other 2 is would anyone like to help me on these

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0check the textbook that I mention. it has a good lesson for you to tackle word problems in math. majority of the keywords are discussed in details

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is less than 15 bucks in barnes and noble or even cheaper if you bought it online as used

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok i understand that part but it is telling me to find the amount of aspirin to give a 10 yr old of and adult dosage of 325 milligrams it confuses me

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok i will check that book out but i got to figure these out before saturday

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in pharmacology, the adult dosage is always 1.5 or twice the pediatric's

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that's the rule of thumb. but there are factors to consider, such as (BMI) or weight of the person, age, and gender

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so half of that then right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it only says the age not the weight or the gender

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0my question is Find the amount of aspirin to give a child of age 10 if the usual adult dosage is 325 milligrams

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0try half that amount.
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