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inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
Okay, post it here :)
 2 years ago

shruti Group TitleBest ResponseYou've already chosen the best response.0
okay. now post your problem here.
 2 years ago

zscdragon Group TitleBest ResponseYou've already chosen the best response.0
take you time baby, relax ;)
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
It's Yao Ming!
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
it is 4x to the 4th power  7x to the 3rd power  12x to the 4th power +6x to the 3rd power
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
\(4x^47x^312x^4+6x^3\)?
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
what you ned to do is combine like terms. Let me rewrite it a little for you \(4x^412x^47x^3+6x^3\)
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
@zscdragon , please read the code of conduct. http://openstudy.com/codeofconduct We are here to help people, not give them the answers...
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
By the way, my post lagged, so somehow it came out after @zscdragon 's did. But, essentially, we did the same thing.
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
Actually because my internet is being slow. And I was serious about giving the answers. We are here to teach, not to cheat.
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
More importantly, @tanyahosler , do you understand?
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
I mean the problem xD
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
what about helping me with this one 5a to the 2nd power; a=2 can someone help me thru this one
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
yeah i got it i understand how they got it
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
replace the a with a negative 2
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
Right now you have \(5a^2\), put in a 2 (with parenthesis!) inside, and tell me what you get
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
Did you read http://openstudy.com/codeofconduct @zscdragon ? We are not supposed to nor allowed to just give answers like that.
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
3 squared
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
@tanyahosler , how did you get that answer?
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
subtracted it
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
was i right
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
No :( Uh, let me show you what I meant
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
So, we have \(5a^2\) instead of \(a\), we want (2). So just put it in. \(5*(2)^2\) Exponents first Can you try to do the rest?
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
so 10squared
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
No  square what's inside the parenthesis
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
ok i'm lost
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
Exponents are before multiplcation and division, always!
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
i'm lost
 2 years ago

zscdragon Group TitleBest ResponseYou've already chosen the best response.0
@tanyahosler look relax, everything's fine, just look at what I'll say
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
Here, should look like this \(5*(\text{ }(2)^2\text{ })\)
 2 years ago

zscdragon Group TitleBest ResponseYou've already chosen the best response.0
\[5 * a^2\] is the equation, now what if you replace 'a' by 2
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
@zscdragon , Please do not curse on this site. I'm reporting you for foul language.
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
i am still a lil confused
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
tanya, you want to "square" the a. The a is 2 in this case . What's negative 2 squared?
 2 years ago

zscdragon Group TitleBest ResponseYou've already chosen the best response.0
@tanyahosler , ok don't listen to that @inkyvoyd, he's all confused and doesn't know his material
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
please guys i need help i have to have this in by saturday
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
@tanyahosler , It's okay. I'll help you by personal message, because zsc is being distracting. Why don't you tell me what you don't understand in a message :)
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
it isn't a test it is homework and i don't know how to put the problems in here right
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
It's alright, I'll spend time to explain it. I have a few hours on hand, and I'm willing to use them :)
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
ok i'm not sure how to do algebra anymore been 22 yrs since school
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
the next one is going to be really difficult for me to put in cause i don't know how
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
Press the equation button. It should help.
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
Other wise you could try taking a screenshot, and uploading it.
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
ok it is in my textbook
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
but i wanna get this one done
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
Hm. Try using the equation button. Tell me if you have trouble.
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
i don't know how to enter it in there
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
I see that you have gone from insulting language to stalking. I am slightly annoyed, but more so amused. I do request that if you want to publicly "embarrass" me, that you DO NOT POST HERE AND HIJACK SOMEONE'S THREAD. Please post it in chat. Thank you.
 2 years ago

Mayah3 Group TitleBest ResponseYou've already chosen the best response.0
O_O!!!!!!!!!!!!!!!!!
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
I'm going to completely ignore you, not because I don't want to answer, but because this isn't your thread to hijack (nor is it mine). If you have a problem with me, let's fight it out in chat, instead of hijacking tanya's post.
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{b ^{24ac;b=3,a=1,c=2}}\]
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
not sure if i did that right
 2 years ago

Mayah3 Group TitleBest ResponseYou've already chosen the best response.0
Can You Like Build A Bridge And Get Over It?
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
Oh, I know what you are trying to post. Is it \(\sqrt{b^24ac};b=3,a=1,c=2\)
 2 years ago

Carniel Group TitleBest ResponseYou've already chosen the best response.0
@Zscdragon Stop trolling or I will report you
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
@Mayah3 , My side's open, but I don't think his is. :(
 2 years ago

zscdragon Group TitleBest ResponseYou've already chosen the best response.0
@Carniel everything I said is based on reason, please reread that a few times
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
yes that is it inkyvoyd
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
Okay @tanyahosler . Put in what you are given for the letters. \(\sqrt{b^24ac}\) a=1, b=2, and c=3
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
@zscdragon , Please don't use this thread to insult me. Please insult me in chat. You are being incredibly rude and disruptive to the OP.
 2 years ago

Carniel Group TitleBest ResponseYou've already chosen the best response.0
Again your getting out of hand.
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
b = 3, a=1, c= 2
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
a=1, b=2, and c=3 Put (1) for all the a's you see. Like this. \(\sqrt{b^24(1)c}\) That make sense to you?
 2 years ago

zscdragon Group TitleBest ResponseYou've already chosen the best response.0
@inkyvoyd i never insulted you. all i write are facts and truths, nothing less, nothing more. u dont like it, dont read it ;)
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
Now, try the same for b.
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
\(\sqrt{b^24(1)c}\) b=2 here. Remember, just put the negative 2 in parenthesis, and square it. ignore the square root for now, and just type in what you get without the square root. Try using "Draw" if you have to.
 2 years ago

Mayah3 Group TitleBest ResponseYou've already chosen the best response.0
can he just shut up?
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
@zscdragon , I'd be happy to answer any of your comments if you post them in the appropriate math chat. What you are discussing does not pertain to what Tanya is trying to learn about, and thus is going to be ignored completely by me. Again, post it in chat, and I will answer. This is the last time I will reply to you on this thread because you are not being productive. Thank you.
 2 years ago

Carniel Group TitleBest ResponseYou've already chosen the best response.0
Your posting in a OQ he is trying to answer. Anything else out of you and I will report you
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
dw:1343280511266:dw
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
Yes. But put the "a" and "b" in :)
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
dw:1343280648000:dw
 2 years ago

Mayah3 Group TitleBest ResponseYou've already chosen the best response.0
Dude ! Shut Up Okay? Dang. No One Cares About Your Comments. You're Making A Fool Out Of Yourself ___
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
i'm just trying to get help so i understand and thats all dang
 2 years ago

Carniel Group TitleBest ResponseYou've already chosen the best response.0
Im done trying to negotiate im reporting
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
@tanyahosler , Mayah was not talking to you :)
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
leave me out of your little battle here so he is helping me i don't care who went where as long as they are explaining it to me so i can get the help i need
 2 years ago

Mayah3 Group TitleBest ResponseYou've already chosen the best response.0
Ohh You've Just Been Told
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
\(\sqrt{ (2)^24(1)(3)}\)
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
See? All I did was replace a, b, and c, with what they were as numbers :)
 2 years ago

panlac01 Group TitleBest ResponseYou've already chosen the best response.1
the competition going on in helping is actually getting in the way of helping.
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
There actually is no competition, @panlac01 . zsc stopped helping her a long time ago. I switched to messaging her because he was harassing us too badly, and it was getting distracting. We are almost done with a third problem.
 2 years ago

panlac01 Group TitleBest ResponseYou've already chosen the best response.1
is she looking for an answer? because Khan academy would be better off for her to get her quick lessons.
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
no just help
 2 years ago

panlac01 Group TitleBest ResponseYou've already chosen the best response.1
do you go over your lectures and textbook?
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
@panlac01 , a lot of the original posts of zsc got deleted, so it might not make much sense. We are fine though, just finishing a problem.
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
yes but i got confused
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
ok i understand it a lil bit
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
\(\sqrt{ (2)^24(1)(3)}\) So, just evaluate straight through. Try it yourself once, tell me what you get...
 2 years ago

panlac01 Group TitleBest ResponseYou've already chosen the best response.1
what level of algebra are you tackling? because the problems being posted are rather easy so long as your fundamentals are solid. practice 35 hours a day on top of your lessons. if you think you're lagging, seek the help of your professor. some textbooks are pretty helpful like Practical Algebra a selfteaching guide by Peter Selby et al.
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
intermediate algebra
 2 years ago

panlac01 Group TitleBest ResponseYou've already chosen the best response.1
good luck. go over all your notes and examples provided by your professor and specially the textbook.
 2 years ago

inkyvoyd Group TitleBest ResponseYou've already chosen the best response.3
@panlac01 , can you help her out if she has anymore questions? I just finished the problem, but I must go to sleep now.
 2 years ago

panlac01 Group TitleBest ResponseYou've already chosen the best response.1
she will be fine.
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
i get confused on story problems and that is what my other 2 is would anyone like to help me on these
 2 years ago

panlac01 Group TitleBest ResponseYou've already chosen the best response.1
check the textbook that I mention. it has a good lesson for you to tackle word problems in math. majority of the keywords are discussed in details
 2 years ago

panlac01 Group TitleBest ResponseYou've already chosen the best response.1
it is less than 15 bucks in barnes and noble or even cheaper if you bought it online as used
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
ok i understand that part but it is telling me to find the amount of aspirin to give a 10 yr old of and adult dosage of 325 milligrams it confuses me
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
ok i will check that book out but i got to figure these out before saturday
 2 years ago

panlac01 Group TitleBest ResponseYou've already chosen the best response.1
in pharmacology, the adult dosage is always 1.5 or twice the pediatric's
 2 years ago

panlac01 Group TitleBest ResponseYou've already chosen the best response.1
that's the rule of thumb. but there are factors to consider, such as (BMI) or weight of the person, age, and gender
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
so half of that then right
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
it only says the age not the weight or the gender
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
my question is Find the amount of aspirin to give a child of age 10 if the usual adult dosage is 325 milligrams
 2 years ago

tanyahosler Group TitleBest ResponseYou've already chosen the best response.0
so i'm confused
 2 years ago

panlac01 Group TitleBest ResponseYou've already chosen the best response.1
try half that amount.
 2 years ago
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