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tanyahosler Group Title

i have a problems with my algebra homework

  • 2 years ago
  • 2 years ago

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  1. inkyvoyd Group Title
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    Okay, post it here :)

    • 2 years ago
  2. shruti Group Title
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    okay. now post your problem here.

    • 2 years ago
  3. zscdragon Group Title
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    take you time baby, relax ;)

    • 2 years ago
  4. Hero Group Title
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    It's Yao Ming!

    • 2 years ago
  5. tanyahosler Group Title
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    it is 4x to the 4th power - 7x to the 3rd power - 12x to the 4th power +6x to the 3rd power

    • 2 years ago
  6. inkyvoyd Group Title
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    \(4x^4-7x^3-12x^4+6x^3\)?

    • 2 years ago
  7. tanyahosler Group Title
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    yes

    • 2 years ago
  8. inkyvoyd Group Title
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    what you ned to do is combine like terms. Let me rewrite it a little for you \(4x^4-12x^4-7x^3+6x^3\)

    • 2 years ago
  9. inkyvoyd Group Title
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    @zscdragon , please read the code of conduct. http://openstudy.com/code-of-conduct We are here to help people, not give them the answers...

    • 2 years ago
  10. inkyvoyd Group Title
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    By the way, my post lagged, so somehow it came out after @zscdragon 's did. But, essentially, we did the same thing.

    • 2 years ago
  11. inkyvoyd Group Title
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    Actually because my internet is being slow. And I was serious about giving the answers. We are here to teach, not to cheat.

    • 2 years ago
  12. inkyvoyd Group Title
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    More importantly, @tanyahosler , do you understand?

    • 2 years ago
  13. inkyvoyd Group Title
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    I mean the problem xD

    • 2 years ago
  14. tanyahosler Group Title
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    what about helping me with this one -5a to the 2nd power; a=-2 can someone help me thru this one

    • 2 years ago
  15. tanyahosler Group Title
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    yeah i got it i understand how they got it

    • 2 years ago
  16. inkyvoyd Group Title
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    replace the a with a negative 2

    • 2 years ago
  17. inkyvoyd Group Title
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    Right now you have \(-5a^2\), put in a -2 (with parenthesis!) inside, and tell me what you get

    • 2 years ago
  18. tanyahosler Group Title
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    3

    • 2 years ago
  19. inkyvoyd Group Title
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    Did you read http://openstudy.com/code-of-conduct @zscdragon ? We are not supposed to nor allowed to just give answers like that.

    • 2 years ago
  20. tanyahosler Group Title
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    3 squared

    • 2 years ago
  21. inkyvoyd Group Title
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    @tanyahosler , how did you get that answer?

    • 2 years ago
  22. tanyahosler Group Title
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    subtracted it

    • 2 years ago
  23. tanyahosler Group Title
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    was i right

    • 2 years ago
  24. inkyvoyd Group Title
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    No :( Uh, let me show you what I meant

    • 2 years ago
  25. tanyahosler Group Title
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    ok

    • 2 years ago
  26. inkyvoyd Group Title
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    So, we have \(-5a^2\) instead of \(a\), we want (-2). So just put it in. \(-5*(-2)^2\) Exponents first Can you try to do the rest?

    • 2 years ago
  27. tanyahosler Group Title
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    so 10squared

    • 2 years ago
  28. inkyvoyd Group Title
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    No - square what's inside the parenthesis

    • 2 years ago
  29. tanyahosler Group Title
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    ok i'm lost

    • 2 years ago
  30. inkyvoyd Group Title
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    Exponents are before multiplcation and division, always!

    • 2 years ago
  31. tanyahosler Group Title
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    i'm lost

    • 2 years ago
  32. zscdragon Group Title
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    @tanyahosler look relax, everything's fine, just look at what I'll say

    • 2 years ago
  33. inkyvoyd Group Title
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    Here, should look like this \(-5*(\text{ }(-2)^2\text{ })\)

    • 2 years ago
  34. zscdragon Group Title
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    \[-5 * a^2\] is the equation, now what if you replace 'a' by -2

    • 2 years ago
  35. inkyvoyd Group Title
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    @zscdragon , Please do not curse on this site. I'm reporting you for foul language.

    • 2 years ago
  36. tanyahosler Group Title
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    i am still a lil confused

    • 2 years ago
  37. inkyvoyd Group Title
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    tanya, you want to "square" the a. The a is -2 in this case . What's negative 2 squared?

    • 2 years ago
  38. zscdragon Group Title
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    @tanyahosler , ok don't listen to that @inkyvoyd, he's all confused and doesn't know his material

    • 2 years ago
  39. tanyahosler Group Title
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    please guys i need help i have to have this in by saturday

    • 2 years ago
  40. inkyvoyd Group Title
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    @tanyahosler , It's okay. I'll help you by personal message, because zsc is being distracting. Why don't you tell me what you don't understand in a message :)

    • 2 years ago
  41. tanyahosler Group Title
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    ok

    • 2 years ago
  42. tanyahosler Group Title
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    it isn't a test it is homework and i don't know how to put the problems in here right

    • 2 years ago
  43. inkyvoyd Group Title
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    It's alright, I'll spend time to explain it. I have a few hours on hand, and I'm willing to use them :)

    • 2 years ago
  44. tanyahosler Group Title
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    ok i'm not sure how to do algebra anymore been 22 yrs since school

    • 2 years ago
  45. tanyahosler Group Title
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    the next one is going to be really difficult for me to put in cause i don't know how

    • 2 years ago
  46. inkyvoyd Group Title
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    Press the equation button. It should help.

    • 2 years ago
  47. inkyvoyd Group Title
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    Other wise you could try taking a screenshot, and uploading it.

    • 2 years ago
  48. tanyahosler Group Title
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    ok it is in my textbook

    • 2 years ago
  49. tanyahosler Group Title
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    but i wanna get this one done

    • 2 years ago
  50. inkyvoyd Group Title
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    Hm. Try using the equation button. Tell me if you have trouble.

    • 2 years ago
  51. tanyahosler Group Title
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    i don't know how to enter it in there

    • 2 years ago
  52. inkyvoyd Group Title
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    I see that you have gone from insulting language to stalking. I am slightly annoyed, but more so amused. I do request that if you want to publicly "embarrass" me, that you DO NOT POST HERE AND HIJACK SOMEONE'S THREAD. Please post it in chat. Thank you.

    • 2 years ago
  53. Mayah3 Group Title
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    O_O!!!!!!!!!!!!!!!!!

    • 2 years ago
  54. inkyvoyd Group Title
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    I'm going to completely ignore you, not because I don't want to answer, but because this isn't your thread to hijack (nor is it mine). If you have a problem with me, let's fight it out in chat, instead of hijacking tanya's post.

    • 2 years ago
  55. tanyahosler Group Title
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    \[\sqrt{b ^{2-4ac;b=3,a=-1,c=-2}}\]

    • 2 years ago
  56. tanyahosler Group Title
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    not sure if i did that right

    • 2 years ago
  57. Mayah3 Group Title
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    Can You Like Build A Bridge And Get Over It?

    • 2 years ago
  58. inkyvoyd Group Title
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    Oh, I know what you are trying to post. Is it \(\sqrt{b^2-4ac};b=3,a=-1,c=-2\)

    • 2 years ago
  59. Carniel Group Title
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    @Zscdragon Stop trolling or I will report you

    • 2 years ago
  60. inkyvoyd Group Title
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    @Mayah3 , My side's open, but I don't think his is. :(

    • 2 years ago
  61. zscdragon Group Title
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    @Carniel everything I said is based on reason, please re-read that a few times

    • 2 years ago
  62. tanyahosler Group Title
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    yes that is it inkyvoyd

    • 2 years ago
  63. inkyvoyd Group Title
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    Okay @tanyahosler . Put in what you are given for the letters. \(\sqrt{b^2-4ac}\) a=-1, b=-2, and c=3

    • 2 years ago
  64. inkyvoyd Group Title
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    @zscdragon , Please don't use this thread to insult me. Please insult me in chat. You are being incredibly rude and disruptive to the OP.

    • 2 years ago
  65. Carniel Group Title
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    Again your getting out of hand.

    • 2 years ago
  66. tanyahosler Group Title
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    b = 3, a=-1, c= -2

    • 2 years ago
  67. inkyvoyd Group Title
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    a=-1, b=-2, and c=3 Put (-1) for all the a's you see. Like this. \(\sqrt{b^2-4(-1)c}\) That make sense to you?

    • 2 years ago
  68. zscdragon Group Title
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    @inkyvoyd i never insulted you. all i write are facts and truths, nothing less, nothing more. u dont like it, dont read it ;)

    • 2 years ago
  69. tanyahosler Group Title
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    yes

    • 2 years ago
  70. inkyvoyd Group Title
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    Now, try the same for b.

    • 2 years ago
  71. inkyvoyd Group Title
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    \(\sqrt{b^2-4(-1)c}\) b=-2 here. Remember, just put the negative 2 in parenthesis, and square it. ignore the square root for now, and just type in what you get without the square root. Try using "Draw" if you have to.

    • 2 years ago
  72. tanyahosler Group Title
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    9

    • 2 years ago
  73. Mayah3 Group Title
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    can he just shut up?

    • 2 years ago
  74. inkyvoyd Group Title
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    @zscdragon , I'd be happy to answer any of your comments if you post them in the appropriate math chat. What you are discussing does not pertain to what Tanya is trying to learn about, and thus is going to be ignored completely by me. Again, post it in chat, and I will answer. This is the last time I will reply to you on this thread because you are not being productive. Thank you.

    • 2 years ago
  75. Carniel Group Title
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    Your posting in a OQ he is trying to answer. Anything else out of you and I will report you

    • 2 years ago
  76. tanyahosler Group Title
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    |dw:1343280511266:dw|

    • 2 years ago
  77. inkyvoyd Group Title
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    Yes. But put the "a" and "b" in :)

    • 2 years ago
  78. inkyvoyd Group Title
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    |dw:1343280648000:dw|

    • 2 years ago
  79. Mayah3 Group Title
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    Dude ! Shut Up Okay? Dang. No One Cares About Your Comments. You're Making A Fool Out Of Yourself -___-

    • 2 years ago
  80. tanyahosler Group Title
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    i'm just trying to get help so i understand and thats all dang

    • 2 years ago
  81. Carniel Group Title
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    Im done trying to negotiate im reporting

    • 2 years ago
  82. inkyvoyd Group Title
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    @tanyahosler , Mayah was not talking to you :)

    • 2 years ago
  83. tanyahosler Group Title
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    oh ok

    • 2 years ago
  84. tanyahosler Group Title
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    leave me out of your little battle here so he is helping me i don't care who went where as long as they are explaining it to me so i can get the help i need

    • 2 years ago
  85. Mayah3 Group Title
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    Ohh You've Just Been Told

    • 2 years ago
  86. inkyvoyd Group Title
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    \(\sqrt{ (-2)^2-4(-1)(3)}\)

    • 2 years ago
  87. inkyvoyd Group Title
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    See? All I did was replace a, b, and c, with what they were as numbers :)

    • 2 years ago
  88. panlac01 Group Title
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    the competition going on in helping is actually getting in the way of helping.

    • 2 years ago
  89. inkyvoyd Group Title
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    There actually is no competition, @panlac01 . zsc stopped helping her a long time ago. I switched to messaging her because he was harassing us too badly, and it was getting distracting. We are almost done with a third problem.

    • 2 years ago
  90. panlac01 Group Title
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    is she looking for an answer? because Khan academy would be better off for her to get her quick lessons.

    • 2 years ago
  91. tanyahosler Group Title
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    no just help

    • 2 years ago
  92. panlac01 Group Title
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    k

    • 2 years ago
  93. panlac01 Group Title
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    do you go over your lectures and textbook?

    • 2 years ago
  94. inkyvoyd Group Title
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    @panlac01 , a lot of the original posts of zsc got deleted, so it might not make much sense. We are fine though, just finishing a problem.

    • 2 years ago
  95. tanyahosler Group Title
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    yes but i got confused

    • 2 years ago
  96. tanyahosler Group Title
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    ok i understand it a lil bit

    • 2 years ago
  97. inkyvoyd Group Title
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    \(\sqrt{ (-2)^2-4(-1)(3)}\) So, just evaluate straight through. Try it yourself once, tell me what you get...

    • 2 years ago
  98. panlac01 Group Title
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    what level of algebra are you tackling? because the problems being posted are rather easy so long as your fundamentals are solid. practice 3-5 hours a day on top of your lessons. if you think you're lagging, seek the help of your professor. some textbooks are pretty helpful like Practical Algebra a self-teaching guide by Peter Selby et al.

    • 2 years ago
  99. tanyahosler Group Title
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    9

    • 2 years ago
  100. tanyahosler Group Title
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    intermediate algebra

    • 2 years ago
  101. panlac01 Group Title
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    good luck. go over all your notes and examples provided by your professor and specially the textbook.

    • 2 years ago
  102. inkyvoyd Group Title
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    @panlac01 , can you help her out if she has anymore questions? I just finished the problem, but I must go to sleep now.

    • 2 years ago
  103. panlac01 Group Title
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    she will be fine.

    • 2 years ago
  104. tanyahosler Group Title
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    i get confused on story problems and that is what my other 2 is would anyone like to help me on these

    • 2 years ago
  105. panlac01 Group Title
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    check the textbook that I mention. it has a good lesson for you to tackle word problems in math. majority of the keywords are discussed in details

    • 2 years ago
  106. panlac01 Group Title
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    it is less than 15 bucks in barnes and noble or even cheaper if you bought it online as used

    • 2 years ago
  107. tanyahosler Group Title
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    ok i understand that part but it is telling me to find the amount of aspirin to give a 10 yr old of and adult dosage of 325 milligrams it confuses me

    • 2 years ago
  108. tanyahosler Group Title
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    ok i will check that book out but i got to figure these out before saturday

    • 2 years ago
  109. panlac01 Group Title
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    in pharmacology, the adult dosage is always 1.5 or twice the pediatric's

    • 2 years ago
  110. panlac01 Group Title
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    that's the rule of thumb. but there are factors to consider, such as (BMI) or weight of the person, age, and gender

    • 2 years ago
  111. tanyahosler Group Title
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    so half of that then right

    • 2 years ago
  112. tanyahosler Group Title
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    it only says the age not the weight or the gender

    • 2 years ago
  113. tanyahosler Group Title
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    my question is Find the amount of aspirin to give a child of age 10 if the usual adult dosage is 325 milligrams

    • 2 years ago
  114. tanyahosler Group Title
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    so i'm confused

    • 2 years ago
  115. panlac01 Group Title
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    try half that amount.

    • 2 years ago
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