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tanyahosler

  • 2 years ago

i have a problems with my algebra homework

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  1. inkyvoyd
    • 2 years ago
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    Okay, post it here :)

  2. shruti
    • 2 years ago
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    okay. now post your problem here.

  3. zscdragon
    • 2 years ago
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    take you time baby, relax ;)

  4. Hero
    • 2 years ago
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    It's Yao Ming!

  5. tanyahosler
    • 2 years ago
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    it is 4x to the 4th power - 7x to the 3rd power - 12x to the 4th power +6x to the 3rd power

  6. inkyvoyd
    • 2 years ago
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    \(4x^4-7x^3-12x^4+6x^3\)?

  7. tanyahosler
    • 2 years ago
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    yes

  8. inkyvoyd
    • 2 years ago
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    what you ned to do is combine like terms. Let me rewrite it a little for you \(4x^4-12x^4-7x^3+6x^3\)

  9. inkyvoyd
    • 2 years ago
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    @zscdragon , please read the code of conduct. http://openstudy.com/code-of-conduct We are here to help people, not give them the answers...

  10. inkyvoyd
    • 2 years ago
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    By the way, my post lagged, so somehow it came out after @zscdragon 's did. But, essentially, we did the same thing.

  11. inkyvoyd
    • 2 years ago
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    Actually because my internet is being slow. And I was serious about giving the answers. We are here to teach, not to cheat.

  12. inkyvoyd
    • 2 years ago
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    More importantly, @tanyahosler , do you understand?

  13. inkyvoyd
    • 2 years ago
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    I mean the problem xD

  14. tanyahosler
    • 2 years ago
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    what about helping me with this one -5a to the 2nd power; a=-2 can someone help me thru this one

  15. tanyahosler
    • 2 years ago
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    yeah i got it i understand how they got it

  16. inkyvoyd
    • 2 years ago
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    replace the a with a negative 2

  17. inkyvoyd
    • 2 years ago
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    Right now you have \(-5a^2\), put in a -2 (with parenthesis!) inside, and tell me what you get

  18. tanyahosler
    • 2 years ago
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    3

  19. inkyvoyd
    • 2 years ago
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    Did you read http://openstudy.com/code-of-conduct @zscdragon ? We are not supposed to nor allowed to just give answers like that.

  20. tanyahosler
    • 2 years ago
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    3 squared

  21. inkyvoyd
    • 2 years ago
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    @tanyahosler , how did you get that answer?

  22. tanyahosler
    • 2 years ago
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    subtracted it

  23. tanyahosler
    • 2 years ago
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    was i right

  24. inkyvoyd
    • 2 years ago
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    No :( Uh, let me show you what I meant

  25. tanyahosler
    • 2 years ago
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    ok

  26. inkyvoyd
    • 2 years ago
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    So, we have \(-5a^2\) instead of \(a\), we want (-2). So just put it in. \(-5*(-2)^2\) Exponents first Can you try to do the rest?

  27. tanyahosler
    • 2 years ago
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    so 10squared

  28. inkyvoyd
    • 2 years ago
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    No - square what's inside the parenthesis

  29. tanyahosler
    • 2 years ago
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    ok i'm lost

  30. inkyvoyd
    • 2 years ago
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    Exponents are before multiplcation and division, always!

  31. tanyahosler
    • 2 years ago
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    i'm lost

  32. zscdragon
    • 2 years ago
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    @tanyahosler look relax, everything's fine, just look at what I'll say

  33. inkyvoyd
    • 2 years ago
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    Here, should look like this \(-5*(\text{ }(-2)^2\text{ })\)

  34. zscdragon
    • 2 years ago
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    \[-5 * a^2\] is the equation, now what if you replace 'a' by -2

  35. inkyvoyd
    • 2 years ago
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    @zscdragon , Please do not curse on this site. I'm reporting you for foul language.

  36. tanyahosler
    • 2 years ago
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    i am still a lil confused

  37. inkyvoyd
    • 2 years ago
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    tanya, you want to "square" the a. The a is -2 in this case . What's negative 2 squared?

  38. zscdragon
    • 2 years ago
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    @tanyahosler , ok don't listen to that @inkyvoyd, he's all confused and doesn't know his material

  39. tanyahosler
    • 2 years ago
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    please guys i need help i have to have this in by saturday

  40. inkyvoyd
    • 2 years ago
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    @tanyahosler , It's okay. I'll help you by personal message, because zsc is being distracting. Why don't you tell me what you don't understand in a message :)

  41. tanyahosler
    • 2 years ago
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    ok

  42. tanyahosler
    • 2 years ago
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    it isn't a test it is homework and i don't know how to put the problems in here right

  43. inkyvoyd
    • 2 years ago
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    It's alright, I'll spend time to explain it. I have a few hours on hand, and I'm willing to use them :)

  44. tanyahosler
    • 2 years ago
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    ok i'm not sure how to do algebra anymore been 22 yrs since school

  45. tanyahosler
    • 2 years ago
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    the next one is going to be really difficult for me to put in cause i don't know how

  46. inkyvoyd
    • 2 years ago
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    Press the equation button. It should help.

  47. inkyvoyd
    • 2 years ago
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    Other wise you could try taking a screenshot, and uploading it.

  48. tanyahosler
    • 2 years ago
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    ok it is in my textbook

  49. tanyahosler
    • 2 years ago
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    but i wanna get this one done

  50. inkyvoyd
    • 2 years ago
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    Hm. Try using the equation button. Tell me if you have trouble.

  51. tanyahosler
    • 2 years ago
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    i don't know how to enter it in there

  52. inkyvoyd
    • 2 years ago
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    I see that you have gone from insulting language to stalking. I am slightly annoyed, but more so amused. I do request that if you want to publicly "embarrass" me, that you DO NOT POST HERE AND HIJACK SOMEONE'S THREAD. Please post it in chat. Thank you.

  53. Mayah3
    • 2 years ago
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    O_O!!!!!!!!!!!!!!!!!

  54. inkyvoyd
    • 2 years ago
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    I'm going to completely ignore you, not because I don't want to answer, but because this isn't your thread to hijack (nor is it mine). If you have a problem with me, let's fight it out in chat, instead of hijacking tanya's post.

  55. tanyahosler
    • 2 years ago
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    \[\sqrt{b ^{2-4ac;b=3,a=-1,c=-2}}\]

  56. tanyahosler
    • 2 years ago
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    not sure if i did that right

  57. Mayah3
    • 2 years ago
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    Can You Like Build A Bridge And Get Over It?

  58. inkyvoyd
    • 2 years ago
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    Oh, I know what you are trying to post. Is it \(\sqrt{b^2-4ac};b=3,a=-1,c=-2\)

  59. Carniel
    • 2 years ago
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    @Zscdragon Stop trolling or I will report you

  60. inkyvoyd
    • 2 years ago
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    @Mayah3 , My side's open, but I don't think his is. :(

  61. zscdragon
    • 2 years ago
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    @Carniel everything I said is based on reason, please re-read that a few times

  62. tanyahosler
    • 2 years ago
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    yes that is it inkyvoyd

  63. inkyvoyd
    • 2 years ago
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    Okay @tanyahosler . Put in what you are given for the letters. \(\sqrt{b^2-4ac}\) a=-1, b=-2, and c=3

  64. inkyvoyd
    • 2 years ago
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    @zscdragon , Please don't use this thread to insult me. Please insult me in chat. You are being incredibly rude and disruptive to the OP.

  65. Carniel
    • 2 years ago
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    Again your getting out of hand.

  66. tanyahosler
    • 2 years ago
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    b = 3, a=-1, c= -2

  67. inkyvoyd
    • 2 years ago
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    a=-1, b=-2, and c=3 Put (-1) for all the a's you see. Like this. \(\sqrt{b^2-4(-1)c}\) That make sense to you?

  68. zscdragon
    • 2 years ago
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    @inkyvoyd i never insulted you. all i write are facts and truths, nothing less, nothing more. u dont like it, dont read it ;)

  69. tanyahosler
    • 2 years ago
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    yes

  70. inkyvoyd
    • 2 years ago
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    Now, try the same for b.

  71. inkyvoyd
    • 2 years ago
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    \(\sqrt{b^2-4(-1)c}\) b=-2 here. Remember, just put the negative 2 in parenthesis, and square it. ignore the square root for now, and just type in what you get without the square root. Try using "Draw" if you have to.

  72. tanyahosler
    • 2 years ago
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    9

  73. Mayah3
    • 2 years ago
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    can he just shut up?

  74. inkyvoyd
    • 2 years ago
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    @zscdragon , I'd be happy to answer any of your comments if you post them in the appropriate math chat. What you are discussing does not pertain to what Tanya is trying to learn about, and thus is going to be ignored completely by me. Again, post it in chat, and I will answer. This is the last time I will reply to you on this thread because you are not being productive. Thank you.

  75. Carniel
    • 2 years ago
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    Your posting in a OQ he is trying to answer. Anything else out of you and I will report you

  76. tanyahosler
    • 2 years ago
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    |dw:1343280511266:dw|

  77. inkyvoyd
    • 2 years ago
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    Yes. But put the "a" and "b" in :)

  78. inkyvoyd
    • 2 years ago
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    |dw:1343280648000:dw|

  79. Mayah3
    • 2 years ago
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    Dude ! Shut Up Okay? Dang. No One Cares About Your Comments. You're Making A Fool Out Of Yourself -___-

  80. tanyahosler
    • 2 years ago
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    i'm just trying to get help so i understand and thats all dang

  81. Carniel
    • 2 years ago
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    Im done trying to negotiate im reporting

  82. inkyvoyd
    • 2 years ago
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    @tanyahosler , Mayah was not talking to you :)

  83. tanyahosler
    • 2 years ago
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    oh ok

  84. tanyahosler
    • 2 years ago
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    leave me out of your little battle here so he is helping me i don't care who went where as long as they are explaining it to me so i can get the help i need

  85. Mayah3
    • 2 years ago
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    Ohh You've Just Been Told

  86. inkyvoyd
    • 2 years ago
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    \(\sqrt{ (-2)^2-4(-1)(3)}\)

  87. inkyvoyd
    • 2 years ago
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    See? All I did was replace a, b, and c, with what they were as numbers :)

  88. panlac01
    • 2 years ago
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    the competition going on in helping is actually getting in the way of helping.

  89. inkyvoyd
    • 2 years ago
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    There actually is no competition, @panlac01 . zsc stopped helping her a long time ago. I switched to messaging her because he was harassing us too badly, and it was getting distracting. We are almost done with a third problem.

  90. panlac01
    • 2 years ago
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    is she looking for an answer? because Khan academy would be better off for her to get her quick lessons.

  91. tanyahosler
    • 2 years ago
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    no just help

  92. panlac01
    • 2 years ago
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    k

  93. panlac01
    • 2 years ago
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    do you go over your lectures and textbook?

  94. inkyvoyd
    • 2 years ago
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    @panlac01 , a lot of the original posts of zsc got deleted, so it might not make much sense. We are fine though, just finishing a problem.

  95. tanyahosler
    • 2 years ago
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    yes but i got confused

  96. tanyahosler
    • 2 years ago
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    ok i understand it a lil bit

  97. inkyvoyd
    • 2 years ago
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    \(\sqrt{ (-2)^2-4(-1)(3)}\) So, just evaluate straight through. Try it yourself once, tell me what you get...

  98. panlac01
    • 2 years ago
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    what level of algebra are you tackling? because the problems being posted are rather easy so long as your fundamentals are solid. practice 3-5 hours a day on top of your lessons. if you think you're lagging, seek the help of your professor. some textbooks are pretty helpful like Practical Algebra a self-teaching guide by Peter Selby et al.

  99. tanyahosler
    • 2 years ago
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    9

  100. tanyahosler
    • 2 years ago
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    intermediate algebra

  101. panlac01
    • 2 years ago
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    good luck. go over all your notes and examples provided by your professor and specially the textbook.

  102. inkyvoyd
    • 2 years ago
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    @panlac01 , can you help her out if she has anymore questions? I just finished the problem, but I must go to sleep now.

  103. panlac01
    • 2 years ago
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    she will be fine.

  104. tanyahosler
    • 2 years ago
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    i get confused on story problems and that is what my other 2 is would anyone like to help me on these

  105. panlac01
    • 2 years ago
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    check the textbook that I mention. it has a good lesson for you to tackle word problems in math. majority of the keywords are discussed in details

  106. panlac01
    • 2 years ago
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    it is less than 15 bucks in barnes and noble or even cheaper if you bought it online as used

  107. tanyahosler
    • 2 years ago
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    ok i understand that part but it is telling me to find the amount of aspirin to give a 10 yr old of and adult dosage of 325 milligrams it confuses me

  108. tanyahosler
    • 2 years ago
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    ok i will check that book out but i got to figure these out before saturday

  109. panlac01
    • 2 years ago
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    in pharmacology, the adult dosage is always 1.5 or twice the pediatric's

  110. panlac01
    • 2 years ago
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    that's the rule of thumb. but there are factors to consider, such as (BMI) or weight of the person, age, and gender

  111. tanyahosler
    • 2 years ago
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    so half of that then right

  112. tanyahosler
    • 2 years ago
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    it only says the age not the weight or the gender

  113. tanyahosler
    • 2 years ago
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    my question is Find the amount of aspirin to give a child of age 10 if the usual adult dosage is 325 milligrams

  114. tanyahosler
    • 2 years ago
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    so i'm confused

  115. panlac01
    • 2 years ago
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    try half that amount.

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