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inkyvoydBest ResponseYou've already chosen the best response.3
Okay, post it here :)
 one year ago

shrutiBest ResponseYou've already chosen the best response.0
okay. now post your problem here.
 one year ago

zscdragonBest ResponseYou've already chosen the best response.0
take you time baby, relax ;)
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
it is 4x to the 4th power  7x to the 3rd power  12x to the 4th power +6x to the 3rd power
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
\(4x^47x^312x^4+6x^3\)?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
what you ned to do is combine like terms. Let me rewrite it a little for you \(4x^412x^47x^3+6x^3\)
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
@zscdragon , please read the code of conduct. http://openstudy.com/codeofconduct We are here to help people, not give them the answers...
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
By the way, my post lagged, so somehow it came out after @zscdragon 's did. But, essentially, we did the same thing.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
Actually because my internet is being slow. And I was serious about giving the answers. We are here to teach, not to cheat.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
More importantly, @tanyahosler , do you understand?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
I mean the problem xD
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
what about helping me with this one 5a to the 2nd power; a=2 can someone help me thru this one
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
yeah i got it i understand how they got it
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
replace the a with a negative 2
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
Right now you have \(5a^2\), put in a 2 (with parenthesis!) inside, and tell me what you get
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
Did you read http://openstudy.com/codeofconduct @zscdragon ? We are not supposed to nor allowed to just give answers like that.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
@tanyahosler , how did you get that answer?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
No :( Uh, let me show you what I meant
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
So, we have \(5a^2\) instead of \(a\), we want (2). So just put it in. \(5*(2)^2\) Exponents first Can you try to do the rest?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
No  square what's inside the parenthesis
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
Exponents are before multiplcation and division, always!
 one year ago

zscdragonBest ResponseYou've already chosen the best response.0
@tanyahosler look relax, everything's fine, just look at what I'll say
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
Here, should look like this \(5*(\text{ }(2)^2\text{ })\)
 one year ago

zscdragonBest ResponseYou've already chosen the best response.0
\[5 * a^2\] is the equation, now what if you replace 'a' by 2
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
@zscdragon , Please do not curse on this site. I'm reporting you for foul language.
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
i am still a lil confused
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
tanya, you want to "square" the a. The a is 2 in this case . What's negative 2 squared?
 one year ago

zscdragonBest ResponseYou've already chosen the best response.0
@tanyahosler , ok don't listen to that @inkyvoyd, he's all confused and doesn't know his material
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
please guys i need help i have to have this in by saturday
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
@tanyahosler , It's okay. I'll help you by personal message, because zsc is being distracting. Why don't you tell me what you don't understand in a message :)
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
it isn't a test it is homework and i don't know how to put the problems in here right
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
It's alright, I'll spend time to explain it. I have a few hours on hand, and I'm willing to use them :)
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
ok i'm not sure how to do algebra anymore been 22 yrs since school
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
the next one is going to be really difficult for me to put in cause i don't know how
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
Press the equation button. It should help.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
Other wise you could try taking a screenshot, and uploading it.
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
ok it is in my textbook
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
but i wanna get this one done
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
Hm. Try using the equation button. Tell me if you have trouble.
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
i don't know how to enter it in there
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
I see that you have gone from insulting language to stalking. I am slightly annoyed, but more so amused. I do request that if you want to publicly "embarrass" me, that you DO NOT POST HERE AND HIJACK SOMEONE'S THREAD. Please post it in chat. Thank you.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
I'm going to completely ignore you, not because I don't want to answer, but because this isn't your thread to hijack (nor is it mine). If you have a problem with me, let's fight it out in chat, instead of hijacking tanya's post.
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
\[\sqrt{b ^{24ac;b=3,a=1,c=2}}\]
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
not sure if i did that right
 one year ago

Mayah3Best ResponseYou've already chosen the best response.0
Can You Like Build A Bridge And Get Over It?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
Oh, I know what you are trying to post. Is it \(\sqrt{b^24ac};b=3,a=1,c=2\)
 one year ago

CarnielBest ResponseYou've already chosen the best response.0
@Zscdragon Stop trolling or I will report you
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
@Mayah3 , My side's open, but I don't think his is. :(
 one year ago

zscdragonBest ResponseYou've already chosen the best response.0
@Carniel everything I said is based on reason, please reread that a few times
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
yes that is it inkyvoyd
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
Okay @tanyahosler . Put in what you are given for the letters. \(\sqrt{b^24ac}\) a=1, b=2, and c=3
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
@zscdragon , Please don't use this thread to insult me. Please insult me in chat. You are being incredibly rude and disruptive to the OP.
 one year ago

CarnielBest ResponseYou've already chosen the best response.0
Again your getting out of hand.
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
b = 3, a=1, c= 2
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
a=1, b=2, and c=3 Put (1) for all the a's you see. Like this. \(\sqrt{b^24(1)c}\) That make sense to you?
 one year ago

zscdragonBest ResponseYou've already chosen the best response.0
@inkyvoyd i never insulted you. all i write are facts and truths, nothing less, nothing more. u dont like it, dont read it ;)
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
Now, try the same for b.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
\(\sqrt{b^24(1)c}\) b=2 here. Remember, just put the negative 2 in parenthesis, and square it. ignore the square root for now, and just type in what you get without the square root. Try using "Draw" if you have to.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
@zscdragon , I'd be happy to answer any of your comments if you post them in the appropriate math chat. What you are discussing does not pertain to what Tanya is trying to learn about, and thus is going to be ignored completely by me. Again, post it in chat, and I will answer. This is the last time I will reply to you on this thread because you are not being productive. Thank you.
 one year ago

CarnielBest ResponseYou've already chosen the best response.0
Your posting in a OQ he is trying to answer. Anything else out of you and I will report you
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
dw:1343280511266:dw
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
Yes. But put the "a" and "b" in :)
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
dw:1343280648000:dw
 one year ago

Mayah3Best ResponseYou've already chosen the best response.0
Dude ! Shut Up Okay? Dang. No One Cares About Your Comments. You're Making A Fool Out Of Yourself ___
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
i'm just trying to get help so i understand and thats all dang
 one year ago

CarnielBest ResponseYou've already chosen the best response.0
Im done trying to negotiate im reporting
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
@tanyahosler , Mayah was not talking to you :)
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
leave me out of your little battle here so he is helping me i don't care who went where as long as they are explaining it to me so i can get the help i need
 one year ago

Mayah3Best ResponseYou've already chosen the best response.0
Ohh You've Just Been Told
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
\(\sqrt{ (2)^24(1)(3)}\)
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
See? All I did was replace a, b, and c, with what they were as numbers :)
 one year ago

panlac01Best ResponseYou've already chosen the best response.1
the competition going on in helping is actually getting in the way of helping.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
There actually is no competition, @panlac01 . zsc stopped helping her a long time ago. I switched to messaging her because he was harassing us too badly, and it was getting distracting. We are almost done with a third problem.
 one year ago

panlac01Best ResponseYou've already chosen the best response.1
is she looking for an answer? because Khan academy would be better off for her to get her quick lessons.
 one year ago

panlac01Best ResponseYou've already chosen the best response.1
do you go over your lectures and textbook?
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
@panlac01 , a lot of the original posts of zsc got deleted, so it might not make much sense. We are fine though, just finishing a problem.
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
yes but i got confused
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
ok i understand it a lil bit
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
\(\sqrt{ (2)^24(1)(3)}\) So, just evaluate straight through. Try it yourself once, tell me what you get...
 one year ago

panlac01Best ResponseYou've already chosen the best response.1
what level of algebra are you tackling? because the problems being posted are rather easy so long as your fundamentals are solid. practice 35 hours a day on top of your lessons. if you think you're lagging, seek the help of your professor. some textbooks are pretty helpful like Practical Algebra a selfteaching guide by Peter Selby et al.
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
intermediate algebra
 one year ago

panlac01Best ResponseYou've already chosen the best response.1
good luck. go over all your notes and examples provided by your professor and specially the textbook.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.3
@panlac01 , can you help her out if she has anymore questions? I just finished the problem, but I must go to sleep now.
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
i get confused on story problems and that is what my other 2 is would anyone like to help me on these
 one year ago

panlac01Best ResponseYou've already chosen the best response.1
check the textbook that I mention. it has a good lesson for you to tackle word problems in math. majority of the keywords are discussed in details
 one year ago

panlac01Best ResponseYou've already chosen the best response.1
it is less than 15 bucks in barnes and noble or even cheaper if you bought it online as used
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
ok i understand that part but it is telling me to find the amount of aspirin to give a 10 yr old of and adult dosage of 325 milligrams it confuses me
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
ok i will check that book out but i got to figure these out before saturday
 one year ago

panlac01Best ResponseYou've already chosen the best response.1
in pharmacology, the adult dosage is always 1.5 or twice the pediatric's
 one year ago

panlac01Best ResponseYou've already chosen the best response.1
that's the rule of thumb. but there are factors to consider, such as (BMI) or weight of the person, age, and gender
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
so half of that then right
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
it only says the age not the weight or the gender
 one year ago

tanyahoslerBest ResponseYou've already chosen the best response.0
my question is Find the amount of aspirin to give a child of age 10 if the usual adult dosage is 325 milligrams
 one year ago

panlac01Best ResponseYou've already chosen the best response.1
try half that amount.
 one year ago
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