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i have a problems with my algebra homework

Mathematics
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Okay, post it here :)
okay. now post your problem here.
take you time baby, relax ;)

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Other answers:

It's Yao Ming!
it is 4x to the 4th power - 7x to the 3rd power - 12x to the 4th power +6x to the 3rd power
\(4x^4-7x^3-12x^4+6x^3\)?
yes
what you ned to do is combine like terms. Let me rewrite it a little for you \(4x^4-12x^4-7x^3+6x^3\)
@zscdragon , please read the code of conduct. http://openstudy.com/code-of-conduct We are here to help people, not give them the answers...
By the way, my post lagged, so somehow it came out after @zscdragon 's did. But, essentially, we did the same thing.
Actually because my internet is being slow. And I was serious about giving the answers. We are here to teach, not to cheat.
More importantly, @tanyahosler , do you understand?
I mean the problem xD
what about helping me with this one -5a to the 2nd power; a=-2 can someone help me thru this one
yeah i got it i understand how they got it
replace the a with a negative 2
Right now you have \(-5a^2\), put in a -2 (with parenthesis!) inside, and tell me what you get
3
Did you read http://openstudy.com/code-of-conduct @zscdragon ? We are not supposed to nor allowed to just give answers like that.
3 squared
@tanyahosler , how did you get that answer?
subtracted it
was i right
No :( Uh, let me show you what I meant
ok
So, we have \(-5a^2\) instead of \(a\), we want (-2). So just put it in. \(-5*(-2)^2\) Exponents first Can you try to do the rest?
so 10squared
No - square what's inside the parenthesis
ok i'm lost
Exponents are before multiplcation and division, always!
i'm lost
@tanyahosler look relax, everything's fine, just look at what I'll say
Here, should look like this \(-5*(\text{ }(-2)^2\text{ })\)
\[-5 * a^2\] is the equation, now what if you replace 'a' by -2
@zscdragon , Please do not curse on this site. I'm reporting you for foul language.
i am still a lil confused
tanya, you want to "square" the a. The a is -2 in this case . What's negative 2 squared?
@tanyahosler , ok don't listen to that @inkyvoyd, he's all confused and doesn't know his material
please guys i need help i have to have this in by saturday
@tanyahosler , It's okay. I'll help you by personal message, because zsc is being distracting. Why don't you tell me what you don't understand in a message :)
ok
it isn't a test it is homework and i don't know how to put the problems in here right
It's alright, I'll spend time to explain it. I have a few hours on hand, and I'm willing to use them :)
ok i'm not sure how to do algebra anymore been 22 yrs since school
the next one is going to be really difficult for me to put in cause i don't know how
Press the equation button. It should help.
Other wise you could try taking a screenshot, and uploading it.
ok it is in my textbook
but i wanna get this one done
Hm. Try using the equation button. Tell me if you have trouble.
i don't know how to enter it in there
I see that you have gone from insulting language to stalking. I am slightly annoyed, but more so amused. I do request that if you want to publicly "embarrass" me, that you DO NOT POST HERE AND HIJACK SOMEONE'S THREAD. Please post it in chat. Thank you.
O_O!!!!!!!!!!!!!!!!!
I'm going to completely ignore you, not because I don't want to answer, but because this isn't your thread to hijack (nor is it mine). If you have a problem with me, let's fight it out in chat, instead of hijacking tanya's post.
\[\sqrt{b ^{2-4ac;b=3,a=-1,c=-2}}\]
not sure if i did that right
Can You Like Build A Bridge And Get Over It?
Oh, I know what you are trying to post. Is it \(\sqrt{b^2-4ac};b=3,a=-1,c=-2\)
@Zscdragon Stop trolling or I will report you
@Mayah3 , My side's open, but I don't think his is. :(
@Carniel everything I said is based on reason, please re-read that a few times
yes that is it inkyvoyd
Okay @tanyahosler . Put in what you are given for the letters. \(\sqrt{b^2-4ac}\) a=-1, b=-2, and c=3
@zscdragon , Please don't use this thread to insult me. Please insult me in chat. You are being incredibly rude and disruptive to the OP.
Again your getting out of hand.
b = 3, a=-1, c= -2
a=-1, b=-2, and c=3 Put (-1) for all the a's you see. Like this. \(\sqrt{b^2-4(-1)c}\) That make sense to you?
@inkyvoyd i never insulted you. all i write are facts and truths, nothing less, nothing more. u dont like it, dont read it ;)
yes
Now, try the same for b.
\(\sqrt{b^2-4(-1)c}\) b=-2 here. Remember, just put the negative 2 in parenthesis, and square it. ignore the square root for now, and just type in what you get without the square root. Try using "Draw" if you have to.
9
can he just shut up?
@zscdragon , I'd be happy to answer any of your comments if you post them in the appropriate math chat. What you are discussing does not pertain to what Tanya is trying to learn about, and thus is going to be ignored completely by me. Again, post it in chat, and I will answer. This is the last time I will reply to you on this thread because you are not being productive. Thank you.
Your posting in a OQ he is trying to answer. Anything else out of you and I will report you
|dw:1343280511266:dw|
Yes. But put the "a" and "b" in :)
|dw:1343280648000:dw|
Dude ! Shut Up Okay? Dang. No One Cares About Your Comments. You're Making A Fool Out Of Yourself -___-
i'm just trying to get help so i understand and thats all dang
Im done trying to negotiate im reporting
@tanyahosler , Mayah was not talking to you :)
oh ok
leave me out of your little battle here so he is helping me i don't care who went where as long as they are explaining it to me so i can get the help i need
Ohh You've Just Been Told
\(\sqrt{ (-2)^2-4(-1)(3)}\)
See? All I did was replace a, b, and c, with what they were as numbers :)
the competition going on in helping is actually getting in the way of helping.
There actually is no competition, @panlac01 . zsc stopped helping her a long time ago. I switched to messaging her because he was harassing us too badly, and it was getting distracting. We are almost done with a third problem.
is she looking for an answer? because Khan academy would be better off for her to get her quick lessons.
no just help
k
do you go over your lectures and textbook?
@panlac01 , a lot of the original posts of zsc got deleted, so it might not make much sense. We are fine though, just finishing a problem.
yes but i got confused
ok i understand it a lil bit
\(\sqrt{ (-2)^2-4(-1)(3)}\) So, just evaluate straight through. Try it yourself once, tell me what you get...
what level of algebra are you tackling? because the problems being posted are rather easy so long as your fundamentals are solid. practice 3-5 hours a day on top of your lessons. if you think you're lagging, seek the help of your professor. some textbooks are pretty helpful like Practical Algebra a self-teaching guide by Peter Selby et al.
9
intermediate algebra
good luck. go over all your notes and examples provided by your professor and specially the textbook.
@panlac01 , can you help her out if she has anymore questions? I just finished the problem, but I must go to sleep now.
she will be fine.
i get confused on story problems and that is what my other 2 is would anyone like to help me on these
check the textbook that I mention. it has a good lesson for you to tackle word problems in math. majority of the keywords are discussed in details
it is less than 15 bucks in barnes and noble or even cheaper if you bought it online as used
ok i understand that part but it is telling me to find the amount of aspirin to give a 10 yr old of and adult dosage of 325 milligrams it confuses me
ok i will check that book out but i got to figure these out before saturday
in pharmacology, the adult dosage is always 1.5 or twice the pediatric's
that's the rule of thumb. but there are factors to consider, such as (BMI) or weight of the person, age, and gender
so half of that then right
it only says the age not the weight or the gender
my question is Find the amount of aspirin to give a child of age 10 if the usual adult dosage is 325 milligrams
so i'm confused
try half that amount.

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