tanyahosler 3 years ago i have a problems with my algebra homework

1. inkyvoyd

Okay, post it here :)

2. shruti

okay. now post your problem here.

3. zscdragon

take you time baby, relax ;)

4. Hero

It's Yao Ming!

5. tanyahosler

it is 4x to the 4th power - 7x to the 3rd power - 12x to the 4th power +6x to the 3rd power

6. inkyvoyd

$$4x^4-7x^3-12x^4+6x^3$$?

7. tanyahosler

yes

8. inkyvoyd

what you ned to do is combine like terms. Let me rewrite it a little for you $$4x^4-12x^4-7x^3+6x^3$$

9. inkyvoyd

@zscdragon , please read the code of conduct. http://openstudy.com/code-of-conduct We are here to help people, not give them the answers...

10. inkyvoyd

By the way, my post lagged, so somehow it came out after @zscdragon 's did. But, essentially, we did the same thing.

11. inkyvoyd

Actually because my internet is being slow. And I was serious about giving the answers. We are here to teach, not to cheat.

12. inkyvoyd

More importantly, @tanyahosler , do you understand?

13. inkyvoyd

I mean the problem xD

14. tanyahosler

what about helping me with this one -5a to the 2nd power; a=-2 can someone help me thru this one

15. tanyahosler

yeah i got it i understand how they got it

16. inkyvoyd

replace the a with a negative 2

17. inkyvoyd

Right now you have $$-5a^2$$, put in a -2 (with parenthesis!) inside, and tell me what you get

18. tanyahosler

3

19. inkyvoyd

Did you read http://openstudy.com/code-of-conduct @zscdragon ? We are not supposed to nor allowed to just give answers like that.

20. tanyahosler

3 squared

21. inkyvoyd

@tanyahosler , how did you get that answer?

22. tanyahosler

subtracted it

23. tanyahosler

was i right

24. inkyvoyd

No :( Uh, let me show you what I meant

25. tanyahosler

ok

26. inkyvoyd

So, we have $$-5a^2$$ instead of $$a$$, we want (-2). So just put it in. $$-5*(-2)^2$$ Exponents first Can you try to do the rest?

27. tanyahosler

so 10squared

28. inkyvoyd

No - square what's inside the parenthesis

29. tanyahosler

ok i'm lost

30. inkyvoyd

Exponents are before multiplcation and division, always!

31. tanyahosler

i'm lost

32. zscdragon

@tanyahosler look relax, everything's fine, just look at what I'll say

33. inkyvoyd

Here, should look like this $$-5*(\text{ }(-2)^2\text{ })$$

34. zscdragon

$-5 * a^2$ is the equation, now what if you replace 'a' by -2

35. inkyvoyd

@zscdragon , Please do not curse on this site. I'm reporting you for foul language.

36. tanyahosler

i am still a lil confused

37. inkyvoyd

tanya, you want to "square" the a. The a is -2 in this case . What's negative 2 squared?

38. zscdragon

@tanyahosler , ok don't listen to that @inkyvoyd, he's all confused and doesn't know his material

39. tanyahosler

please guys i need help i have to have this in by saturday

40. inkyvoyd

@tanyahosler , It's okay. I'll help you by personal message, because zsc is being distracting. Why don't you tell me what you don't understand in a message :)

41. tanyahosler

ok

42. tanyahosler

it isn't a test it is homework and i don't know how to put the problems in here right

43. inkyvoyd

It's alright, I'll spend time to explain it. I have a few hours on hand, and I'm willing to use them :)

44. tanyahosler

ok i'm not sure how to do algebra anymore been 22 yrs since school

45. tanyahosler

the next one is going to be really difficult for me to put in cause i don't know how

46. inkyvoyd

Press the equation button. It should help.

47. inkyvoyd

48. tanyahosler

ok it is in my textbook

49. tanyahosler

but i wanna get this one done

50. inkyvoyd

Hm. Try using the equation button. Tell me if you have trouble.

51. tanyahosler

i don't know how to enter it in there

52. inkyvoyd

I see that you have gone from insulting language to stalking. I am slightly annoyed, but more so amused. I do request that if you want to publicly "embarrass" me, that you DO NOT POST HERE AND HIJACK SOMEONE'S THREAD. Please post it in chat. Thank you.

53. Mayah3

O_O!!!!!!!!!!!!!!!!!

54. inkyvoyd

I'm going to completely ignore you, not because I don't want to answer, but because this isn't your thread to hijack (nor is it mine). If you have a problem with me, let's fight it out in chat, instead of hijacking tanya's post.

55. tanyahosler

$\sqrt{b ^{2-4ac;b=3,a=-1,c=-2}}$

56. tanyahosler

not sure if i did that right

57. Mayah3

Can You Like Build A Bridge And Get Over It?

58. inkyvoyd

Oh, I know what you are trying to post. Is it $$\sqrt{b^2-4ac};b=3,a=-1,c=-2$$

59. Carniel

@Zscdragon Stop trolling or I will report you

60. inkyvoyd

@Mayah3 , My side's open, but I don't think his is. :(

61. zscdragon

@Carniel everything I said is based on reason, please re-read that a few times

62. tanyahosler

yes that is it inkyvoyd

63. inkyvoyd

Okay @tanyahosler . Put in what you are given for the letters. $$\sqrt{b^2-4ac}$$ a=-1, b=-2, and c=3

64. inkyvoyd

@zscdragon , Please don't use this thread to insult me. Please insult me in chat. You are being incredibly rude and disruptive to the OP.

65. Carniel

Again your getting out of hand.

66. tanyahosler

b = 3, a=-1, c= -2

67. inkyvoyd

a=-1, b=-2, and c=3 Put (-1) for all the a's you see. Like this. $$\sqrt{b^2-4(-1)c}$$ That make sense to you?

68. zscdragon

@inkyvoyd i never insulted you. all i write are facts and truths, nothing less, nothing more. u dont like it, dont read it ;)

69. tanyahosler

yes

70. inkyvoyd

Now, try the same for b.

71. inkyvoyd

$$\sqrt{b^2-4(-1)c}$$ b=-2 here. Remember, just put the negative 2 in parenthesis, and square it. ignore the square root for now, and just type in what you get without the square root. Try using "Draw" if you have to.

72. tanyahosler

9

73. Mayah3

can he just shut up?

74. inkyvoyd

@zscdragon , I'd be happy to answer any of your comments if you post them in the appropriate math chat. What you are discussing does not pertain to what Tanya is trying to learn about, and thus is going to be ignored completely by me. Again, post it in chat, and I will answer. This is the last time I will reply to you on this thread because you are not being productive. Thank you.

75. Carniel

Your posting in a OQ he is trying to answer. Anything else out of you and I will report you

76. tanyahosler

|dw:1343280511266:dw|

77. inkyvoyd

Yes. But put the "a" and "b" in :)

78. inkyvoyd

|dw:1343280648000:dw|

79. Mayah3

Dude ! Shut Up Okay? Dang. No One Cares About Your Comments. You're Making A Fool Out Of Yourself -___-

80. tanyahosler

i'm just trying to get help so i understand and thats all dang

81. Carniel

Im done trying to negotiate im reporting

82. inkyvoyd

@tanyahosler , Mayah was not talking to you :)

83. tanyahosler

oh ok

84. tanyahosler

leave me out of your little battle here so he is helping me i don't care who went where as long as they are explaining it to me so i can get the help i need

85. Mayah3

Ohh You've Just Been Told

86. inkyvoyd

$$\sqrt{ (-2)^2-4(-1)(3)}$$

87. inkyvoyd

See? All I did was replace a, b, and c, with what they were as numbers :)

88. panlac01

the competition going on in helping is actually getting in the way of helping.

89. inkyvoyd

There actually is no competition, @panlac01 . zsc stopped helping her a long time ago. I switched to messaging her because he was harassing us too badly, and it was getting distracting. We are almost done with a third problem.

90. panlac01

is she looking for an answer? because Khan academy would be better off for her to get her quick lessons.

91. tanyahosler

no just help

92. panlac01

k

93. panlac01

do you go over your lectures and textbook?

94. inkyvoyd

@panlac01 , a lot of the original posts of zsc got deleted, so it might not make much sense. We are fine though, just finishing a problem.

95. tanyahosler

yes but i got confused

96. tanyahosler

ok i understand it a lil bit

97. inkyvoyd

$$\sqrt{ (-2)^2-4(-1)(3)}$$ So, just evaluate straight through. Try it yourself once, tell me what you get...

98. panlac01

what level of algebra are you tackling? because the problems being posted are rather easy so long as your fundamentals are solid. practice 3-5 hours a day on top of your lessons. if you think you're lagging, seek the help of your professor. some textbooks are pretty helpful like Practical Algebra a self-teaching guide by Peter Selby et al.

99. tanyahosler

9

100. tanyahosler

intermediate algebra

101. panlac01

good luck. go over all your notes and examples provided by your professor and specially the textbook.

102. inkyvoyd

@panlac01 , can you help her out if she has anymore questions? I just finished the problem, but I must go to sleep now.

103. panlac01

she will be fine.

104. tanyahosler

i get confused on story problems and that is what my other 2 is would anyone like to help me on these

105. panlac01

check the textbook that I mention. it has a good lesson for you to tackle word problems in math. majority of the keywords are discussed in details

106. panlac01

it is less than 15 bucks in barnes and noble or even cheaper if you bought it online as used

107. tanyahosler

ok i understand that part but it is telling me to find the amount of aspirin to give a 10 yr old of and adult dosage of 325 milligrams it confuses me

108. tanyahosler

ok i will check that book out but i got to figure these out before saturday

109. panlac01

in pharmacology, the adult dosage is always 1.5 or twice the pediatric's

110. panlac01

that's the rule of thumb. but there are factors to consider, such as (BMI) or weight of the person, age, and gender

111. tanyahosler

so half of that then right

112. tanyahosler

it only says the age not the weight or the gender

113. tanyahosler

my question is Find the amount of aspirin to give a child of age 10 if the usual adult dosage is 325 milligrams

114. tanyahosler

so i'm confused

115. panlac01

try half that amount.