anonymous
  • anonymous
i have a problems with my algebra homework
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
inkyvoyd
  • inkyvoyd
Okay, post it here :)
anonymous
  • anonymous
okay. now post your problem here.
anonymous
  • anonymous
take you time baby, relax ;)

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More answers

Hero
  • Hero
It's Yao Ming!
anonymous
  • anonymous
it is 4x to the 4th power - 7x to the 3rd power - 12x to the 4th power +6x to the 3rd power
inkyvoyd
  • inkyvoyd
\(4x^4-7x^3-12x^4+6x^3\)?
anonymous
  • anonymous
yes
inkyvoyd
  • inkyvoyd
what you ned to do is combine like terms. Let me rewrite it a little for you \(4x^4-12x^4-7x^3+6x^3\)
inkyvoyd
  • inkyvoyd
@zscdragon , please read the code of conduct. http://openstudy.com/code-of-conduct We are here to help people, not give them the answers...
inkyvoyd
  • inkyvoyd
By the way, my post lagged, so somehow it came out after @zscdragon 's did. But, essentially, we did the same thing.
inkyvoyd
  • inkyvoyd
Actually because my internet is being slow. And I was serious about giving the answers. We are here to teach, not to cheat.
inkyvoyd
  • inkyvoyd
More importantly, @tanyahosler , do you understand?
inkyvoyd
  • inkyvoyd
I mean the problem xD
anonymous
  • anonymous
what about helping me with this one -5a to the 2nd power; a=-2 can someone help me thru this one
anonymous
  • anonymous
yeah i got it i understand how they got it
inkyvoyd
  • inkyvoyd
replace the a with a negative 2
inkyvoyd
  • inkyvoyd
Right now you have \(-5a^2\), put in a -2 (with parenthesis!) inside, and tell me what you get
anonymous
  • anonymous
3
inkyvoyd
  • inkyvoyd
Did you read http://openstudy.com/code-of-conduct @zscdragon ? We are not supposed to nor allowed to just give answers like that.
anonymous
  • anonymous
3 squared
inkyvoyd
  • inkyvoyd
@tanyahosler , how did you get that answer?
anonymous
  • anonymous
subtracted it
anonymous
  • anonymous
was i right
inkyvoyd
  • inkyvoyd
No :( Uh, let me show you what I meant
anonymous
  • anonymous
ok
inkyvoyd
  • inkyvoyd
So, we have \(-5a^2\) instead of \(a\), we want (-2). So just put it in. \(-5*(-2)^2\) Exponents first Can you try to do the rest?
anonymous
  • anonymous
so 10squared
inkyvoyd
  • inkyvoyd
No - square what's inside the parenthesis
anonymous
  • anonymous
ok i'm lost
inkyvoyd
  • inkyvoyd
Exponents are before multiplcation and division, always!
anonymous
  • anonymous
i'm lost
anonymous
  • anonymous
@tanyahosler look relax, everything's fine, just look at what I'll say
inkyvoyd
  • inkyvoyd
Here, should look like this \(-5*(\text{ }(-2)^2\text{ })\)
anonymous
  • anonymous
\[-5 * a^2\] is the equation, now what if you replace 'a' by -2
inkyvoyd
  • inkyvoyd
@zscdragon , Please do not curse on this site. I'm reporting you for foul language.
anonymous
  • anonymous
i am still a lil confused
inkyvoyd
  • inkyvoyd
tanya, you want to "square" the a. The a is -2 in this case . What's negative 2 squared?
anonymous
  • anonymous
@tanyahosler , ok don't listen to that @inkyvoyd, he's all confused and doesn't know his material
anonymous
  • anonymous
please guys i need help i have to have this in by saturday
inkyvoyd
  • inkyvoyd
@tanyahosler , It's okay. I'll help you by personal message, because zsc is being distracting. Why don't you tell me what you don't understand in a message :)
anonymous
  • anonymous
ok
anonymous
  • anonymous
it isn't a test it is homework and i don't know how to put the problems in here right
inkyvoyd
  • inkyvoyd
It's alright, I'll spend time to explain it. I have a few hours on hand, and I'm willing to use them :)
anonymous
  • anonymous
ok i'm not sure how to do algebra anymore been 22 yrs since school
anonymous
  • anonymous
the next one is going to be really difficult for me to put in cause i don't know how
inkyvoyd
  • inkyvoyd
Press the equation button. It should help.
inkyvoyd
  • inkyvoyd
Other wise you could try taking a screenshot, and uploading it.
anonymous
  • anonymous
ok it is in my textbook
anonymous
  • anonymous
but i wanna get this one done
inkyvoyd
  • inkyvoyd
Hm. Try using the equation button. Tell me if you have trouble.
anonymous
  • anonymous
i don't know how to enter it in there
inkyvoyd
  • inkyvoyd
I see that you have gone from insulting language to stalking. I am slightly annoyed, but more so amused. I do request that if you want to publicly "embarrass" me, that you DO NOT POST HERE AND HIJACK SOMEONE'S THREAD. Please post it in chat. Thank you.
Mayah3
  • Mayah3
O_O!!!!!!!!!!!!!!!!!
inkyvoyd
  • inkyvoyd
I'm going to completely ignore you, not because I don't want to answer, but because this isn't your thread to hijack (nor is it mine). If you have a problem with me, let's fight it out in chat, instead of hijacking tanya's post.
anonymous
  • anonymous
\[\sqrt{b ^{2-4ac;b=3,a=-1,c=-2}}\]
anonymous
  • anonymous
not sure if i did that right
Mayah3
  • Mayah3
Can You Like Build A Bridge And Get Over It?
inkyvoyd
  • inkyvoyd
Oh, I know what you are trying to post. Is it \(\sqrt{b^2-4ac};b=3,a=-1,c=-2\)
Carniel
  • Carniel
@Zscdragon Stop trolling or I will report you
inkyvoyd
  • inkyvoyd
@Mayah3 , My side's open, but I don't think his is. :(
anonymous
  • anonymous
@Carniel everything I said is based on reason, please re-read that a few times
anonymous
  • anonymous
yes that is it inkyvoyd
inkyvoyd
  • inkyvoyd
Okay @tanyahosler . Put in what you are given for the letters. \(\sqrt{b^2-4ac}\) a=-1, b=-2, and c=3
inkyvoyd
  • inkyvoyd
@zscdragon , Please don't use this thread to insult me. Please insult me in chat. You are being incredibly rude and disruptive to the OP.
Carniel
  • Carniel
Again your getting out of hand.
anonymous
  • anonymous
b = 3, a=-1, c= -2
inkyvoyd
  • inkyvoyd
a=-1, b=-2, and c=3 Put (-1) for all the a's you see. Like this. \(\sqrt{b^2-4(-1)c}\) That make sense to you?
anonymous
  • anonymous
@inkyvoyd i never insulted you. all i write are facts and truths, nothing less, nothing more. u dont like it, dont read it ;)
anonymous
  • anonymous
yes
inkyvoyd
  • inkyvoyd
Now, try the same for b.
inkyvoyd
  • inkyvoyd
\(\sqrt{b^2-4(-1)c}\) b=-2 here. Remember, just put the negative 2 in parenthesis, and square it. ignore the square root for now, and just type in what you get without the square root. Try using "Draw" if you have to.
anonymous
  • anonymous
9
Mayah3
  • Mayah3
can he just shut up?
inkyvoyd
  • inkyvoyd
@zscdragon , I'd be happy to answer any of your comments if you post them in the appropriate math chat. What you are discussing does not pertain to what Tanya is trying to learn about, and thus is going to be ignored completely by me. Again, post it in chat, and I will answer. This is the last time I will reply to you on this thread because you are not being productive. Thank you.
Carniel
  • Carniel
Your posting in a OQ he is trying to answer. Anything else out of you and I will report you
anonymous
  • anonymous
|dw:1343280511266:dw|
inkyvoyd
  • inkyvoyd
Yes. But put the "a" and "b" in :)
inkyvoyd
  • inkyvoyd
|dw:1343280648000:dw|
Mayah3
  • Mayah3
Dude ! Shut Up Okay? Dang. No One Cares About Your Comments. You're Making A Fool Out Of Yourself -___-
anonymous
  • anonymous
i'm just trying to get help so i understand and thats all dang
Carniel
  • Carniel
Im done trying to negotiate im reporting
inkyvoyd
  • inkyvoyd
@tanyahosler , Mayah was not talking to you :)
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
leave me out of your little battle here so he is helping me i don't care who went where as long as they are explaining it to me so i can get the help i need
Mayah3
  • Mayah3
Ohh You've Just Been Told
inkyvoyd
  • inkyvoyd
\(\sqrt{ (-2)^2-4(-1)(3)}\)
inkyvoyd
  • inkyvoyd
See? All I did was replace a, b, and c, with what they were as numbers :)
anonymous
  • anonymous
the competition going on in helping is actually getting in the way of helping.
inkyvoyd
  • inkyvoyd
There actually is no competition, @panlac01 . zsc stopped helping her a long time ago. I switched to messaging her because he was harassing us too badly, and it was getting distracting. We are almost done with a third problem.
anonymous
  • anonymous
is she looking for an answer? because Khan academy would be better off for her to get her quick lessons.
anonymous
  • anonymous
no just help
anonymous
  • anonymous
k
anonymous
  • anonymous
do you go over your lectures and textbook?
inkyvoyd
  • inkyvoyd
@panlac01 , a lot of the original posts of zsc got deleted, so it might not make much sense. We are fine though, just finishing a problem.
anonymous
  • anonymous
yes but i got confused
anonymous
  • anonymous
ok i understand it a lil bit
inkyvoyd
  • inkyvoyd
\(\sqrt{ (-2)^2-4(-1)(3)}\) So, just evaluate straight through. Try it yourself once, tell me what you get...
anonymous
  • anonymous
what level of algebra are you tackling? because the problems being posted are rather easy so long as your fundamentals are solid. practice 3-5 hours a day on top of your lessons. if you think you're lagging, seek the help of your professor. some textbooks are pretty helpful like Practical Algebra a self-teaching guide by Peter Selby et al.
anonymous
  • anonymous
9
anonymous
  • anonymous
intermediate algebra
anonymous
  • anonymous
good luck. go over all your notes and examples provided by your professor and specially the textbook.
inkyvoyd
  • inkyvoyd
@panlac01 , can you help her out if she has anymore questions? I just finished the problem, but I must go to sleep now.
anonymous
  • anonymous
she will be fine.
anonymous
  • anonymous
i get confused on story problems and that is what my other 2 is would anyone like to help me on these
anonymous
  • anonymous
check the textbook that I mention. it has a good lesson for you to tackle word problems in math. majority of the keywords are discussed in details
anonymous
  • anonymous
it is less than 15 bucks in barnes and noble or even cheaper if you bought it online as used
anonymous
  • anonymous
ok i understand that part but it is telling me to find the amount of aspirin to give a 10 yr old of and adult dosage of 325 milligrams it confuses me
anonymous
  • anonymous
ok i will check that book out but i got to figure these out before saturday
anonymous
  • anonymous
in pharmacology, the adult dosage is always 1.5 or twice the pediatric's
anonymous
  • anonymous
that's the rule of thumb. but there are factors to consider, such as (BMI) or weight of the person, age, and gender
anonymous
  • anonymous
so half of that then right
anonymous
  • anonymous
it only says the age not the weight or the gender
anonymous
  • anonymous
my question is Find the amount of aspirin to give a child of age 10 if the usual adult dosage is 325 milligrams
anonymous
  • anonymous
so i'm confused
anonymous
  • anonymous
try half that amount.

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