i have a problems with my algebra homework

- anonymous

i have a problems with my algebra homework

- katieb

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- inkyvoyd

Okay, post it here :)

- anonymous

okay.
now post your problem here.

- anonymous

take you time baby, relax ;)

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## More answers

- Hero

It's Yao Ming!

- anonymous

it is 4x to the 4th power - 7x to the 3rd power - 12x to the 4th power +6x to the 3rd power

- inkyvoyd

\(4x^4-7x^3-12x^4+6x^3\)?

- anonymous

yes

- inkyvoyd

what you ned to do is combine like terms. Let me rewrite it a little for you
\(4x^4-12x^4-7x^3+6x^3\)

- inkyvoyd

@zscdragon , please read the code of conduct.
http://openstudy.com/code-of-conduct
We are here to help people, not give them the answers...

- inkyvoyd

By the way, my post lagged, so somehow it came out after @zscdragon 's did. But, essentially, we did the same thing.

- inkyvoyd

Actually because my internet is being slow. And I was serious about giving the answers. We are here to teach, not to cheat.

- inkyvoyd

More importantly, @tanyahosler , do you understand?

- inkyvoyd

I mean the problem xD

- anonymous

what about helping me with this one -5a to the 2nd power; a=-2 can someone help me thru this one

- anonymous

yeah i got it i understand how they got it

- inkyvoyd

replace the a with a negative 2

- inkyvoyd

Right now you have
\(-5a^2\), put in a -2 (with parenthesis!) inside, and tell me what you get

- anonymous

3

- inkyvoyd

Did you read
http://openstudy.com/code-of-conduct
@zscdragon ?
We are not supposed to nor allowed to just give answers like that.

- anonymous

3 squared

- inkyvoyd

@tanyahosler , how did you get that answer?

- anonymous

subtracted it

- anonymous

was i right

- inkyvoyd

No :( Uh, let me show you what I meant

- anonymous

ok

- inkyvoyd

So, we have \(-5a^2\)
instead of \(a\), we want (-2). So just put it in.
\(-5*(-2)^2\)
Exponents first
Can you try to do the rest?

- anonymous

so 10squared

- inkyvoyd

No - square what's inside the parenthesis

- anonymous

ok i'm lost

- inkyvoyd

Exponents are before multiplcation and division, always!

- anonymous

i'm lost

- anonymous

@tanyahosler look relax, everything's fine, just look at what I'll say

- inkyvoyd

Here, should look like this
\(-5*(\text{ }(-2)^2\text{ })\)

- anonymous

\[-5 * a^2\] is the equation, now what if you replace 'a' by -2

- inkyvoyd

@zscdragon , Please do not curse on this site. I'm reporting you for foul language.

- anonymous

i am still a lil confused

- inkyvoyd

tanya, you want to "square" the a. The a is -2 in this case . What's negative 2 squared?

- anonymous

@tanyahosler , ok don't listen to that @inkyvoyd, he's all confused and doesn't know his material

- anonymous

please guys i need help i have to have this in by saturday

- inkyvoyd

@tanyahosler , It's okay. I'll help you by personal message, because zsc is being distracting. Why don't you tell me what you don't understand in a message :)

- anonymous

ok

- anonymous

it isn't a test it is homework and i don't know how to put the problems in here right

- inkyvoyd

It's alright, I'll spend time to explain it. I have a few hours on hand, and I'm willing to use them :)

- anonymous

ok i'm not sure how to do algebra anymore been 22 yrs since school

- anonymous

the next one is going to be really difficult for me to put in cause i don't know how

- inkyvoyd

Press the equation button. It should help.

- inkyvoyd

Other wise you could try taking a screenshot, and uploading it.

- anonymous

ok it is in my textbook

- anonymous

but i wanna get this one done

- inkyvoyd

Hm. Try using the equation button. Tell me if you have trouble.

- anonymous

i don't know how to enter it in there

- inkyvoyd

I see that you have gone from insulting language to stalking. I am slightly annoyed, but more so amused. I do request that if you want to publicly "embarrass" me, that you DO NOT POST HERE AND HIJACK SOMEONE'S THREAD. Please post it in chat. Thank you.

- Mayah3

O_O!!!!!!!!!!!!!!!!!

- inkyvoyd

I'm going to completely ignore you, not because I don't want to answer, but because this isn't your thread to hijack (nor is it mine). If you have a problem with me, let's fight it out in chat, instead of hijacking tanya's post.

- anonymous

\[\sqrt{b ^{2-4ac;b=3,a=-1,c=-2}}\]

- anonymous

not sure if i did that right

- Mayah3

Can You Like Build A Bridge And Get Over It?

- inkyvoyd

Oh, I know what you are trying to post. Is it
\(\sqrt{b^2-4ac};b=3,a=-1,c=-2\)

- Carniel

@Zscdragon Stop trolling or I will report you

- inkyvoyd

@Mayah3 , My side's open, but I don't think his is. :(

- anonymous

@Carniel everything I said is based on reason, please re-read that a few times

- anonymous

yes that is it inkyvoyd

- inkyvoyd

Okay @tanyahosler . Put in what you are given for the letters.
\(\sqrt{b^2-4ac}\) a=-1, b=-2, and c=3

- inkyvoyd

@zscdragon , Please don't use this thread to insult me. Please insult me in chat. You are being incredibly rude and disruptive to the OP.

- Carniel

Again your getting out of hand.

- anonymous

b = 3, a=-1, c= -2

- inkyvoyd

a=-1, b=-2, and c=3
Put (-1) for all the a's you see. Like this.
\(\sqrt{b^2-4(-1)c}\)
That make sense to you?

- anonymous

@inkyvoyd i never insulted you. all i write are facts and truths, nothing less, nothing more. u dont like it, dont read it ;)

- anonymous

yes

- inkyvoyd

Now, try the same for b.

- inkyvoyd

\(\sqrt{b^2-4(-1)c}\)
b=-2 here. Remember, just put the negative 2 in parenthesis, and square it. ignore the square root for now, and just type in what you get without the square root. Try using "Draw" if you have to.

- anonymous

9

- Mayah3

can he just shut up?

- inkyvoyd

@zscdragon , I'd be happy to answer any of your comments if you post them in the appropriate math chat. What you are discussing does not pertain to what Tanya is trying to learn about, and thus is going to be ignored completely by me. Again, post it in chat, and I will answer. This is the last time I will reply to you on this thread because you are not being productive. Thank you.

- Carniel

Your posting in a OQ he is trying to answer. Anything else out of you and I will report you

- anonymous

|dw:1343280511266:dw|

- inkyvoyd

Yes. But put the "a" and "b" in :)

- inkyvoyd

|dw:1343280648000:dw|

- Mayah3

Dude ! Shut Up Okay? Dang. No One Cares About Your Comments. You're Making A Fool Out Of Yourself -___-

- anonymous

i'm just trying to get help so i understand and thats all dang

- Carniel

Im done trying to negotiate im reporting

- inkyvoyd

@tanyahosler , Mayah was not talking to you :)

- anonymous

oh ok

- anonymous

leave me out of your little battle here so he is helping me i don't care who went where as long as they are explaining it to me so i can get the help i need

- Mayah3

Ohh You've Just Been Told

- inkyvoyd

\(\sqrt{ (-2)^2-4(-1)(3)}\)

- inkyvoyd

See? All I did was replace a, b, and c, with what they were as numbers :)

- anonymous

the competition going on in helping is actually getting in the way of helping.

- inkyvoyd

There actually is no competition, @panlac01 . zsc stopped helping her a long time ago. I switched to messaging her because he was harassing us too badly, and it was getting distracting. We are almost done with a third problem.

- anonymous

is she looking for an answer? because Khan academy would be better off for her to get her quick lessons.

- anonymous

no just help

- anonymous

k

- anonymous

do you go over your lectures and textbook?

- inkyvoyd

@panlac01 , a lot of the original posts of zsc got deleted, so it might not make much sense. We are fine though, just finishing a problem.

- anonymous

yes but i got confused

- anonymous

ok i understand it a lil bit

- inkyvoyd

\(\sqrt{ (-2)^2-4(-1)(3)}\)
So, just evaluate straight through. Try it yourself once, tell me what you get...

- anonymous

what level of algebra are you tackling? because the problems being posted are rather easy so long as your fundamentals are solid. practice 3-5 hours a day on top of your lessons. if you think you're lagging, seek the help of your professor. some textbooks are pretty helpful like Practical Algebra a self-teaching guide by Peter Selby et al.

- anonymous

9

- anonymous

intermediate algebra

- anonymous

good luck. go over all your notes and examples provided by your professor and specially the textbook.

- inkyvoyd

@panlac01 , can you help her out if she has anymore questions? I just finished the problem, but I must go to sleep now.

- anonymous

she will be fine.

- anonymous

i get confused on story problems and that is what my other 2 is would anyone like to help me on these

- anonymous

check the textbook that I mention. it has a good lesson for you to tackle word problems in math. majority of the keywords are discussed in details

- anonymous

it is less than 15 bucks in barnes and noble or even cheaper if you bought it online as used

- anonymous

ok i understand that part but it is telling me to find the amount of aspirin to give a 10 yr old of and adult dosage of 325 milligrams it confuses me

- anonymous

ok i will check that book out but i got to figure these out before saturday

- anonymous

in pharmacology, the adult dosage is always 1.5 or twice the pediatric's

- anonymous

that's the rule of thumb. but there are factors to consider, such as (BMI) or weight of the person, age, and gender

- anonymous

so half of that then right

- anonymous

it only says the age not the weight or the gender

- anonymous

my question is Find the amount of aspirin to give a child of age 10 if the usual adult dosage is 325 milligrams

- anonymous

so i'm confused

- anonymous

try half that amount.

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