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## Deathfish Group Title What is the expression for exact value of pi - using infinite series? 2 years ago 2 years ago

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1. Spacelimbus Group Title

Are you allowed to use any series?

2. Deathfish Group Title

any series will do

3. Spacelimbus Group Title

then I recommend using the series for tan^(-1)x, because I know that this series approaches for very large x the value pi / 2, so you can just take a multiply (2 times) of that.

4. Spacelimbus Group Title

but that's only my first intuition and maybe it doesn't answer that problem rigorously

5. Spacelimbus Group Title

$\lim_{x \to \infty} \tan^{-1} x = \frac{\pi}{2}$ $\lim_{x \to \infty} 2 \tan^{-1}x = 2 \sum_{n=1}^\infty \frac{(-1)^{n+1}}{2n-1}x^{2n+1}$

6. Spacelimbus Group Title

$\large \lim_{x \to \infty} 2 \tan^{-1}x =\lim_{x \to \infty}\ 2 \sum_{n=1}^\infty \frac{(-1)^{n+1}}{2n-1}x^{2n+1}$ Shouldn't forget to carry out the limit

7. Neemo Group Title

$\sum_{n=0}^{+ \infty }\frac{(-1)^n}{2n+1}=\frac{ \pi}{4}$