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cerichards

how do I find the sin of a triangle

  • one year ago
  • one year ago

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  1. ParthKohli
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    I must correct it to '\(\sin\) of an angle'.

    • one year ago
  2. ParthKohli
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    You find the opposite side of that angle, and then divide that by the hypotenuse in the given triangle.

    • one year ago
  3. ParthKohli
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    And that, ma'am, is the way to find \(\sin\) given an angle.

    • one year ago
  4. candyfloss94
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    |dw:1343316228890:dw| just to make you feel easier ;)

    • one year ago
  5. cerichards
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    |dw:1343316381359:dw|

    • one year ago
  6. ParthKohli
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    What do you have to find the \(\sin\) of?

    • one year ago
  7. cerichards
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    Sin of V

    • one year ago
  8. ParthKohli
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    What is the side opposite to \(\angle V\)?

    • one year ago
  9. cerichards
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    w

    • one year ago
  10. ParthKohli
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    What is the length given?

    • one year ago
  11. cerichards
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    72

    • one year ago
  12. ParthKohli
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    Actually, 72 is not opposite to V. |dw:1343316700534:dw|

    • one year ago
  13. cerichards
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    oh my bad.

    • one year ago
  14. ParthKohli
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    Also, hypotenuse is the longest side. Note that the thing I told you applies only for right triangles.

    • one year ago
  15. cerichards
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    okk ParthKohli

    • one year ago
  16. dpflan
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    This is a useful mnemonic to remember fundamental trigonometric concepts. Classic: SOH CAH TAO Sin = Opposite side length / Hypotenuse side length Cosine = Adjacent side length / Hypotenuse side length Tangent = Opposite side length / Adjacent side length

    • one year ago
  17. ParthKohli
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    Erm, it's SOH CAH TOA @dpflan

    • one year ago
  18. cerichards
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    thanks

    • one year ago
  19. cerichards
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    so would it be 21 over 75

    • one year ago
  20. ParthKohli
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    Yeah!

    • one year ago
  21. cerichards
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    okk thanks for your help

    • one year ago
  22. dpflan
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    heh, right @ParthKohli, my mistake ;)

    • one year ago
  23. ParthKohli
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    Oops! Sorry for tagging!

    • one year ago
  24. dpflan
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    Edited: Classic: SOH CAH TOA Sin = Opposite side length / Hypotenuse side length Cosine = Adjacent side length / Hypotenuse side length Tangent = Opposite side length / Adjacent side length

    • one year ago
  25. cerichards
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    so would cosX be 72/75

    • one year ago
  26. ParthKohli
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    Um, no. \[\cos = {{\text{adjacent} \over \text{hypotenuse}} \Longrightarrow \cos X = ? } \]

    • one year ago
  27. ParthKohli
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    Adjacent side is \(21\). Hypotenuse is the longest side i.e \(75\).

    • one year ago
  28. cerichards
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    OK AND TAN X WOULD BE 21/72

    • one year ago
  29. ParthKohli
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    Nope.

    • one year ago
  30. ParthKohli
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    tan = opposite/adjacent

    • one year ago
  31. ali110
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    sin theta= perpendicular/hypatenus

    • one year ago
  32. cerichards
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    @ali110 thanks

    • one year ago
  33. ali110
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    Some people have curly brown hair,they paint black some=sine people have=perpendicular(from people)/hypatenus(from have) so sine=perpendicular/hypatanus curly=cosine brown hair=base(from brown)/hypataneus(from hair) so cosine=base/hypatenus they=tan paint black=perpendicular(from paint)/base(from black) so tan=perpendicular/base whole trignometry in just in line!!!!!!!!!! hahahahaahaha @cerichards

    • one year ago
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