cerichards
how do I find the sin of a triangle
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ParthKohli
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I must correct it to '\(\sin\) of an angle'.
ParthKohli
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You find the opposite side of that angle, and then divide that by the hypotenuse in the given triangle.
ParthKohli
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And that, ma'am, is the way to find \(\sin\) given an angle.
candyfloss94
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|dw:1343316228890:dw|
just to make you feel easier ;)
cerichards
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|dw:1343316381359:dw|
ParthKohli
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What do you have to find the \(\sin\) of?
cerichards
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Sin of V
ParthKohli
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What is the side opposite to \(\angle V\)?
cerichards
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w
ParthKohli
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What is the length given?
cerichards
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72
ParthKohli
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Actually, 72 is not opposite to V.
|dw:1343316700534:dw|
cerichards
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oh my bad.
ParthKohli
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Also, hypotenuse is the longest side.
Note that the thing I told you applies only for right triangles.
cerichards
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okk ParthKohli
dpflan
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This is a useful mnemonic to remember fundamental trigonometric concepts.
Classic: SOH CAH TAO
Sin = Opposite side length / Hypotenuse side length
Cosine = Adjacent side length / Hypotenuse side length
Tangent = Opposite side length / Adjacent side length
ParthKohli
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Erm, it's SOH CAH TOA @dpflan
cerichards
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thanks
cerichards
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so would it be 21 over 75
ParthKohli
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Yeah!
cerichards
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okk thanks for your help
dpflan
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heh, right @ParthKohli, my mistake ;)
ParthKohli
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Oops! Sorry for tagging!
dpflan
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Edited:
Classic: SOH CAH TOA
Sin = Opposite side length / Hypotenuse side length
Cosine = Adjacent side length / Hypotenuse side length
Tangent = Opposite side length / Adjacent side length
cerichards
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so would cosX be 72/75
ParthKohli
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Um, no.
\[\cos = {{\text{adjacent} \over \text{hypotenuse}} \Longrightarrow \cos X = ? } \]
ParthKohli
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Adjacent side is \(21\).
Hypotenuse is the longest side i.e \(75\).
cerichards
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OK AND TAN X WOULD BE 21/72
ParthKohli
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Nope.
ParthKohli
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tan = opposite/adjacent
ali110
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sin theta= perpendicular/hypatenus
cerichards
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@ali110 thanks
ali110
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Some people have curly brown hair,they paint black
some=sine
people have=perpendicular(from people)/hypatenus(from have)
so sine=perpendicular/hypatanus
curly=cosine
brown hair=base(from brown)/hypataneus(from hair)
so cosine=base/hypatenus
they=tan
paint black=perpendicular(from paint)/base(from black)
so tan=perpendicular/base
whole trignometry in just in line!!!!!!!!!!
hahahahaahaha
@cerichards