## cerichards 2 years ago how do I find the sin of a triangle

1. ParthKohli

I must correct it to '$$\sin$$ of an angle'.

2. ParthKohli

You find the opposite side of that angle, and then divide that by the hypotenuse in the given triangle.

3. ParthKohli

And that, ma'am, is the way to find $$\sin$$ given an angle.

4. candyfloss94

|dw:1343316228890:dw| just to make you feel easier ;)

5. cerichards

|dw:1343316381359:dw|

6. ParthKohli

What do you have to find the $$\sin$$ of?

7. cerichards

Sin of V

8. ParthKohli

What is the side opposite to $$\angle V$$?

9. cerichards

w

10. ParthKohli

What is the length given?

11. cerichards

72

12. ParthKohli

Actually, 72 is not opposite to V. |dw:1343316700534:dw|

13. cerichards

14. ParthKohli

Also, hypotenuse is the longest side. Note that the thing I told you applies only for right triangles.

15. cerichards

okk ParthKohli

16. dpflan

This is a useful mnemonic to remember fundamental trigonometric concepts. Classic: SOH CAH TAO Sin = Opposite side length / Hypotenuse side length Cosine = Adjacent side length / Hypotenuse side length Tangent = Opposite side length / Adjacent side length

17. ParthKohli

Erm, it's SOH CAH TOA @dpflan

18. cerichards

thanks

19. cerichards

so would it be 21 over 75

20. ParthKohli

Yeah!

21. cerichards

okk thanks for your help

22. dpflan

heh, right @ParthKohli, my mistake ;)

23. ParthKohli

Oops! Sorry for tagging!

24. dpflan

Edited: Classic: SOH CAH TOA Sin = Opposite side length / Hypotenuse side length Cosine = Adjacent side length / Hypotenuse side length Tangent = Opposite side length / Adjacent side length

25. cerichards

so would cosX be 72/75

26. ParthKohli

Um, no. $\cos = {{\text{adjacent} \over \text{hypotenuse}} \Longrightarrow \cos X = ? }$

27. ParthKohli

Adjacent side is $$21$$. Hypotenuse is the longest side i.e $$75$$.

28. cerichards

OK AND TAN X WOULD BE 21/72

29. ParthKohli

Nope.

30. ParthKohli

31. ali110

sin theta= perpendicular/hypatenus

32. cerichards

@ali110 thanks

33. ali110

Some people have curly brown hair,they paint black some=sine people have=perpendicular(from people)/hypatenus(from have) so sine=perpendicular/hypatanus curly=cosine brown hair=base(from brown)/hypataneus(from hair) so cosine=base/hypatenus they=tan paint black=perpendicular(from paint)/base(from black) so tan=perpendicular/base whole trignometry in just in line!!!!!!!!!! hahahahaahaha @cerichards