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cerichards

  • 3 years ago

how do I find the sin of a triangle

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  1. ParthKohli
    • 3 years ago
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    I must correct it to '\(\sin\) of an angle'.

  2. ParthKohli
    • 3 years ago
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    You find the opposite side of that angle, and then divide that by the hypotenuse in the given triangle.

  3. ParthKohli
    • 3 years ago
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    And that, ma'am, is the way to find \(\sin\) given an angle.

  4. candyfloss94
    • 3 years ago
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    |dw:1343316228890:dw| just to make you feel easier ;)

  5. cerichards
    • 3 years ago
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    |dw:1343316381359:dw|

  6. ParthKohli
    • 3 years ago
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    What do you have to find the \(\sin\) of?

  7. cerichards
    • 3 years ago
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    Sin of V

  8. ParthKohli
    • 3 years ago
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    What is the side opposite to \(\angle V\)?

  9. cerichards
    • 3 years ago
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    w

  10. ParthKohli
    • 3 years ago
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    What is the length given?

  11. cerichards
    • 3 years ago
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    72

  12. ParthKohli
    • 3 years ago
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    Actually, 72 is not opposite to V. |dw:1343316700534:dw|

  13. cerichards
    • 3 years ago
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    oh my bad.

  14. ParthKohli
    • 3 years ago
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    Also, hypotenuse is the longest side. Note that the thing I told you applies only for right triangles.

  15. cerichards
    • 3 years ago
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    okk ParthKohli

  16. dpflan
    • 3 years ago
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    This is a useful mnemonic to remember fundamental trigonometric concepts. Classic: SOH CAH TAO Sin = Opposite side length / Hypotenuse side length Cosine = Adjacent side length / Hypotenuse side length Tangent = Opposite side length / Adjacent side length

  17. ParthKohli
    • 3 years ago
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    Erm, it's SOH CAH TOA @dpflan

  18. cerichards
    • 3 years ago
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    thanks

  19. cerichards
    • 3 years ago
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    so would it be 21 over 75

  20. ParthKohli
    • 3 years ago
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    Yeah!

  21. cerichards
    • 3 years ago
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    okk thanks for your help

  22. dpflan
    • 3 years ago
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    heh, right @ParthKohli, my mistake ;)

  23. ParthKohli
    • 3 years ago
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    Oops! Sorry for tagging!

  24. dpflan
    • 3 years ago
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    Edited: Classic: SOH CAH TOA Sin = Opposite side length / Hypotenuse side length Cosine = Adjacent side length / Hypotenuse side length Tangent = Opposite side length / Adjacent side length

  25. cerichards
    • 3 years ago
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    so would cosX be 72/75

  26. ParthKohli
    • 3 years ago
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    Um, no. \[\cos = {{\text{adjacent} \over \text{hypotenuse}} \Longrightarrow \cos X = ? } \]

  27. ParthKohli
    • 3 years ago
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    Adjacent side is \(21\). Hypotenuse is the longest side i.e \(75\).

  28. cerichards
    • 3 years ago
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    OK AND TAN X WOULD BE 21/72

  29. ParthKohli
    • 3 years ago
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    Nope.

  30. ParthKohli
    • 3 years ago
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    tan = opposite/adjacent

  31. ali110
    • 3 years ago
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    sin theta= perpendicular/hypatenus

  32. cerichards
    • 3 years ago
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    @ali110 thanks

  33. ali110
    • 3 years ago
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    Some people have curly brown hair,they paint black some=sine people have=perpendicular(from people)/hypatenus(from have) so sine=perpendicular/hypatanus curly=cosine brown hair=base(from brown)/hypataneus(from hair) so cosine=base/hypatenus they=tan paint black=perpendicular(from paint)/base(from black) so tan=perpendicular/base whole trignometry in just in line!!!!!!!!!! hahahahaahaha @cerichards

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