Desireegb
Help? I don't know what I'm doing wrong...
Use the table for sine values, and find x to the nearest tenth.
(My Answer)
x (Approximately) = ? 1.0
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Desireegb
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aroub
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sin(48)=10/x
aroub
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Is this what you did?
Desireegb
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oh wait, i think i may know now, heres my work
sin 48* = x/10
sin 48* = 0.7431
0.7431 = x/10
x = 10(0.7431)
0.1
aroub
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No, what is sin?
lawrenceh123
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sin is opposite over hypotenuse and could one of you help me with my question please
Desireegb
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i could try sry i was away from the computor when u asked what sin was
Desireegb
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i hav instructions for the lesson and the definition they gave me for Sine ratio was: with respect to an acute angle of a right triangle, the ratio formed by the side opposite the acute angle over the hypotenuse.
Desireegb
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i looked over ur problem and i dont really understand what to do on that either sorry :(
aroub
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Okay, sin is opposite over hypotenuse. Sin 48= opposite/ hypotenuse. What's the opposite of sin 48?
Desireegb
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10 right?
aroub
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Yup!
aroub
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This is your mistake.
Desireegb
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so that would be
sin 48* = 10/x
aroub
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Exactly :)
Desireegb
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okay so the problem would be:
sin 48* = 10/x
sin 48* = 0.7431
0.7431 = 10/x
10 = x(0.7431)
and then i divide?
aroub
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Yes
Desireegb
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k i got 0.07431 so that goes to 0.1 when rounded right?
aroub
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How did you get that? O.o!
Desireegb
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i divided 0.07431 by 10 and i got 0.07431 and i rounded to the nearest tenth and since 7 is a high number i rounded it to 0.1
aroub
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yepp :D
Desireegb
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awesome lol