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SkykhanFalcon
 2 years ago
Best ResponseYou've already chosen the best response.02x^35=u 6x^2dx = du> integral(sqrt(u)*du/2 =u^(3/2)/2 + constant

SkykhanFalcon
 2 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}1/\sqrt{u}\]

hiralpatel121
 2 years ago
Best ResponseYou've already chosen the best response.0Shouldn't it be u^(3/2)/3+C?

SkykhanFalcon
 2 years ago
Best ResponseYou've already chosen the best response.0yes yes my mistake :/

Valpey
 2 years ago
Best ResponseYou've already chosen the best response.0You can \[let\ u = 2x^35;\ du=6x^2\] \[\int3x^2\sqrt{2x^35} = \frac{1}{2}\int\sqrt{u}\ du\]

SkykhanFalcon
 2 years ago
Best ResponseYou've already chosen the best response.0(u^3/2)*2/3*1/2 so (u^3/2)*1/3

Valpey
 2 years ago
Best ResponseYou've already chosen the best response.0\[=\frac{1}{3}u^{\frac{3}{2}}+C\]
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