Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

hiralpatel121

  • 3 years ago

I need help with an attached problem please.

  • This Question is Closed
  1. hiralpatel121
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

  2. SkykhanFalcon
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    2x^3-5=u 6x^2dx = du-----> integral(sqrt(u)*du/2 =u^(3/2)/2 + constant

  3. SkykhanFalcon
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\int\limits_{}^{}1/\sqrt{u}\]

  4. hiralpatel121
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Shouldn't it be u^(3/2)/3+C?

  5. SkykhanFalcon
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes yes my mistake :/

  6. Valpey
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You can \[let\ u = 2x^3-5;\ du=6x^2\] \[\int3x^2\sqrt{2x^3-5} = \frac{1}{2}\int\sqrt{u}\ du\]

  7. SkykhanFalcon
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (u^3/2)*2/3*1/2 so (u^3/2)*1/3

  8. Valpey
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[=\frac{1}{3}u^{\frac{3}{2}}+C\]

  9. hiralpatel121
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ugh I got:

  10. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy