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SkykhanFalconBest ResponseYou've already chosen the best response.0
2x^35=u 6x^2dx = du> integral(sqrt(u)*du/2 =u^(3/2)/2 + constant
 one year ago

SkykhanFalconBest ResponseYou've already chosen the best response.0
\[\int\limits_{}^{}1/\sqrt{u}\]
 one year ago

hiralpatel121Best ResponseYou've already chosen the best response.0
Shouldn't it be u^(3/2)/3+C?
 one year ago

SkykhanFalconBest ResponseYou've already chosen the best response.0
yes yes my mistake :/
 one year ago

ValpeyBest ResponseYou've already chosen the best response.0
You can \[let\ u = 2x^35;\ du=6x^2\] \[\int3x^2\sqrt{2x^35} = \frac{1}{2}\int\sqrt{u}\ du\]
 one year ago

SkykhanFalconBest ResponseYou've already chosen the best response.0
(u^3/2)*2/3*1/2 so (u^3/2)*1/3
 one year ago

ValpeyBest ResponseYou've already chosen the best response.0
\[=\frac{1}{3}u^{\frac{3}{2}}+C\]
 one year ago
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