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Enter in standard form the equation of the line passing through the given point and having the given slope. B(2, - 5), m = -2/3

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Use the short formula.. y - y1 = m(x-x1) y - (-5) = -2/3 (x - 2)
y+5 = 2/3x - 4/3

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Other answers:

Now bring that into standard form.
2/3 x - y = i am stuck
make y the subject first.
y = 2/3 x -4/3 - 5
y = -2/3 - 5
not sure what answer is then
|dw:1343322191844:dw|Can you solve from here?
not sure sorry
What is it that you do not understand so i can help you out?
Lets start this over. Basically you have got your slope and your b, so you are pretty much set up.
he said y = 2x/3 - 19/3 you cant substract that correct
so it would be 2x/3 - y = -19/3
y - y1 = m(x-x1) y - (-5) = -2/3 (x - 2) y+5=-2/3x + 4/3
okay i see that so far
then i understand the 2/3x - y = 4/3 - 5 after this is where i get confused
From there, you must but it into standard form, having all the x's and y's on one side. Subtract y, and then subtract 4/3. Giving you 11/3=-2/3x-y
2/3x-y = 11/3
Yes. Only dont forget the (-) sign in front of the 2/3
okay thanks
np :)
in my problem it will not let me have / as an option
Okay, then you can get rid of the fractions by multiply each side by 3.
Giving you -2x-3y=11

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