anonymous
  • anonymous
Enter in standard form the equation of the line passing through the given point and having the given slope. B(2, - 5), m = -2/3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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saifoo.khan
  • saifoo.khan
Use the short formula.. y - y1 = m(x-x1) y - (-5) = -2/3 (x - 2)
saifoo.khan
  • saifoo.khan
Solve.
anonymous
  • anonymous
y+5 = 2/3x - 4/3

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saifoo.khan
  • saifoo.khan
Correct.
saifoo.khan
  • saifoo.khan
Now bring that into standard form.
anonymous
  • anonymous
2/3 x - y = i am stuck
saifoo.khan
  • saifoo.khan
make y the subject first.
saifoo.khan
  • saifoo.khan
y = 2/3 x -4/3 - 5
anonymous
  • anonymous
y = -2/3 - 5
saifoo.khan
  • saifoo.khan
wrong.
anonymous
  • anonymous
not sure what answer is then
saifoo.khan
  • saifoo.khan
|dw:1343322191844:dw|Can you solve from here?
anonymous
  • anonymous
not sure sorry
anonymous
  • anonymous
What is it that you do not understand so i can help you out?
anonymous
  • anonymous
Lets start this over. Basically you have got your slope and your b, so you are pretty much set up.
anonymous
  • anonymous
he said y = 2x/3 - 19/3 you cant substract that correct
anonymous
  • anonymous
so it would be 2x/3 - y = -19/3
anonymous
  • anonymous
y - y1 = m(x-x1) y - (-5) = -2/3 (x - 2) y+5=-2/3x + 4/3
anonymous
  • anonymous
okay i see that so far
anonymous
  • anonymous
then i understand the 2/3x - y = 4/3 - 5 after this is where i get confused
anonymous
  • anonymous
From there, you must but it into standard form, having all the x's and y's on one side. Subtract y, and then subtract 4/3. Giving you 11/3=-2/3x-y
anonymous
  • anonymous
2/3x-y = 11/3
anonymous
  • anonymous
Yes. Only dont forget the (-) sign in front of the 2/3
anonymous
  • anonymous
okay thanks
anonymous
  • anonymous
np :)
anonymous
  • anonymous
in my problem it will not let me have / as an option
anonymous
  • anonymous
Okay, then you can get rid of the fractions by multiply each side by 3.
anonymous
  • anonymous
Giving you -2x-3y=11
anonymous
  • anonymous
thanks
anonymous
  • anonymous
Sure.

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