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PhoenixFire Group Title

Prove that if n-2 is divisible by 4 then n^2 - 4 is divisible by 16.

  • 2 years ago
  • 2 years ago

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  1. PhoenixFire Group Title
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    For a given integer.

    • 2 years ago
  2. carl51 Group Title
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    Say that n is 26 so 26-2=24 and 24 is divisible by 4. 26x 2-4=52-4=48 and 48 is divisible by 16

    • 2 years ago
  3. zzr0ck3r Group Title
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    hehe I wish, sec

    • 2 years ago
  4. zzr0ck3r Group Title
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    I would do contradiction

    • 2 years ago
  5. PhoenixFire Group Title
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    \[\forall{n}\in \mathbb{Z} : 4|n-2 \rightarrow 16|n^2-4\] I believe that's the correct notation.

    • 2 years ago
  6. zzr0ck3r Group Title
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    yeah

    • 2 years ago
  7. zzr0ck3r Group Title
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    do you need to show for all n?

    • 2 years ago
  8. zzr0ck3r Group Title
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    nm i c

    • 2 years ago
  9. PhoenixFire Group Title
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    I need to show the proof.

    • 2 years ago
  10. zzr0ck3r Group Title
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    ok assume n-2= 4k for some k in Z then n = 4k+2 then n^2-4 = (4k+2)^2 - 4 = 16k^2 + 16k +4-4 = 16(k^2+k) since k^2+k is in Z 16|n^2-4

    • 2 years ago
  11. zzr0ck3r Group Title
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    sorry direct proof was fast I think

    • 2 years ago
  12. PhoenixFire Group Title
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    Yeah, they wanted Direct Proof. so since n^2 - 4 = 16k the (k^2+k) in 16(k^2+k) doesn't matter, the rest match. that's what was confusing me.

    • 2 years ago
  13. zzr0ck3r Group Title
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    yeah 16 | (16* any integer)

    • 2 years ago
  14. PhoenixFire Group Title
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    Thanks for the help.

    • 2 years ago
  15. zzr0ck3r Group Title
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    np

    • 2 years ago
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