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anonymous
 4 years ago
f point C is the midpoint of /AB , what is the coordinate of point B?
(–9, 2)
(–3, 1)
(0, –7)
(–1, –8)
anonymous
 4 years ago
f point C is the midpoint of /AB , what is the coordinate of point B? (–9, 2) (–3, 1) (0, –7) (–1, –8)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0read pages 2 and on  http://finedrafts.com/files/Larson%20PreCal%208th/Larson%20Precal%20CH1.pdf

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0midpoint formula is in page 5

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0did you also read about the distance?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\large Midpoint(x,y) = (\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})\] Here: \((x,y) = (3, 5)\) , \((x_1, y_1) = (6, 3)\) and we have to find \(x_2\) and \(y_2\) \[\large Midpoint(3,5) = (\frac{6 + x_2}{2}, \frac{3 + y_2}{2})\] Try to equate x coordinate of Left side with the right side.. Similary do for y coordinates on both the sides.. and find \(x_2\) and \(y_2\)...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so is should be A or c

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for x, what do you need to add to 6 so when you divide it by 2, you get 3? the same technique for y.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Simply solve this: \[\frac{6 + x_2}{2} = 3\] Multiply 2 both the sides and then add 6 both the sides and tell me what are you getting for \(x_2\)..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What is this @panlac01

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0asking her why she's choosing A as an answer.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0indirectly, of course

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0when you get a chance, Diana, please review http://www.purplemath.com/modules/negative.htm
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