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viniterranova
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Find a vector perpendicular to Oy axis. Knowing that v*v1=8 and v*v2=3. v1=(3,1,2) and v2=(1,1,1)
 one year ago
 one year ago
viniterranova Group Title
Find a vector perpendicular to Oy axis. Knowing that v*v1=8 and v*v2=3. v1=(3,1,2) and v2=(1,1,1)
 one year ago
 one year ago

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Spacelimbus Group TitleBest ResponseYou've already chosen the best response.1
A bit confused by this question, is this what you have written above the dot product? the xaxis is perpendicular to the yaxis, also the zaxis
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.2
...or any other vector in the without a y component
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.2
oh wait, it's supposed to be perpendicular to which axis? @viniterranova please explain so we can help you
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.0
Determine the vector v, orthogonal to the axis Oy.
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.0
where v*v1=8 and v*v2=3
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.2
you did not really clarify you just repeated yourself are these dot products?
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.0
Yes these are dot products
 one year ago

Spacelimbus Group TitleBest ResponseYou've already chosen the best response.1
then the y component can be left away, will result in a system of equations.
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.0
Here it´s a shot from the book where i taken the question.
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.2
so we have\[\vec v\cdot\vec v_1=8\]\[\vec v\cdot\vec v_2=3\]where\[\vec v_1=\langle3,1,2\rangle\]\[\vec v_2=\langle1,1,1\rangle\]and if it is perpendicular to the y axis we have that\[\vec v\cdot\langle0,1,0\rangle=0\]let\[\vec v=\langle x,y,z\rangle\] and we get the system of equations spacelimbus was referring to
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.0
And, what´s more?
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.2
\[\vec v\cdot\vec v_1=3x+y2z=8\]\[\vec v\cdot\vec v_2=x+y+z=3\]\[\vec v\cdot\langle0,1,0\rangle=y=0\]
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.0
So, in this case y = zero? That ´s right? So, i just plug 0 in the equation in order to slove the system? Am i right?
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.0
In this i got a following system 3x2z=8 and x+z= 3 and solving in function of z i got z=x3 and so, i have reached x=2. Am i right?
 one year ago

Spacelimbus Group TitleBest ResponseYou've already chosen the best response.1
x=2, z=1, is what I got if you want to compare.
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.0
Yes, that´s for sure. x=2 and z=1. Thanks guys.
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.0
So the answer to the question is w=(2,0,1)
 one year ago

Spacelimbus Group TitleBest ResponseYou've already chosen the best response.1
well in the exercise they called the vector v, so you maybe want to name him like that too, but that's not a convention, the coordinates are what's important, and you maybe want to write it in brackets, see how @TuringTest wrote the vectors.
 one year ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.0
Thanks for the help. But, i don´t know how to use the Latex yet. Thanks a lot for the help.
 one year ago
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