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anonymous
 3 years ago
Find a vector perpendicular to Oy axis. Knowing that v*v1=8 and v*v2=3. v1=(3,1,2) and v2=(1,1,1)
anonymous
 3 years ago
Find a vector perpendicular to Oy axis. Knowing that v*v1=8 and v*v2=3. v1=(3,1,2) and v2=(1,1,1)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0A bit confused by this question, is this what you have written above the dot product? the xaxis is perpendicular to the yaxis, also the zaxis

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2...or any other vector in the without a y component

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2oh wait, it's supposed to be perpendicular to which axis? @viniterranova please explain so we can help you

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Determine the vector v, orthogonal to the axis Oy.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0where v*v1=8 and v*v2=3

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2you did not really clarify you just repeated yourself are these dot products?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes these are dot products

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then the y component can be left away, will result in a system of equations.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Here it´s a shot from the book where i taken the question.

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2so we have\[\vec v\cdot\vec v_1=8\]\[\vec v\cdot\vec v_2=3\]where\[\vec v_1=\langle3,1,2\rangle\]\[\vec v_2=\langle1,1,1\rangle\]and if it is perpendicular to the y axis we have that\[\vec v\cdot\langle0,1,0\rangle=0\]let\[\vec v=\langle x,y,z\rangle\] and we get the system of equations spacelimbus was referring to

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.2\[\vec v\cdot\vec v_1=3x+y2z=8\]\[\vec v\cdot\vec v_2=x+y+z=3\]\[\vec v\cdot\langle0,1,0\rangle=y=0\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So, in this case y = zero? That ´s right? So, i just plug 0 in the equation in order to slove the system? Am i right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0In this i got a following system 3x2z=8 and x+z= 3 and solving in function of z i got z=x3 and so, i have reached x=2. Am i right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0x=2, z=1, is what I got if you want to compare.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, that´s for sure. x=2 and z=1. Thanks guys.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So the answer to the question is w=(2,0,1)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well in the exercise they called the vector v, so you maybe want to name him like that too, but that's not a convention, the coordinates are what's important, and you maybe want to write it in brackets, see how @TuringTest wrote the vectors.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks for the help. But, i don´t know how to use the Latex yet. Thanks a lot for the help.
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