Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

viniterranova

  • 3 years ago

Find a vector perpendicular to Oy axis. Knowing that v*v1=8 and v*v2=-3. v1=(3,1,-2) and v2=(-1,1,1)

  • This Question is Closed
  1. Spacelimbus
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    A bit confused by this question, is this what you have written above the dot product? the x-axis is perpendicular to the y-axis, also the z-axis

  2. TuringTest
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    ...or any other vector in the without a y component

  3. TuringTest
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    oh wait, it's supposed to be perpendicular to which axis? @viniterranova please explain so we can help you

  4. viniterranova
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Determine the vector v, orthogonal to the axis Oy.

  5. viniterranova
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    where v*v1=8 and v*v2=-3

  6. TuringTest
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you did not really clarify you just repeated yourself are these dot products?

  7. viniterranova
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes these are dot products

  8. viniterranova
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  9. Spacelimbus
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    then the y component can be left away, will result in a system of equations.

  10. viniterranova
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Here it´s a shot from the book where i taken the question.

  11. TuringTest
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    so we have\[\vec v\cdot\vec v_1=8\]\[\vec v\cdot\vec v_2=-3\]where\[\vec v_1=\langle3,1,-2\rangle\]\[\vec v_2=\langle-1,1,1\rangle\]and if it is perpendicular to the y axis we have that\[\vec v\cdot\langle0,1,0\rangle=0\]let\[\vec v=\langle x,y,z\rangle\] and we get the system of equations spacelimbus was referring to

  12. viniterranova
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    And, what´s more?

  13. TuringTest
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \[\vec v\cdot\vec v_1=3x+y-2z=8\]\[\vec v\cdot\vec v_2=-x+y+z=-3\]\[\vec v\cdot\langle0,1,0\rangle=y=0\]

  14. viniterranova
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So, in this case y = zero? That ´s right? So, i just plug 0 in the equation in order to slove the system? Am i right?

  15. TuringTest
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    yep

  16. viniterranova
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    In this i got a following system 3x-2z=8 and -x+z= -3 and solving in function of z i got z=x-3 and so, i have reached x=2. Am i right?

  17. Spacelimbus
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    x=2, z=-1, is what I got if you want to compare.

  18. viniterranova
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes, that´s for sure. x=2 and z=-1. Thanks guys.

  19. viniterranova
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So the answer to the question is w=(2,0,-1)

  20. Spacelimbus
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    well in the exercise they called the vector v, so you maybe want to name him like that too, but that's not a convention, the coordinates are what's important, and you maybe want to write it in brackets, see how @TuringTest wrote the vectors.

  21. viniterranova
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thanks for the help. But, i don´t know how to use the Latex yet. Thanks a lot for the help.

  22. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy