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ashleyb

  • 3 years ago

how do you solve the following equation??...equation in comment box

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  1. ashleyb
    • 3 years ago
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    |dw:1343424233134:dw|

  2. jim_thompson5910
    • 3 years ago
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    is there only one variable?

  3. ashleyb
    • 3 years ago
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    yes

  4. ashleyb
    • 3 years ago
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    i represents feet ant t represents time

  5. jim_thompson5910
    • 3 years ago
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    So the equation is \[\Large t = 2\pi\sqrt{\frac{1}{32}}\] ???

  6. jim_thompson5910
    • 3 years ago
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    and that's a 1 (one)?

  7. ashleyb
    • 3 years ago
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    no its I think it an i

  8. jim_thompson5910
    • 3 years ago
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    oh an L...

  9. ashleyb
    • 3 years ago
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    yes

  10. jim_thompson5910
    • 3 years ago
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    so like this \[\Large t = 2\pi\sqrt{\frac{L}{32}}\]

  11. ashleyb
    • 3 years ago
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    yes

  12. jim_thompson5910
    • 3 years ago
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    and you want to solve for L?

  13. ashleyb
    • 3 years ago
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    no t

  14. ashleyb
    • 3 years ago
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    let me give another example

  15. jim_thompson5910
    • 3 years ago
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    oh, t is already isolated (and solved for)

  16. jim_thompson5910
    • 3 years ago
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    ok

  17. ashleyb
    • 3 years ago
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    |dw:1343424734335:dw| L represents feet and i have to solve for t...in other words the 3 represents feet

  18. jim_thompson5910
    • 3 years ago
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    So you're plugging in arbitrary values of L to find t?

  19. ashleyb
    • 3 years ago
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    correct

  20. jim_thompson5910
    • 3 years ago
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    which values do they want you to plug in?

  21. ashleyb
    • 3 years ago
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    i have to plug in 4 values...3,2,1,0

  22. jim_thompson5910
    • 3 years ago
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    I'll do one and hopefully it will makes sense enough for you to be able to do the others \[\Large t = 2\pi\sqrt{\frac{L}{32}}\] \[\Large t = 2\pi\sqrt{\frac{3}{32}} ... \ \text{Plug in L = 3}\] \[\Large t = 2\pi\sqrt{0.09375}\] \[\Large t \approx 2\pi(0.306186)\] \[\Large t \approx 2(3.14159)(0.306186)\] \[\Large t \approx (6.28318)(0.306186)\] \[\Large t \approx 1.92382\] ---------------------------------- So when \[\Large L = 3\] the value of t is approximately \[\Large t \approx 1.92382\]

  23. jim_thompson5910
    • 3 years ago
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    Hopefully it makes sense. If not, let me know.

  24. ashleyb
    • 3 years ago
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    oh that makes sense...but how do u get the answer not in decimal form...like how do solve the radical

  25. jim_thompson5910
    • 3 years ago
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    Well you can't simplify \[\Large \sqrt{\frac{3}{32}}\] too much. I guess you can say \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}}{\sqrt{32}}\] \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}}{\sqrt{16*2}}\] \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}}{\sqrt{16}*\sqrt{2}}\] \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}}{4\sqrt{2}}\] \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}*\sqrt{2}}{4\sqrt{2}*\sqrt{2}}\] \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{6}}{4*2}\] \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{6}}{8}\] ------------------------------------------------------- So \[\Large t = 2\pi\sqrt{\frac{3}{32}}\] becomes \[\Large t = 2\pi\frac{\sqrt{6}}{8}\]

  26. jim_thompson5910
    • 3 years ago
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    but in my opinion, that's not much of a simplification

  27. ashleyb
    • 3 years ago
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    okayy i understand now...thanks for your help

  28. jim_thompson5910
    • 3 years ago
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    oh you can go further to get \[\Large t = 2\pi\frac{\sqrt{6}}{8}\] \[\Large t = \frac{\pi\sqrt{6}}{4}\]

  29. jim_thompson5910
    • 3 years ago
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    you're welcome

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