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ashleyb
how do you solve the following equation??...equation in comment box
is there only one variable?
i represents feet ant t represents time
So the equation is \[\Large t = 2\pi\sqrt{\frac{1}{32}}\] ???
and that's a 1 (one)?
so like this \[\Large t = 2\pi\sqrt{\frac{L}{32}}\]
and you want to solve for L?
let me give another example
oh, t is already isolated (and solved for)
|dw:1343424734335:dw| L represents feet and i have to solve for t...in other words the 3 represents feet
So you're plugging in arbitrary values of L to find t?
which values do they want you to plug in?
i have to plug in 4 values...3,2,1,0
I'll do one and hopefully it will makes sense enough for you to be able to do the others \[\Large t = 2\pi\sqrt{\frac{L}{32}}\] \[\Large t = 2\pi\sqrt{\frac{3}{32}} ... \ \text{Plug in L = 3}\] \[\Large t = 2\pi\sqrt{0.09375}\] \[\Large t \approx 2\pi(0.306186)\] \[\Large t \approx 2(3.14159)(0.306186)\] \[\Large t \approx (6.28318)(0.306186)\] \[\Large t \approx 1.92382\] ---------------------------------- So when \[\Large L = 3\] the value of t is approximately \[\Large t \approx 1.92382\]
Hopefully it makes sense. If not, let me know.
oh that makes sense...but how do u get the answer not in decimal form...like how do solve the radical
Well you can't simplify \[\Large \sqrt{\frac{3}{32}}\] too much. I guess you can say \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}}{\sqrt{32}}\] \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}}{\sqrt{16*2}}\] \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}}{\sqrt{16}*\sqrt{2}}\] \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}}{4\sqrt{2}}\] \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}*\sqrt{2}}{4\sqrt{2}*\sqrt{2}}\] \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{6}}{4*2}\] \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{6}}{8}\] ------------------------------------------------------- So \[\Large t = 2\pi\sqrt{\frac{3}{32}}\] becomes \[\Large t = 2\pi\frac{\sqrt{6}}{8}\]
but in my opinion, that's not much of a simplification
okayy i understand now...thanks for your help
oh you can go further to get \[\Large t = 2\pi\frac{\sqrt{6}}{8}\] \[\Large t = \frac{\pi\sqrt{6}}{4}\]
you're welcome