## ashleyb 3 years ago how do you solve the following equation??...equation in comment box

1. ashleyb

|dw:1343424233134:dw|

2. jim_thompson5910

is there only one variable?

3. ashleyb

yes

4. ashleyb

i represents feet ant t represents time

5. jim_thompson5910

So the equation is $\Large t = 2\pi\sqrt{\frac{1}{32}}$ ???

6. jim_thompson5910

and that's a 1 (one)?

7. ashleyb

no its I think it an i

8. jim_thompson5910

oh an L...

9. ashleyb

yes

10. jim_thompson5910

so like this $\Large t = 2\pi\sqrt{\frac{L}{32}}$

11. ashleyb

yes

12. jim_thompson5910

and you want to solve for L?

13. ashleyb

no t

14. ashleyb

let me give another example

15. jim_thompson5910

oh, t is already isolated (and solved for)

16. jim_thompson5910

ok

17. ashleyb

|dw:1343424734335:dw| L represents feet and i have to solve for t...in other words the 3 represents feet

18. jim_thompson5910

So you're plugging in arbitrary values of L to find t?

19. ashleyb

correct

20. jim_thompson5910

which values do they want you to plug in?

21. ashleyb

i have to plug in 4 values...3,2,1,0

22. jim_thompson5910

I'll do one and hopefully it will makes sense enough for you to be able to do the others $\Large t = 2\pi\sqrt{\frac{L}{32}}$ $\Large t = 2\pi\sqrt{\frac{3}{32}} ... \ \text{Plug in L = 3}$ $\Large t = 2\pi\sqrt{0.09375}$ $\Large t \approx 2\pi(0.306186)$ $\Large t \approx 2(3.14159)(0.306186)$ $\Large t \approx (6.28318)(0.306186)$ $\Large t \approx 1.92382$ ---------------------------------- So when $\Large L = 3$ the value of t is approximately $\Large t \approx 1.92382$

23. jim_thompson5910

Hopefully it makes sense. If not, let me know.

24. ashleyb

oh that makes sense...but how do u get the answer not in decimal form...like how do solve the radical

25. jim_thompson5910

Well you can't simplify $\Large \sqrt{\frac{3}{32}}$ too much. I guess you can say $\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}}{\sqrt{32}}$ $\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}}{\sqrt{16*2}}$ $\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}}{\sqrt{16}*\sqrt{2}}$ $\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}}{4\sqrt{2}}$ $\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}*\sqrt{2}}{4\sqrt{2}*\sqrt{2}}$ $\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{6}}{4*2}$ $\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{6}}{8}$ ------------------------------------------------------- So $\Large t = 2\pi\sqrt{\frac{3}{32}}$ becomes $\Large t = 2\pi\frac{\sqrt{6}}{8}$

26. jim_thompson5910

but in my opinion, that's not much of a simplification

27. ashleyb

okayy i understand now...thanks for your help

28. jim_thompson5910

oh you can go further to get $\Large t = 2\pi\frac{\sqrt{6}}{8}$ $\Large t = \frac{\pi\sqrt{6}}{4}$

29. jim_thompson5910

you're welcome