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ashleyb Group Title

how do you solve the following equation??...equation in comment box

  • 2 years ago
  • 2 years ago

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  1. ashleyb Group Title
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    |dw:1343424233134:dw|

    • 2 years ago
  2. jim_thompson5910 Group Title
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    is there only one variable?

    • 2 years ago
  3. ashleyb Group Title
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    yes

    • 2 years ago
  4. ashleyb Group Title
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    i represents feet ant t represents time

    • 2 years ago
  5. jim_thompson5910 Group Title
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    So the equation is \[\Large t = 2\pi\sqrt{\frac{1}{32}}\] ???

    • 2 years ago
  6. jim_thompson5910 Group Title
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    and that's a 1 (one)?

    • 2 years ago
  7. ashleyb Group Title
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    no its I think it an i

    • 2 years ago
  8. jim_thompson5910 Group Title
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    oh an L...

    • 2 years ago
  9. ashleyb Group Title
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    yes

    • 2 years ago
  10. jim_thompson5910 Group Title
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    so like this \[\Large t = 2\pi\sqrt{\frac{L}{32}}\]

    • 2 years ago
  11. ashleyb Group Title
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    yes

    • 2 years ago
  12. jim_thompson5910 Group Title
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    and you want to solve for L?

    • 2 years ago
  13. ashleyb Group Title
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    no t

    • 2 years ago
  14. ashleyb Group Title
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    let me give another example

    • 2 years ago
  15. jim_thompson5910 Group Title
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    oh, t is already isolated (and solved for)

    • 2 years ago
  16. jim_thompson5910 Group Title
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    ok

    • 2 years ago
  17. ashleyb Group Title
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    |dw:1343424734335:dw| L represents feet and i have to solve for t...in other words the 3 represents feet

    • 2 years ago
  18. jim_thompson5910 Group Title
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    So you're plugging in arbitrary values of L to find t?

    • 2 years ago
  19. ashleyb Group Title
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    correct

    • 2 years ago
  20. jim_thompson5910 Group Title
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    which values do they want you to plug in?

    • 2 years ago
  21. ashleyb Group Title
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    i have to plug in 4 values...3,2,1,0

    • 2 years ago
  22. jim_thompson5910 Group Title
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    I'll do one and hopefully it will makes sense enough for you to be able to do the others \[\Large t = 2\pi\sqrt{\frac{L}{32}}\] \[\Large t = 2\pi\sqrt{\frac{3}{32}} ... \ \text{Plug in L = 3}\] \[\Large t = 2\pi\sqrt{0.09375}\] \[\Large t \approx 2\pi(0.306186)\] \[\Large t \approx 2(3.14159)(0.306186)\] \[\Large t \approx (6.28318)(0.306186)\] \[\Large t \approx 1.92382\] ---------------------------------- So when \[\Large L = 3\] the value of t is approximately \[\Large t \approx 1.92382\]

    • 2 years ago
  23. jim_thompson5910 Group Title
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    Hopefully it makes sense. If not, let me know.

    • 2 years ago
  24. ashleyb Group Title
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    oh that makes sense...but how do u get the answer not in decimal form...like how do solve the radical

    • 2 years ago
  25. jim_thompson5910 Group Title
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    Well you can't simplify \[\Large \sqrt{\frac{3}{32}}\] too much. I guess you can say \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}}{\sqrt{32}}\] \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}}{\sqrt{16*2}}\] \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}}{\sqrt{16}*\sqrt{2}}\] \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}}{4\sqrt{2}}\] \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{3}*\sqrt{2}}{4\sqrt{2}*\sqrt{2}}\] \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{6}}{4*2}\] \[\Large \sqrt{\frac{3}{32}} = \frac{\sqrt{6}}{8}\] ------------------------------------------------------- So \[\Large t = 2\pi\sqrt{\frac{3}{32}}\] becomes \[\Large t = 2\pi\frac{\sqrt{6}}{8}\]

    • 2 years ago
  26. jim_thompson5910 Group Title
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    but in my opinion, that's not much of a simplification

    • 2 years ago
  27. ashleyb Group Title
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    okayy i understand now...thanks for your help

    • 2 years ago
  28. jim_thompson5910 Group Title
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    oh you can go further to get \[\Large t = 2\pi\frac{\sqrt{6}}{8}\] \[\Large t = \frac{\pi\sqrt{6}}{4}\]

    • 2 years ago
  29. jim_thompson5910 Group Title
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    you're welcome

    • 2 years ago
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