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Do you have actual values? Maybe a diagram will help...

The attached example1.pdf gives the initial condition where
r1(0) = r10 = {1,1} and r2(0) = r20 = {-2,-3}
The line between them, as shown, does not intersect with the origin. Also, shown, however, are velocity vectors
v1 = {1,1} and v2 = {0, 1}.
Thus you can guess that at t = 1, you'll have
r1(1) = {2,2} and r2(1) = {-2,-2}.
That, of course, goes through the origin. The answer for this case would be t = 1. But I'm looking for a symbolic answer.

Sorry, but I gotta go. Great problem.

It's cool, right? Not a homework problem like the other poor summer school kids here...

i guess equating x,y,z coordinates and solving for t would help to find the value of t.

Only 2D

2d cases only ... it's a bit simpler. do you have any other constraints for v?

can you give me the solution you got from Wolf?

r10={Ax0, Ay0},
r20={Bx0, By0},
v1= {Vax, Vay},
v2 = {Vbx, Vby}

can you post the code instead?

Here's the code:
If you can read the nb, explaining would be so much easier lol. Also note that I use Cx and Cy because in the real problem that's the "origin." Just skp it - I replace it later with {0,0}

i think this is a similar Q
http://openstudy.com/study#/updates/5012a650e4b08ffc0ef4add0

No, I don't think we can use that one. It has nothing to do with collision.

man ... you sure know how to program. I'm using MMA as simple calculator.

well, x is a variable ... are you trying to find the velocity and time from given 4 points?

No ,no, no. Look, its hard to explain. But I solved it just now so don't worry about it.

okay!! good for you that you solved!!