What are the x– and y–intercepts of the graph of y = x^2 + x – 6?

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What are the x– and y–intercepts of the graph of y = x^2 + x – 6?

Mathematics
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For finding x intercept, Put y = 0 And for finding y intercept, Put x = 0..
So: for finding x intercept you will put y = 0 that is: \[x^2 + x - 6 = 0\] Try to factor this equation and you will get two values of x..
Tell me what is your factors to this equation??

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to factor it i would fing two numbers that multiply to -6 and add to 0?
Add to 1..
okay
Solving or not??
-2 and 3 are my factors
Then you are pretty correct in this..
So is this right? \[(x+3)(x-2) = 0\]
okay so those are my x and y factors?
No these are only for x we will find y somewhat later..
okay...can u show me the steps for finding y?
For finding y, put x = 0 in your original equation..
okay so y=0^2+0-6?
Yes go ahead so what did you get for y ??
-6?
So true..
thankyou so much!!! I was having alot of trouble with this!
Welcome dear..

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