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BagelsAreIcelandic

  • 2 years ago

(a^5b^3) (a^4b^5) Do I multiply for add the exponents? E.g. would I have a^9 or a^20? Thank you!

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  1. jim_thompson5910
    • 2 years ago
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    You add the exponents in this case

  2. BagelsAreIcelandic
    • 2 years ago
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    Oh my goodness... THANK YOU!!!!! Last time I had to ask this question, I was forced to wait 10 minutes for a wrong answer.

  3. jim_thompson5910
    • 2 years ago
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    you're welcome

  4. BagelsAreIcelandic
    • 2 years ago
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    So it is a^9andb^8 correct?

  5. jim_thompson5910
    • 2 years ago
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    bingo

  6. BagelsAreIcelandic
    • 2 years ago
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    THANK YOU! Can you answer one more quick question, please?

  7. jim_thompson5910
    • 2 years ago
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    so \[\Large a^9b^8\]

  8. BagelsAreIcelandic
    • 2 years ago
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    (-2hi^3)(2h^2ij^3)

  9. jim_thompson5910
    • 2 years ago
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    multiply -2 and 2 to get?

  10. BagelsAreIcelandic
    • 2 years ago
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    Would it be -4h^3i^4j^7?

  11. jim_thompson5910
    • 2 years ago
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    The term for j is j^3 since the first expression doesn't have any j terms

  12. jim_thompson5910
    • 2 years ago
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    or because (-2hi^3)(2h^2ij^3) really is (-2hi^3j^0)(2h^2ij^3)

  13. jim_thompson5910
    • 2 years ago
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    So i'm not sure how you're getting 4+3 = 7

  14. BagelsAreIcelandic
    • 2 years ago
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    -4h^2i^3j^12?

  15. jim_thompson5910
    • 2 years ago
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    no

  16. jim_thompson5910
    • 2 years ago
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    What are the exponents for j in (-2hi^3j^0)(2h^2ij^3) ???

  17. BagelsAreIcelandic
    • 2 years ago
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    Do I not multiply -2 and 2?

  18. jim_thompson5910
    • 2 years ago
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    yes those are the coefficients

  19. BagelsAreIcelandic
    • 2 years ago
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    0 and 3

  20. jim_thompson5910
    • 2 years ago
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    add them

  21. jim_thompson5910
    • 2 years ago
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    to get the final exponent for j

  22. BagelsAreIcelandic
    • 2 years ago
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    3

  23. jim_thompson5910
    • 2 years ago
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    So the answer is \[\Large -4h^3i^4j^3\]

  24. BagelsAreIcelandic
    • 2 years ago
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    Thank you!!

  25. jim_thompson5910
    • 2 years ago
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    yw

  26. BagelsAreIcelandic
    • 2 years ago
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    Okay now, another one! :D ([3^2]^3g^5h^8)^2

  27. jim_thompson5910
    • 2 years ago
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    What is [3^2]^3

  28. BagelsAreIcelandic
    • 2 years ago
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    Do you mind if I do the problem by myself, and I'll give you my answer and see if I'm right?

  29. jim_thompson5910
    • 2 years ago
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    alright

  30. BagelsAreIcelandic
    • 2 years ago
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    Stay with me, please! :)

  31. jim_thompson5910
    • 2 years ago
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    ok

  32. BagelsAreIcelandic
    • 2 years ago
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    729g^10h^16

  33. BagelsAreIcelandic
    • 2 years ago
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    Yes?

  34. jim_thompson5910
    • 2 years ago
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    no it's not correct

  35. BagelsAreIcelandic
    • 2 years ago
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    Huh..

  36. jim_thompson5910
    • 2 years ago
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    3^2 is 9 So [3^2]^3 = 9^3 = 729 This means ([3^2]^3g^5h^8)^2 becomes (729g^5h^8)^2

  37. jim_thompson5910
    • 2 years ago
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    did you get that as one of your steps?

  38. BagelsAreIcelandic
    • 2 years ago
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    Uhm

  39. BagelsAreIcelandic
    • 2 years ago
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    yes

  40. jim_thompson5910
    • 2 years ago
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    Then you square everything inside

  41. BagelsAreIcelandic
    • 2 years ago
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    Oh!

  42. jim_thompson5910
    • 2 years ago
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    tell me what you get

  43. BagelsAreIcelandic
    • 2 years ago
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    531,411g^10h^13

  44. BagelsAreIcelandic
    • 2 years ago
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    16

  45. jim_thompson5910
    • 2 years ago
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    yes, but I would get rid of the comma....computer answer systems don't like commas

  46. jim_thompson5910
    • 2 years ago
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    oh yes, 16 not 13

  47. jim_thompson5910
    • 2 years ago
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    use only commas to separate out answers (like ordered pairs), don't enter commas for large numbers

  48. BagelsAreIcelandic
    • 2 years ago
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    kk

  49. jim_thompson5910
    • 2 years ago
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    so the answer is 531411g^10h^16 which looks like \[\Large 531411g^{10}h^{16}\]

  50. BagelsAreIcelandic
    • 2 years ago
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    uhm

  51. jim_thompson5910
    • 2 years ago
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    what's wrong?

  52. BagelsAreIcelandic
    • 2 years ago
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    x(x^4)(x^6)

  53. jim_thompson5910
    • 2 years ago
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    x = x^1

  54. BagelsAreIcelandic
    • 2 years ago
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    x^11?

  55. jim_thompson5910
    • 2 years ago
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    So x(x^4)(x^6) is the same as x^1(x^4)(x^6) or x^1 times x^4 times x^6

  56. jim_thompson5910
    • 2 years ago
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    yes

  57. jim_thompson5910
    • 2 years ago
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    x(x^4)(x^6) = x^11

  58. BagelsAreIcelandic
    • 2 years ago
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    Okay, one more question! :)

  59. jim_thompson5910
    • 2 years ago
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    ok

  60. BagelsAreIcelandic
    • 2 years ago
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    |dw:1343517212128:dw|

  61. jim_thompson5910
    • 2 years ago
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    base is \(\large 5n^3\) ? and height is \(\large 2n^3\) ?

  62. BagelsAreIcelandic
    • 2 years ago
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    no height in 2n^2

  63. jim_thompson5910
    • 2 years ago
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    ok

  64. jim_thompson5910
    • 2 years ago
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    and they want the area?

  65. BagelsAreIcelandic
    • 2 years ago
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    Express the area of the triangle as monomial.

  66. jim_thompson5910
    • 2 years ago
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    multiply the two expressions, then cut that result in half to get the area of the triangle

  67. BagelsAreIcelandic
    • 2 years ago
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    5n^5

  68. jim_thompson5910
    • 2 years ago
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    you got it

  69. BagelsAreIcelandic
    • 2 years ago
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    THANK YOU

  70. jim_thompson5910
    • 2 years ago
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    you're welcome

  71. BagelsAreIcelandic
    • 2 years ago
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    Oops, I lied. More problems. I might force you to stick around for a bit, but I'm sure I've got this! :)

  72. jim_thompson5910
    • 2 years ago
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    Why not answer all the ones you can and post them all at once. Remember to post the answers right along with the question Like in the form # 1 Question: .... Answer: .... ====================================== # 2 Question: .... Answer: .... etc etc

  73. BagelsAreIcelandic
    • 2 years ago
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    (5g^4h^4)^3 125g^7h^7

  74. jim_thompson5910
    • 2 years ago
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    That should save time

  75. jim_thompson5910
    • 2 years ago
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    no, now you're multiplying exponents

  76. jim_thompson5910
    • 2 years ago
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    ex: (x^2)^3 = x^(2*3) = x^6

  77. BagelsAreIcelandic
    • 2 years ago
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    125g^12h^12, right?

  78. jim_thompson5910
    • 2 years ago
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    yes

  79. BagelsAreIcelandic
    • 2 years ago
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    (2a^4b)^2/16b^5

  80. BagelsAreIcelandic
    • 2 years ago
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    how do I do this?

  81. jim_thompson5910
    • 2 years ago
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    what is (2a^4b)^2 simplify to?

  82. jim_thompson5910
    • 2 years ago
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    does*

  83. BagelsAreIcelandic
    • 2 years ago
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    4x2a^8b^2

  84. jim_thompson5910
    • 2 years ago
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    where did the x2 come from?

  85. BagelsAreIcelandic
    • 2 years ago
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    multiplying a^2 with 2 therefore 2a^4

  86. jim_thompson5910
    • 2 years ago
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    you mean multiply the exponent 4 with 2 to get 8 So a^4 becomes a^8 So (2a^4b)^2 becomes 4a^8b^2

  87. BagelsAreIcelandic
    • 2 years ago
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    Okay... now what? :0

  88. jim_thompson5910
    • 2 years ago
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    So (2a^4b)^2/16b^5 becomes 4a^8b^2/16b^5

  89. jim_thompson5910
    • 2 years ago
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    Now reduce

  90. jim_thompson5910
    • 2 years ago
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    so 4/16 = ??? a^8b^2 over b^5 = ???

  91. BagelsAreIcelandic
    • 2 years ago
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    a^8/8b^3

  92. jim_thompson5910
    • 2 years ago
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    close a^8b^2 over b^5 becomes a^8 over b^3

  93. jim_thompson5910
    • 2 years ago
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    but 4/16 is NOT 1/8

  94. Romero
    • 2 years ago
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    When I have problems seeing if I have to add or multiply exponents what I do is expand everything. For example let's take \[(a^5) *(a^4)\]let's expand that \[(a *a*a*a*a)*(a*a*a*a)\] Which is basically \[a^9\]

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