anonymous
  • anonymous
(a^5b^3) (a^4b^5) Do I multiply for add the exponents? E.g. would I have a^9 or a^20? Thank you!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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jim_thompson5910
  • jim_thompson5910
You add the exponents in this case
anonymous
  • anonymous
Oh my goodness... THANK YOU!!!!! Last time I had to ask this question, I was forced to wait 10 minutes for a wrong answer.
jim_thompson5910
  • jim_thompson5910
you're welcome

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anonymous
  • anonymous
So it is a^9andb^8 correct?
jim_thompson5910
  • jim_thompson5910
bingo
anonymous
  • anonymous
THANK YOU! Can you answer one more quick question, please?
jim_thompson5910
  • jim_thompson5910
so \[\Large a^9b^8\]
anonymous
  • anonymous
(-2hi^3)(2h^2ij^3)
jim_thompson5910
  • jim_thompson5910
multiply -2 and 2 to get?
anonymous
  • anonymous
Would it be -4h^3i^4j^7?
jim_thompson5910
  • jim_thompson5910
The term for j is j^3 since the first expression doesn't have any j terms
jim_thompson5910
  • jim_thompson5910
or because (-2hi^3)(2h^2ij^3) really is (-2hi^3j^0)(2h^2ij^3)
jim_thompson5910
  • jim_thompson5910
So i'm not sure how you're getting 4+3 = 7
anonymous
  • anonymous
-4h^2i^3j^12?
jim_thompson5910
  • jim_thompson5910
no
jim_thompson5910
  • jim_thompson5910
What are the exponents for j in (-2hi^3j^0)(2h^2ij^3) ???
anonymous
  • anonymous
Do I not multiply -2 and 2?
jim_thompson5910
  • jim_thompson5910
yes those are the coefficients
anonymous
  • anonymous
0 and 3
jim_thompson5910
  • jim_thompson5910
add them
jim_thompson5910
  • jim_thompson5910
to get the final exponent for j
anonymous
  • anonymous
3
jim_thompson5910
  • jim_thompson5910
So the answer is \[\Large -4h^3i^4j^3\]
anonymous
  • anonymous
Thank you!!
jim_thompson5910
  • jim_thompson5910
yw
anonymous
  • anonymous
Okay now, another one! :D ([3^2]^3g^5h^8)^2
jim_thompson5910
  • jim_thompson5910
What is [3^2]^3
anonymous
  • anonymous
Do you mind if I do the problem by myself, and I'll give you my answer and see if I'm right?
jim_thompson5910
  • jim_thompson5910
alright
anonymous
  • anonymous
Stay with me, please! :)
jim_thompson5910
  • jim_thompson5910
ok
anonymous
  • anonymous
729g^10h^16
anonymous
  • anonymous
Yes?
jim_thompson5910
  • jim_thompson5910
no it's not correct
anonymous
  • anonymous
Huh..
jim_thompson5910
  • jim_thompson5910
3^2 is 9 So [3^2]^3 = 9^3 = 729 This means ([3^2]^3g^5h^8)^2 becomes (729g^5h^8)^2
jim_thompson5910
  • jim_thompson5910
did you get that as one of your steps?
anonymous
  • anonymous
Uhm
anonymous
  • anonymous
yes
jim_thompson5910
  • jim_thompson5910
Then you square everything inside
anonymous
  • anonymous
Oh!
jim_thompson5910
  • jim_thompson5910
tell me what you get
anonymous
  • anonymous
531,411g^10h^13
anonymous
  • anonymous
16
jim_thompson5910
  • jim_thompson5910
yes, but I would get rid of the comma....computer answer systems don't like commas
jim_thompson5910
  • jim_thompson5910
oh yes, 16 not 13
jim_thompson5910
  • jim_thompson5910
use only commas to separate out answers (like ordered pairs), don't enter commas for large numbers
anonymous
  • anonymous
kk
jim_thompson5910
  • jim_thompson5910
so the answer is 531411g^10h^16 which looks like \[\Large 531411g^{10}h^{16}\]
anonymous
  • anonymous
uhm
jim_thompson5910
  • jim_thompson5910
what's wrong?
anonymous
  • anonymous
x(x^4)(x^6)
jim_thompson5910
  • jim_thompson5910
x = x^1
anonymous
  • anonymous
x^11?
jim_thompson5910
  • jim_thompson5910
So x(x^4)(x^6) is the same as x^1(x^4)(x^6) or x^1 times x^4 times x^6
jim_thompson5910
  • jim_thompson5910
yes
jim_thompson5910
  • jim_thompson5910
x(x^4)(x^6) = x^11
anonymous
  • anonymous
Okay, one more question! :)
jim_thompson5910
  • jim_thompson5910
ok
anonymous
  • anonymous
|dw:1343517212128:dw|
jim_thompson5910
  • jim_thompson5910
base is \(\large 5n^3\) ? and height is \(\large 2n^3\) ?
anonymous
  • anonymous
no height in 2n^2
jim_thompson5910
  • jim_thompson5910
ok
jim_thompson5910
  • jim_thompson5910
and they want the area?
anonymous
  • anonymous
Express the area of the triangle as monomial.
jim_thompson5910
  • jim_thompson5910
multiply the two expressions, then cut that result in half to get the area of the triangle
anonymous
  • anonymous
5n^5
jim_thompson5910
  • jim_thompson5910
you got it
anonymous
  • anonymous
THANK YOU
jim_thompson5910
  • jim_thompson5910
you're welcome
anonymous
  • anonymous
Oops, I lied. More problems. I might force you to stick around for a bit, but I'm sure I've got this! :)
jim_thompson5910
  • jim_thompson5910
Why not answer all the ones you can and post them all at once. Remember to post the answers right along with the question Like in the form # 1 Question: .... Answer: .... ====================================== # 2 Question: .... Answer: .... etc etc
anonymous
  • anonymous
(5g^4h^4)^3 125g^7h^7
jim_thompson5910
  • jim_thompson5910
That should save time
jim_thompson5910
  • jim_thompson5910
no, now you're multiplying exponents
jim_thompson5910
  • jim_thompson5910
ex: (x^2)^3 = x^(2*3) = x^6
anonymous
  • anonymous
125g^12h^12, right?
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
(2a^4b)^2/16b^5
anonymous
  • anonymous
how do I do this?
jim_thompson5910
  • jim_thompson5910
what is (2a^4b)^2 simplify to?
jim_thompson5910
  • jim_thompson5910
does*
anonymous
  • anonymous
4x2a^8b^2
jim_thompson5910
  • jim_thompson5910
where did the x2 come from?
anonymous
  • anonymous
multiplying a^2 with 2 therefore 2a^4
jim_thompson5910
  • jim_thompson5910
you mean multiply the exponent 4 with 2 to get 8 So a^4 becomes a^8 So (2a^4b)^2 becomes 4a^8b^2
anonymous
  • anonymous
Okay... now what? :0
jim_thompson5910
  • jim_thompson5910
So (2a^4b)^2/16b^5 becomes 4a^8b^2/16b^5
jim_thompson5910
  • jim_thompson5910
Now reduce
jim_thompson5910
  • jim_thompson5910
so 4/16 = ??? a^8b^2 over b^5 = ???
anonymous
  • anonymous
a^8/8b^3
jim_thompson5910
  • jim_thompson5910
close a^8b^2 over b^5 becomes a^8 over b^3
jim_thompson5910
  • jim_thompson5910
but 4/16 is NOT 1/8
anonymous
  • anonymous
When I have problems seeing if I have to add or multiply exponents what I do is expand everything. For example let's take \[(a^5) *(a^4)\]let's expand that \[(a *a*a*a*a)*(a*a*a*a)\] Which is basically \[a^9\]

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