(a^5b^3) (a^4b^5)
Do I multiply for add the exponents? E.g. would I have a^9 or a^20? Thank you!

- anonymous

(a^5b^3) (a^4b^5)
Do I multiply for add the exponents? E.g. would I have a^9 or a^20? Thank you!

- Stacey Warren - Expert brainly.com

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- schrodinger

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- jim_thompson5910

You add the exponents in this case

- anonymous

Oh my goodness... THANK YOU!!!!! Last time I had to ask this question, I was forced to wait 10 minutes for a wrong answer.

- jim_thompson5910

you're welcome

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## More answers

- anonymous

So it is a^9andb^8 correct?

- jim_thompson5910

bingo

- anonymous

THANK YOU! Can you answer one more quick question, please?

- jim_thompson5910

so \[\Large a^9b^8\]

- anonymous

(-2hi^3)(2h^2ij^3)

- jim_thompson5910

multiply -2 and 2 to get?

- anonymous

Would it be -4h^3i^4j^7?

- jim_thompson5910

The term for j is j^3 since the first expression doesn't have any j terms

- jim_thompson5910

or because
(-2hi^3)(2h^2ij^3)
really is
(-2hi^3j^0)(2h^2ij^3)

- jim_thompson5910

So i'm not sure how you're getting 4+3 = 7

- anonymous

-4h^2i^3j^12?

- jim_thompson5910

no

- jim_thompson5910

What are the exponents for j in
(-2hi^3j^0)(2h^2ij^3)
???

- anonymous

Do I not multiply -2 and 2?

- jim_thompson5910

yes those are the coefficients

- anonymous

0 and 3

- jim_thompson5910

add them

- jim_thompson5910

to get the final exponent for j

- anonymous

3

- jim_thompson5910

So the answer is \[\Large -4h^3i^4j^3\]

- anonymous

Thank you!!

- jim_thompson5910

yw

- anonymous

Okay now, another one! :D
([3^2]^3g^5h^8)^2

- jim_thompson5910

What is [3^2]^3

- anonymous

Do you mind if I do the problem by myself, and I'll give you my answer and see if I'm right?

- jim_thompson5910

alright

- anonymous

Stay with me, please! :)

- jim_thompson5910

ok

- anonymous

729g^10h^16

- anonymous

Yes?

- jim_thompson5910

no it's not correct

- anonymous

Huh..

- jim_thompson5910

3^2 is 9
So [3^2]^3 = 9^3 = 729
This means
([3^2]^3g^5h^8)^2
becomes
(729g^5h^8)^2

- jim_thompson5910

did you get that as one of your steps?

- anonymous

Uhm

- anonymous

yes

- jim_thompson5910

Then you square everything inside

- anonymous

Oh!

- jim_thompson5910

tell me what you get

- anonymous

531,411g^10h^13

- anonymous

16

- jim_thompson5910

yes, but I would get rid of the comma....computer answer systems don't like commas

- jim_thompson5910

oh yes, 16 not 13

- jim_thompson5910

use only commas to separate out answers (like ordered pairs), don't enter commas for large numbers

- anonymous

kk

- jim_thompson5910

so the answer is
531411g^10h^16
which looks like
\[\Large 531411g^{10}h^{16}\]

- anonymous

uhm

- jim_thompson5910

what's wrong?

- anonymous

x(x^4)(x^6)

- jim_thompson5910

x = x^1

- anonymous

x^11?

- jim_thompson5910

So
x(x^4)(x^6)
is the same as
x^1(x^4)(x^6)
or
x^1 times x^4 times x^6

- jim_thompson5910

yes

- jim_thompson5910

x(x^4)(x^6) = x^11

- anonymous

Okay, one more question! :)

- jim_thompson5910

ok

- anonymous

|dw:1343517212128:dw|

- jim_thompson5910

base is \(\large 5n^3\) ?
and
height is \(\large 2n^3\) ?

- anonymous

no
height in 2n^2

- jim_thompson5910

ok

- jim_thompson5910

and they want the area?

- anonymous

Express the area of the triangle as monomial.

- jim_thompson5910

multiply the two expressions, then cut that result in half to get the area of the triangle

- anonymous

5n^5

- jim_thompson5910

you got it

- anonymous

THANK YOU

- jim_thompson5910

you're welcome

- anonymous

Oops, I lied. More problems. I might force you to stick around for a bit, but I'm sure I've got this! :)

- jim_thompson5910

Why not answer all the ones you can and post them all at once. Remember to post the answers right along with the question
Like in the form
# 1
Question: ....
Answer: ....
======================================
# 2
Question: ....
Answer: ....
etc etc

- anonymous

(5g^4h^4)^3 125g^7h^7

- jim_thompson5910

That should save time

- jim_thompson5910

no, now you're multiplying exponents

- jim_thompson5910

ex:
(x^2)^3 = x^(2*3) = x^6

- anonymous

125g^12h^12, right?

- jim_thompson5910

yes

- anonymous

(2a^4b)^2/16b^5

- anonymous

how do I do this?

- jim_thompson5910

what is (2a^4b)^2 simplify to?

- jim_thompson5910

does*

- anonymous

4x2a^8b^2

- jim_thompson5910

where did the x2 come from?

- anonymous

multiplying a^2 with 2 therefore 2a^4

- jim_thompson5910

you mean multiply the exponent 4 with 2 to get 8
So a^4 becomes a^8
So
(2a^4b)^2
becomes
4a^8b^2

- anonymous

Okay... now what? :0

- jim_thompson5910

So
(2a^4b)^2/16b^5
becomes
4a^8b^2/16b^5

- jim_thompson5910

Now reduce

- jim_thompson5910

so 4/16 = ???
a^8b^2 over b^5 = ???

- anonymous

a^8/8b^3

- jim_thompson5910

close
a^8b^2 over b^5
becomes
a^8 over b^3

- jim_thompson5910

but 4/16 is NOT 1/8

- anonymous

When I have problems seeing if I have to add or multiply exponents what I do is expand everything. For example let's take \[(a^5) *(a^4)\]let's expand that \[(a *a*a*a*a)*(a*a*a*a)\]
Which is basically
\[a^9\]

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