## BagelsAreIcelandic 3 years ago (a^5b^3) (a^4b^5) Do I multiply for add the exponents? E.g. would I have a^9 or a^20? Thank you!

1. jim_thompson5910

You add the exponents in this case

2. BagelsAreIcelandic

Oh my goodness... THANK YOU!!!!! Last time I had to ask this question, I was forced to wait 10 minutes for a wrong answer.

3. jim_thompson5910

you're welcome

4. BagelsAreIcelandic

So it is a^9andb^8 correct?

5. jim_thompson5910

bingo

6. BagelsAreIcelandic

7. jim_thompson5910

so \[\Large a^9b^8\]

8. BagelsAreIcelandic

(-2hi^3)(2h^2ij^3)

9. jim_thompson5910

multiply -2 and 2 to get?

10. BagelsAreIcelandic

Would it be -4h^3i^4j^7?

11. jim_thompson5910

The term for j is j^3 since the first expression doesn't have any j terms

12. jim_thompson5910

or because (-2hi^3)(2h^2ij^3) really is (-2hi^3j^0)(2h^2ij^3)

13. jim_thompson5910

So i'm not sure how you're getting 4+3 = 7

14. BagelsAreIcelandic

-4h^2i^3j^12?

15. jim_thompson5910

no

16. jim_thompson5910

What are the exponents for j in (-2hi^3j^0)(2h^2ij^3) ???

17. BagelsAreIcelandic

Do I not multiply -2 and 2?

18. jim_thompson5910

yes those are the coefficients

19. BagelsAreIcelandic

0 and 3

20. jim_thompson5910

21. jim_thompson5910

to get the final exponent for j

22. BagelsAreIcelandic

3

23. jim_thompson5910

So the answer is \[\Large -4h^3i^4j^3\]

24. BagelsAreIcelandic

Thank you!!

25. jim_thompson5910

yw

26. BagelsAreIcelandic

Okay now, another one! :D ([3^2]^3g^5h^8)^2

27. jim_thompson5910

What is [3^2]^3

28. BagelsAreIcelandic

Do you mind if I do the problem by myself, and I'll give you my answer and see if I'm right?

29. jim_thompson5910

alright

30. BagelsAreIcelandic

31. jim_thompson5910

ok

32. BagelsAreIcelandic

729g^10h^16

33. BagelsAreIcelandic

Yes?

34. jim_thompson5910

no it's not correct

35. BagelsAreIcelandic

Huh..

36. jim_thompson5910

3^2 is 9 So [3^2]^3 = 9^3 = 729 This means ([3^2]^3g^5h^8)^2 becomes (729g^5h^8)^2

37. jim_thompson5910

did you get that as one of your steps?

38. BagelsAreIcelandic

Uhm

39. BagelsAreIcelandic

yes

40. jim_thompson5910

Then you square everything inside

41. BagelsAreIcelandic

Oh!

42. jim_thompson5910

tell me what you get

43. BagelsAreIcelandic

531,411g^10h^13

44. BagelsAreIcelandic

16

45. jim_thompson5910

yes, but I would get rid of the comma....computer answer systems don't like commas

46. jim_thompson5910

oh yes, 16 not 13

47. jim_thompson5910

use only commas to separate out answers (like ordered pairs), don't enter commas for large numbers

48. BagelsAreIcelandic

kk

49. jim_thompson5910

so the answer is 531411g^10h^16 which looks like \[\Large 531411g^{10}h^{16}\]

50. BagelsAreIcelandic

uhm

51. jim_thompson5910

what's wrong?

52. BagelsAreIcelandic

x(x^4)(x^6)

53. jim_thompson5910

x = x^1

54. BagelsAreIcelandic

x^11?

55. jim_thompson5910

So x(x^4)(x^6) is the same as x^1(x^4)(x^6) or x^1 times x^4 times x^6

56. jim_thompson5910

yes

57. jim_thompson5910

x(x^4)(x^6) = x^11

58. BagelsAreIcelandic

Okay, one more question! :)

59. jim_thompson5910

ok

60. BagelsAreIcelandic

|dw:1343517212128:dw|

61. jim_thompson5910

base is \(\large 5n^3\) ? and height is \(\large 2n^3\) ?

62. BagelsAreIcelandic

no height in 2n^2

63. jim_thompson5910

ok

64. jim_thompson5910

and they want the area?

65. BagelsAreIcelandic

Express the area of the triangle as monomial.

66. jim_thompson5910

multiply the two expressions, then cut that result in half to get the area of the triangle

67. BagelsAreIcelandic

5n^5

68. jim_thompson5910

you got it

69. BagelsAreIcelandic

THANK YOU

70. jim_thompson5910

you're welcome

71. BagelsAreIcelandic

Oops, I lied. More problems. I might force you to stick around for a bit, but I'm sure I've got this! :)

72. jim_thompson5910

Why not answer all the ones you can and post them all at once. Remember to post the answers right along with the question Like in the form # 1 Question: .... Answer: .... ====================================== # 2 Question: .... Answer: .... etc etc

73. BagelsAreIcelandic

(5g^4h^4)^3 125g^7h^7

74. jim_thompson5910

That should save time

75. jim_thompson5910

no, now you're multiplying exponents

76. jim_thompson5910

ex: (x^2)^3 = x^(2*3) = x^6

77. BagelsAreIcelandic

125g^12h^12, right?

78. jim_thompson5910

yes

79. BagelsAreIcelandic

(2a^4b)^2/16b^5

80. BagelsAreIcelandic

how do I do this?

81. jim_thompson5910

what is (2a^4b)^2 simplify to?

82. jim_thompson5910

does*

83. BagelsAreIcelandic

4x2a^8b^2

84. jim_thompson5910

where did the x2 come from?

85. BagelsAreIcelandic

multiplying a^2 with 2 therefore 2a^4

86. jim_thompson5910

you mean multiply the exponent 4 with 2 to get 8 So a^4 becomes a^8 So (2a^4b)^2 becomes 4a^8b^2

87. BagelsAreIcelandic

Okay... now what? :0

88. jim_thompson5910

So (2a^4b)^2/16b^5 becomes 4a^8b^2/16b^5

89. jim_thompson5910

Now reduce

90. jim_thompson5910

so 4/16 = ??? a^8b^2 over b^5 = ???

91. BagelsAreIcelandic

a^8/8b^3

92. jim_thompson5910

close a^8b^2 over b^5 becomes a^8 over b^3

93. jim_thompson5910

but 4/16 is NOT 1/8

94. Romero

When I have problems seeing if I have to add or multiply exponents what I do is expand everything. For example let's take \[(a^5) *(a^4)\]let's expand that \[(a *a*a*a*a)*(a*a*a*a)\] Which is basically \[a^9\]