BagelsAreIcelandic
(a^5b^3) (a^4b^5)
Do I multiply for add the exponents? E.g. would I have a^9 or a^20? Thank you!
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jim_thompson5910
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You add the exponents in this case
BagelsAreIcelandic
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Oh my goodness... THANK YOU!!!!! Last time I had to ask this question, I was forced to wait 10 minutes for a wrong answer.
jim_thompson5910
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you're welcome
BagelsAreIcelandic
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So it is a^9andb^8 correct?
BagelsAreIcelandic
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THANK YOU! Can you answer one more quick question, please?
jim_thompson5910
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so \[\Large a^9b^8\]
BagelsAreIcelandic
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(-2hi^3)(2h^2ij^3)
jim_thompson5910
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multiply -2 and 2 to get?
BagelsAreIcelandic
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Would it be -4h^3i^4j^7?
jim_thompson5910
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The term for j is j^3 since the first expression doesn't have any j terms
jim_thompson5910
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or because
(-2hi^3)(2h^2ij^3)
really is
(-2hi^3j^0)(2h^2ij^3)
jim_thompson5910
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So i'm not sure how you're getting 4+3 = 7
jim_thompson5910
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What are the exponents for j in
(-2hi^3j^0)(2h^2ij^3)
???
BagelsAreIcelandic
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Do I not multiply -2 and 2?
jim_thompson5910
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yes those are the coefficients
jim_thompson5910
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add them
jim_thompson5910
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to get the final exponent for j
jim_thompson5910
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So the answer is \[\Large -4h^3i^4j^3\]
BagelsAreIcelandic
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Okay now, another one! :D
([3^2]^3g^5h^8)^2
jim_thompson5910
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What is [3^2]^3
BagelsAreIcelandic
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Do you mind if I do the problem by myself, and I'll give you my answer and see if I'm right?
jim_thompson5910
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alright
BagelsAreIcelandic
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Stay with me, please! :)
jim_thompson5910
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no it's not correct
jim_thompson5910
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3^2 is 9
So [3^2]^3 = 9^3 = 729
This means
([3^2]^3g^5h^8)^2
becomes
(729g^5h^8)^2
jim_thompson5910
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did you get that as one of your steps?
jim_thompson5910
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Then you square everything inside
jim_thompson5910
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tell me what you get
BagelsAreIcelandic
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531,411g^10h^13
jim_thompson5910
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yes, but I would get rid of the comma....computer answer systems don't like commas
jim_thompson5910
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oh yes, 16 not 13
jim_thompson5910
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use only commas to separate out answers (like ordered pairs), don't enter commas for large numbers
jim_thompson5910
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so the answer is
531411g^10h^16
which looks like
\[\Large 531411g^{10}h^{16}\]
jim_thompson5910
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what's wrong?
jim_thompson5910
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x = x^1
jim_thompson5910
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So
x(x^4)(x^6)
is the same as
x^1(x^4)(x^6)
or
x^1 times x^4 times x^6
jim_thompson5910
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x(x^4)(x^6) = x^11
BagelsAreIcelandic
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Okay, one more question! :)
BagelsAreIcelandic
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|dw:1343517212128:dw|
jim_thompson5910
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base is \(\large 5n^3\) ?
and
height is \(\large 2n^3\) ?
BagelsAreIcelandic
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no
height in 2n^2
jim_thompson5910
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and they want the area?
BagelsAreIcelandic
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Express the area of the triangle as monomial.
jim_thompson5910
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multiply the two expressions, then cut that result in half to get the area of the triangle
jim_thompson5910
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you got it
jim_thompson5910
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you're welcome
BagelsAreIcelandic
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Oops, I lied. More problems. I might force you to stick around for a bit, but I'm sure I've got this! :)
jim_thompson5910
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Why not answer all the ones you can and post them all at once. Remember to post the answers right along with the question
Like in the form
# 1
Question: ....
Answer: ....
======================================
# 2
Question: ....
Answer: ....
etc etc
BagelsAreIcelandic
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(5g^4h^4)^3 125g^7h^7
jim_thompson5910
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That should save time
jim_thompson5910
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no, now you're multiplying exponents
jim_thompson5910
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ex:
(x^2)^3 = x^(2*3) = x^6
BagelsAreIcelandic
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125g^12h^12, right?
BagelsAreIcelandic
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(2a^4b)^2/16b^5
BagelsAreIcelandic
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how do I do this?
jim_thompson5910
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what is (2a^4b)^2 simplify to?
jim_thompson5910
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where did the x2 come from?
BagelsAreIcelandic
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multiplying a^2 with 2 therefore 2a^4
jim_thompson5910
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you mean multiply the exponent 4 with 2 to get 8
So a^4 becomes a^8
So
(2a^4b)^2
becomes
4a^8b^2
BagelsAreIcelandic
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Okay... now what? :0
jim_thompson5910
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So
(2a^4b)^2/16b^5
becomes
4a^8b^2/16b^5
jim_thompson5910
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Now reduce
jim_thompson5910
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so 4/16 = ???
a^8b^2 over b^5 = ???
jim_thompson5910
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close
a^8b^2 over b^5
becomes
a^8 over b^3
jim_thompson5910
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but 4/16 is NOT 1/8
Romero
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When I have problems seeing if I have to add or multiply exponents what I do is expand everything. For example let's take \[(a^5) *(a^4)\]let's expand that \[(a *a*a*a*a)*(a*a*a*a)\]
Which is basically
\[a^9\]