anonymous
  • anonymous
what is the easiest and fastest way to solve this? Nine playing cards from the same deck are placed as shown in the figure below to form a large rectangle of area 180 sq. in. How many inches are there in the perimeter of this large rectangle?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
|dw:1343519419666:dw| they are all the same size I just can't draw
anonymous
  • anonymous
This can be anything....
anonymous
  • anonymous
do we know the measurements of the cards or a better picture?

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anonymous
  • anonymous
|dw:1343519858074:dw| does that make you happy?
anonymous
  • anonymous
w*l=180 2*w+2*l=? This is a system of equations with an infinite number of solutions because we don't have enough information
anonymous
  • anonymous
Iit HAS an answer the answer is 58 but I don't know how to get there
UnkleRhaukus
  • UnkleRhaukus
\[P=6\ell+7w\]
anonymous
  • anonymous
The short sides are 4s and the longer ones are 5s
UnkleRhaukus
  • UnkleRhaukus
\[A=5w\times(w+l)\]
anonymous
  • anonymous
From the illustration we can see that 5 breadths are equal to 4 lengths, which is equal to the length of the whole rectangle. 5b = 4l = L We also know the area of the large rectangle. From this we can create a system of equations, which we can use to solve. Notice also that the height of the rectangle is equal to a breadth and a length. h = b + l Now for the system of equations, which expresses the area (given by A = h*L): (b+l)*5b=180 (1) (b+l)*4l=180 (2) If we solve this system of equations we will get a value for the breadth and width, which we can use to find the perimeter.
anonymous
  • anonymous
okay so 5b^2+5Bl=180 and 4lb+4l^2=180 then use the process of elimination?
anonymous
  • anonymous
i did 20b^2+20bl=720 multiplied by 4 + -20l^2-20bl=-900 multiplied by -5 20bl cancels out so 20b^2-20l^2=-180 now what????
anonymous
  • anonymous
Now you have to find an expression for either b^2 or l^2 and substitute into one of the original equations :)
anonymous
  • anonymous
|dw:1343521248378:dw| is that right so far?

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