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imagreencat
 2 years ago
It is said that electric flux is independent of the surface enclosing the charge. Even if we double the length and width of, say, a box, the electric flux would be the same. However, isn't it that as you increase the area of something, you also increase the flux? And when you increase the dimensions of a rect. prism, you also increase the area of each face. How come the flux does not change still?
imagreencat
 2 years ago
It is said that electric flux is independent of the surface enclosing the charge. Even if we double the length and width of, say, a box, the electric flux would be the same. However, isn't it that as you increase the area of something, you also increase the flux? And when you increase the dimensions of a rect. prism, you also increase the area of each face. How come the flux does not change still?

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lizcody1
 2 years ago
Best ResponseYou've already chosen the best response.0I haven't looked at this in a while, but I am going to guess that it will make a difference whether you increase area of a single surface versus of an enclosed container. In a single surface, larger area means more area for flux in that direction, but net flux with a volume has vectors that cancel each other out? This is just a guess!

imagreencat
 2 years ago
Best ResponseYou've already chosen the best response.0Thank you very much!! :)

Vikas_garg
 2 years ago
Best ResponseYou've already chosen the best response.0according to my knowledge electric lines of forces crossing unit area is electric flux by increasing the area their is no effect on the electric lines of force crossing unit area..

lizcody1
 2 years ago
Best ResponseYou've already chosen the best response.0Hyperphysics has a nice diagram, http://hyperphysics.phyastr.gsu.edu/Hbase/electric/gaulaw.html#c3, and yes Vikas, you are correct, per unit area, it will not change. So perhaps the best way to imagine this is that a larger area will have a larger amount electric lines of force, but the flux per unit area will be constant.
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