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darkbbn Group Title

The sum of three consecutive integers is 267. What is the largest integer?

  • 2 years ago
  • 2 years ago

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  1. ParthKohli Group Title
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    \(x + x + 1 + x + 2 = 267\) Solve for x + 2

    • 2 years ago
  2. darkbbn Group Title
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    how would i solve it? im not good at intgers

    • 2 years ago
  3. lgbasallote Group Title
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    let x be the first integer x + 1 second integer x+2 third integer sum of the three is 267 so x + x + 1 + x+ 2 = 267 3x + 3 = 267 3x = 267 - 3 3x = 264 x = 88 x + 1 = 89 x + 2 = 90

    • 2 years ago
  4. ParthKohli Group Title
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    Basically, three consecutive numbers can be represented by a number, a number more than that, and a number more than the second number.

    • 2 years ago
  5. darkbbn Group Title
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    so is the answer 2?

    • 2 years ago
  6. ParthKohli Group Title
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    Solve the equation for x and then add two to x.

    • 2 years ago
  7. darkbbn Group Title
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    im still confused...

    • 2 years ago
  8. festicle Group Title
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    3x=264

    • 2 years ago
  9. festicle Group Title
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    x + x +x = 267 - 2 - 1

    • 2 years ago
  10. muhammad9t5 Group Title
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    thilet us consider that digit is x then sum of three digits will x+x+1+x+2=267 3x+3=267 3x=267-3 3x=264 x=88 this is 1st digit 2nd digit was x+1 so 88+1=89 3rd was x+2 so 88+2=90 largest is 90...

    • 2 years ago
  11. festicle Group Title
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    but it is consecutive integers . so its x+0 , x+1, x+2

    • 2 years ago
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