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darkbbn

  • 3 years ago

The sum of three consecutive integers is 267. What is the largest integer?

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  1. ParthKohli
    • 3 years ago
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    \(x + x + 1 + x + 2 = 267\) Solve for x + 2

  2. darkbbn
    • 3 years ago
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    how would i solve it? im not good at intgers

  3. lgbasallote
    • 3 years ago
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    let x be the first integer x + 1 second integer x+2 third integer sum of the three is 267 so x + x + 1 + x+ 2 = 267 3x + 3 = 267 3x = 267 - 3 3x = 264 x = 88 x + 1 = 89 x + 2 = 90

  4. ParthKohli
    • 3 years ago
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    Basically, three consecutive numbers can be represented by a number, a number more than that, and a number more than the second number.

  5. darkbbn
    • 3 years ago
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    so is the answer 2?

  6. ParthKohli
    • 3 years ago
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    Solve the equation for x and then add two to x.

  7. darkbbn
    • 3 years ago
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    im still confused...

  8. festicle
    • 3 years ago
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    3x=264

  9. festicle
    • 3 years ago
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    x + x +x = 267 - 2 - 1

  10. muhammad9t5
    • 3 years ago
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    thilet us consider that digit is x then sum of three digits will x+x+1+x+2=267 3x+3=267 3x=267-3 3x=264 x=88 this is 1st digit 2nd digit was x+1 so 88+1=89 3rd was x+2 so 88+2=90 largest is 90...

  11. festicle
    • 3 years ago
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    but it is consecutive integers . so its x+0 , x+1, x+2

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