anonymous
  • anonymous
I keep getting this wrong, need help. Picture attached.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
@lgbasallote you have a clue?
Hero
  • Hero
Hints: Negative exponent means inverse one-half power means square root

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More answers

anonymous
  • anonymous
it keeps coming up odd when i calculate it
Hero
  • Hero
What did you get when you simplified it?
anonymous
  • anonymous
well i typed it and it wont send
anonymous
  • anonymous
\[a^{5/2}b^{3/2}/(2)^{ab}\]
Hero
  • Hero
That's what you got for the answer?
anonymous
  • anonymous
uhh, yeah, bit odd. Not sure what drove me there
Hero
  • Hero
I hate to be the bearer of bad news, but the answer isn't even close to that.
anonymous
  • anonymous
:( i know
Hero
  • Hero
Let's at least change the 1/2 into square roots: \(\large\frac{\sqrt{a^5b^3}}{(\sqrt{ab})^{-1}}\)
mathslover
  • mathslover
answer
1 Attachment
Hero
  • Hero
Thanks @mathslover, I was in the middle of an explanation
anonymous
  • anonymous
OHHH! i see, i was working with the 1/2's incorrectly, thanks guys...
mathslover
  • mathslover
Pleasure .. and sorry to break your explanation ..
mathslover
  • mathslover
No problem @GiggleSquid .. best of luck
Hero
  • Hero
@mathslover, you should probably restrain yourself from doing that. It's kinda rude.
Hero
  • Hero
When new users do it, It's okay because they have no clue what's going on anyway. But when a user who has been here for a while does it, then I get upset.
mathslover
  • mathslover
If there was a way to see that what r u typing then i would have stopped hero.. May be you are going kinda rude ..
ParthKohli
  • ParthKohli
@mathslover Hmm, that is still not an excuse. You must have read the Code Of Conduct, which mentions not to give answers out.
mathslover
  • mathslover
@ParthKohli ... only answers are rude. . but soln are not ..
mathslover
  • mathslover
the user was getting wrong ... again and again as mentioned in the quetion .. So i attached with the drawing that helped him/her
ParthKohli
  • ParthKohli
@Hero @mathslover We might want to indulge in chat, this is supposed to be a question that has already been solved.
Hero
  • Hero
In this case, it would have been good to guide the user to the result. He was obviously trying to understand how to get to the solution. He only needed a few hints and some advice, rather than post the entire solution all at once. You usually only do that when the user isn't present or if the user specifically requests it. Other than that, it is best to guide the users. Remember, this is a learning environment. Posting the entire solution isn't always as effective as you might believe @mathslover. Guiding is much more effective.
ParthKohli
  • ParthKohli
I respect @Hero's opinion completely.
mathslover
  • mathslover
@Hero : I also agree but hence i posted that as image . Well i dont want to make this as a debate
ParthKohli
  • ParthKohli
Come to chat.
mathslover
  • mathslover
why should i @ParthKohli ? Is their any discussion about MATHS there?
ParthKohli
  • ParthKohli
No, I don't want to spoil this question. We'd continue our conversation here.

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