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lgbasalloteBest ResponseYou've already chosen the best response.0
hint: solve for x in 7x + 21 < 7 AND 7x + 21 > 7 does that help?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Wait, what? An absolute value inequality doesn't have a negative on its righthandside!
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
This is a false statement, and does not satisfy for all \(x\).
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
How can an absolute value be less than 7 when absolute value of anything is a positive number?
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Do u know the defination of modulas?
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
IF not then PLZ LOOK AT THIS: let x be any real number. Then the absolute value of x, denoted by IxI, is a non negative real number defined by dw:1343557688022:dw
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Nope. \(x =x \qquad x = x \)
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
so, when 7x+21>= 0 then 7x + 21 < 7 x<4 AND when 7x+21<0 then (7x+21)<7 x >2
 one year ago

bhaweshwebmasterBest ResponseYou've already chosen the best response.0
@sauravshakya now subsitute your answer in the question.. does it seem to satisfy? I already posted this solution.. however @ParthKohli forced me (using logic) to delete it.
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
YA IT SATISFIES @bhaweshwebmaster
 one year ago

bhaweshwebmasterBest ResponseYou've already chosen the best response.0
teach me how.. I don't see it..
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
OH. sorry @bhaweshwebmaster actually there is no solution.... since I 7x+ 21 I >=0
 one year ago
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