Here's the question you clicked on:
GiggleSquid
What is the solution set or set notation for |7x+21|<-7
hint: solve for x in 7x + 21 < -7 AND 7x + 21 > 7 does that help?
Wait, what? An absolute value inequality doesn't have a negative on its right-hand-side!
This is a false statement, and does not satisfy for all \(x\).
How can an absolute value be less than -7 when absolute value of anything is a positive number?
Do u know the defination of modulas?
IF not then PLZ LOOK AT THIS: let x be any real number. Then the absolute value of x, denoted by IxI, is a non negative real number defined by |dw:1343557688022:dw|
Nope. \(|-x| =x \qquad |x| = x \)
so, when 7x+21>= 0 then 7x + 21 < -7 x<-4 AND when 7x+21<0 then -(7x+21)<-7 x >-2
@sauravshakya now subsitute your answer in the question.. does it seem to satisfy? I already posted this solution.. however @ParthKohli forced me (using logic) to delete it.
YA IT SATISFIES @bhaweshwebmaster
teach me how.. I don't see it..
OH. sorry @bhaweshwebmaster actually there is no solution.... since I 7x+ 21 I >=0