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anonymous
 4 years ago
What is the solution set or set notation for 7x+21<7
anonymous
 4 years ago
What is the solution set or set notation for 7x+21<7

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hint: solve for x in 7x + 21 < 7 AND 7x + 21 > 7 does that help?

ParthKohli
 4 years ago
Best ResponseYou've already chosen the best response.1Wait, what? An absolute value inequality doesn't have a negative on its righthandside!

ParthKohli
 4 years ago
Best ResponseYou've already chosen the best response.1This is a false statement, and does not satisfy for all \(x\).

ParthKohli
 4 years ago
Best ResponseYou've already chosen the best response.1How can an absolute value be less than 7 when absolute value of anything is a positive number?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do u know the defination of modulas?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0IF not then PLZ LOOK AT THIS: let x be any real number. Then the absolute value of x, denoted by IxI, is a non negative real number defined by dw:1343557688022:dw

ParthKohli
 4 years ago
Best ResponseYou've already chosen the best response.1Nope. \(x =x \qquad x = x \)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so, when 7x+21>= 0 then 7x + 21 < 7 x<4 AND when 7x+21<0 then (7x+21)<7 x >2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@sauravshakya now subsitute your answer in the question.. does it seem to satisfy? I already posted this solution.. however @ParthKohli forced me (using logic) to delete it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0YA IT SATISFIES @bhaweshwebmaster

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0teach me how.. I don't see it..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OH. sorry @bhaweshwebmaster actually there is no solution.... since I 7x+ 21 I >=0
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