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GiggleSquid

  • 2 years ago

What is the solution set or set notation for |7x+21|<-7

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  1. lgbasallote
    • 2 years ago
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    hint: solve for x in 7x + 21 < -7 AND 7x + 21 > 7 does that help?

  2. ParthKohli
    • 2 years ago
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    Wait, what? An absolute value inequality doesn't have a negative on its right-hand-side!

  3. ParthKohli
    • 2 years ago
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    This is a false statement, and does not satisfy for all \(x\).

  4. ParthKohli
    • 2 years ago
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    How can an absolute value be less than -7 when absolute value of anything is a positive number?

  5. sauravshakya
    • 2 years ago
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    Do u know the defination of modulas?

  6. sauravshakya
    • 2 years ago
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    IF not then PLZ LOOK AT THIS: let x be any real number. Then the absolute value of x, denoted by IxI, is a non negative real number defined by |dw:1343557688022:dw|

  7. ParthKohli
    • 2 years ago
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    Nope. \(|-x| =x \qquad |x| = x \)

  8. sauravshakya
    • 2 years ago
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    so, when 7x+21>= 0 then 7x + 21 < -7 x<-4 AND when 7x+21<0 then -(7x+21)<-7 x >-2

  9. ParthKohli
    • 2 years ago
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    Oh yes.

  10. bhaweshwebmaster
    • 2 years ago
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    @sauravshakya now subsitute your answer in the question.. does it seem to satisfy? I already posted this solution.. however @ParthKohli forced me (using logic) to delete it.

  11. sauravshakya
    • 2 years ago
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    YA IT SATISFIES @bhaweshwebmaster

  12. bhaweshwebmaster
    • 2 years ago
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    teach me how.. I don't see it..

  13. sauravshakya
    • 2 years ago
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    OH. sorry @bhaweshwebmaster actually there is no solution.... since I 7x+ 21 I >=0

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