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 2 years ago
A cylindrical tank of height 0.4 m is open at the top and has a diameter 0.16 m.Water is filled in it upto a height of 0.16 m .Calculate the time taken to empty the tank through a hole of radius 5x10^3m in its bottom?
 2 years ago
A cylindrical tank of height 0.4 m is open at the top and has a diameter 0.16 m.Water is filled in it upto a height of 0.16 m .Calculate the time taken to empty the tank through a hole of radius 5x10^3m in its bottom?

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AravindG
 2 years ago
Best ResponseYou've already chosen the best response.0@VincentLyon.Fr , @ash2326 , @waterineyes

VincentLyon.Fr
 2 years ago
Best ResponseYou've already chosen the best response.0First, use Torricelli's law to determine speed of water in the hole and rate of flow. \(v=\sqrt{2gh}\)

VincentLyon.Fr
 2 years ago
Best ResponseYou've already chosen the best response.0Is the answer 45.80 s ?

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.0h is variable

VincentLyon.Fr
 2 years ago
Best ResponseYou've already chosen the best response.0Total volume is 3.217 L, right?

VincentLyon.Fr
 2 years ago
Best ResponseYou've already chosen the best response.0Try again. radius is 0.08m and height is 0.16m

VincentLyon.Fr
 2 years ago
Best ResponseYou've already chosen the best response.0now escape velocity is \(v=\sqrt{2gh}\)

VincentLyon.Fr
 2 years ago
Best ResponseYou've already chosen the best response.0and discharge is v multiplied by area of hole.

AravindG
 2 years ago
Best ResponseYou've already chosen the best response.0so how do we bring in volume?

VincentLyon.Fr
 2 years ago
Best ResponseYou've already chosen the best response.0time taken is: volume / discharge you should find 22.9s

VincentLyon.Fr
 2 years ago
Best ResponseYou've already chosen the best response.0Yes, but we can get round this difficulty

VincentLyon.Fr
 2 years ago
Best ResponseYou've already chosen the best response.0Do you find the same values?

VincentLyon.Fr
 2 years ago
Best ResponseYou've already chosen the best response.0initial escape velocity is v=root(2g hmax) discharge is v multiplied by area of hole. time taken is: volume / discharge you should find 22.9s This is the time it would take to empty the tank if initial discharge was constant. Real duration, when h varies, is twice that time.
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