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AravindG
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A cylindrical tank of height 0.4 m is open at the top and has a diameter 0.16 m.Water is filled in it upto a height of 0.16 m .Calculate the time taken to empty the tank through a hole of radius 5x10^3m in its bottom?
 2 years ago
 2 years ago
AravindG Group Title
A cylindrical tank of height 0.4 m is open at the top and has a diameter 0.16 m.Water is filled in it upto a height of 0.16 m .Calculate the time taken to empty the tank through a hole of radius 5x10^3m in its bottom?
 2 years ago
 2 years ago

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AravindG Group TitleBest ResponseYou've already chosen the best response.0
@VincentLyon.Fr , @ash2326 , @waterineyes
 2 years ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
First, use Torricelli's law to determine speed of water in the hole and rate of flow. \(v=\sqrt{2gh}\)
 2 years ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
Is the answer 45.80 s ?
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
i didnt get tht :O
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
i got 2.8 :P
 2 years ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
How?
 2 years ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
h is variable
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
then how ?
 2 years ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
Total volume is 3.217 L, right?
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
i got 3.14x10^4
 2 years ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
Try again. radius is 0.08m and height is 0.16m
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
3.21x10^3
 2 years ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
now escape velocity is \(v=\sqrt{2gh}\)
 2 years ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
and discharge is v multiplied by area of hole.
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
v is velocity ryt?
 2 years ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
yep
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
so how do we bring in volume?
 2 years ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
time taken is: volume / discharge you should find 22.9s
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
but isnt h varying?
 2 years ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
Yes, but we can get round this difficulty
 2 years ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
Do you find the same values?
 2 years ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
initial escape velocity is v=root(2g hmax) discharge is v multiplied by area of hole. time taken is: volume / discharge you should find 22.9s This is the time it would take to empty the tank if initial discharge was constant. Real duration, when h varies, is twice that time.
 2 years ago
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