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AravindG
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A cylindrical tank of height 0.4 m is open at the top and has a diameter 0.16 m.Water is filled in it upto a height of 0.16 m .Calculate the time taken to empty the tank through a hole of radius 5x10^3m in its bottom?
 one year ago
 one year ago
AravindG Group Title
A cylindrical tank of height 0.4 m is open at the top and has a diameter 0.16 m.Water is filled in it upto a height of 0.16 m .Calculate the time taken to empty the tank through a hole of radius 5x10^3m in its bottom?
 one year ago
 one year ago

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AravindG Group TitleBest ResponseYou've already chosen the best response.0
@VincentLyon.Fr , @ash2326 , @waterineyes
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
First, use Torricelli's law to determine speed of water in the hole and rate of flow. \(v=\sqrt{2gh}\)
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
Is the answer 45.80 s ?
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
i didnt get tht :O
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
i got 2.8 :P
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
How?
 one year ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
h is variable
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
then how ?
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
Total volume is 3.217 L, right?
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
i got 3.14x10^4
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
Try again. radius is 0.08m and height is 0.16m
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
3.21x10^3
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
ok
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
now escape velocity is \(v=\sqrt{2gh}\)
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
and discharge is v multiplied by area of hole.
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
v is velocity ryt?
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
yep
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
so how do we bring in volume?
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
time taken is: volume / discharge you should find 22.9s
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
but isnt h varying?
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
Yes, but we can get round this difficulty
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
Do you find the same values?
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
initial escape velocity is v=root(2g hmax) discharge is v multiplied by area of hole. time taken is: volume / discharge you should find 22.9s This is the time it would take to empty the tank if initial discharge was constant. Real duration, when h varies, is twice that time.
 one year ago
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