anonymous
  • anonymous
How do i simplify this without using the 6 up in the Sqrt...
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
cwrw238
  • cwrw238
64 is a multiple of 2 2*2*2*2*2*2 sixth root of 64 = 2 now you need to find 6th root of a^3 and b*3
anonymous
  • anonymous
how do i do that?

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cwrw238
  • cwrw238
you use one of exponent rules (x^a)^b = x^ ab 6th root as an exponent is 1/6 so 6th root of a^3 = a(3*1/6) = a^(1/2) in same way we get b(1/2)
cwrw238
  • cwrw238
now put them together to get yur answer
anonymous
  • anonymous
so its like 2a^1/2b^1/2 or do i put a square root on that?
cwrw238
  • cwrw238
luv your name!
cwrw238
  • cwrw238
yea you got it
anonymous
  • anonymous
\o/
anonymous
  • anonymous
sweet, i actually understand the full concept now.
anonymous
  • anonymous
ok, now i got one where the first number doesnt work @cwrw238

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