anonymous
  • anonymous
In right triangle PRS, sin ∠P = (8/17) . What is tan ∠P? 1.8/17 2.8/15 3.15/17 4.17/15 5.15/8
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
cwrw238
  • cwrw238
lets draw it |dw:1343587644186:dw|
anonymous
  • anonymous
okay i kind of see where you are going with it but i still kind of don't understand it
cwrw238
  • cwrw238
sin P = opposite / hypotenuse = 8 /17 tan P = opposite / adjacent (PS) = 8 / PS you can find length of PS by pythagoras theorem - can you do that?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
i'm clueless to it
cwrw238
  • cwrw238
sorry i gotta go now for about 30 minutes - i'll help you more if you need it later
anonymous
  • anonymous
okay thank you
cwrw238
  • cwrw238
ok pythGoras theorem is for right angled trianlge which we/ve got here longest side squared = PR^2 = PS^2 + RS^2 plug in values: 17^2 = PS^2 + 8^2 so PS^2 = 17^2 - 8^2 = 289- 64 = 225 PS = sqrt(225) = 15 ok so tan P = 8/15
cwrw238
  • cwrw238
thats it
anonymous
  • anonymous
okay after reviewing it i understand it so much better thank you for your help and time
cwrw238
  • cwrw238
hopy you've learned something useful to you
cwrw238
  • cwrw238
your welcome

Looking for something else?

Not the answer you are looking for? Search for more explanations.