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cieralee1 Group Title

In right triangle PRS, sin ∠P = (8/17) . What is tan ∠P? 1.8/17 2.8/15 3.15/17 4.17/15 5.15/8

  • one year ago
  • one year ago

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  1. cwrw238 Group Title
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    lets draw it |dw:1343587644186:dw|

    • one year ago
  2. cieralee1 Group Title
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    okay i kind of see where you are going with it but i still kind of don't understand it

    • one year ago
  3. cwrw238 Group Title
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    sin P = opposite / hypotenuse = 8 /17 tan P = opposite / adjacent (PS) = 8 / PS you can find length of PS by pythagoras theorem - can you do that?

    • one year ago
  4. cieralee1 Group Title
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    i'm clueless to it

    • one year ago
  5. cwrw238 Group Title
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    sorry i gotta go now for about 30 minutes - i'll help you more if you need it later

    • one year ago
  6. cieralee1 Group Title
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    okay thank you

    • one year ago
  7. cwrw238 Group Title
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    ok pythGoras theorem is for right angled trianlge which we/ve got here longest side squared = PR^2 = PS^2 + RS^2 plug in values: 17^2 = PS^2 + 8^2 so PS^2 = 17^2 - 8^2 = 289- 64 = 225 PS = sqrt(225) = 15 ok so tan P = 8/15

    • one year ago
  8. cwrw238 Group Title
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    thats it

    • one year ago
  9. cieralee1 Group Title
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    okay after reviewing it i understand it so much better thank you for your help and time

    • one year ago
  10. cwrw238 Group Title
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    hopy you've learned something useful to you

    • one year ago
  11. cwrw238 Group Title
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    your welcome

    • one year ago
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