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A bacteria culture will grow from 400 to 5000 in 1 1/4 hours.
a) Find the constant k for this bacteria using growth formula, y=ne^kt, and write the growth equation.
b)Use your equation to predict how much longer it will take the 5000 bacteria to become 15000 bacteria.
 one year ago
 one year ago
A bacteria culture will grow from 400 to 5000 in 1 1/4 hours. a) Find the constant k for this bacteria using growth formula, y=ne^kt, and write the growth equation. b)Use your equation to predict how much longer it will take the 5000 bacteria to become 15000 bacteria.
 one year ago
 one year ago

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LibnizBest ResponseYou've already chosen the best response.1
n is beginning y is end
 one year ago

GOODMANBest ResponseYou've already chosen the best response.1
Correct. Dont know where to start on this problem.
 one year ago

LibnizBest ResponseYou've already chosen the best response.1
so in beginning there was 400
 one year ago

LibnizBest ResponseYou've already chosen the best response.1
t represent time , what time do you see there
 one year ago

GOODMANBest ResponseYou've already chosen the best response.1
k. so the equation is \[5000=400e ^{k(1.25)}\]
 one year ago

GOODMANBest ResponseYou've already chosen the best response.1
Hmm...take ln of both sides and bring exponent down then solve for k?
 one year ago

GOODMANBest ResponseYou've already chosen the best response.1
\[\ln(5000)=k(1.25)\ln400e\]
 one year ago

GOODMANBest ResponseYou've already chosen the best response.1
How would you set it up?
 one year ago

LibnizBest ResponseYou've already chosen the best response.1
I would divide both sides by 400 first
 one year ago

LibnizBest ResponseYou've already chosen the best response.1
\[5000/400=e ^{k(1.25)}\]
 one year ago

LibnizBest ResponseYou've already chosen the best response.1
now take ln of both sides
 one year ago

GOODMANBest ResponseYou've already chosen the best response.1
\[\ln(25/2)=k(1.25)lne\]
 one year ago

GOODMANBest ResponseYou've already chosen the best response.1
Wouldnt ln and e cancel eachother out though?
 one year ago

GOODMANBest ResponseYou've already chosen the best response.1
So basically, to get k, you would divide ln(25/2) by 1.25?
 one year ago

GOODMANBest ResponseYou've already chosen the best response.1
lol thanks. so to rewrite the equation, i would just plug everything in?
 one year ago

GOODMANBest ResponseYou've already chosen the best response.1
\[5000=400e ^{2.02(1.25)}\]
 one year ago

LibnizBest ResponseYou've already chosen the best response.1
close but to be more general you use t instead of specific time
 one year ago

GOODMANBest ResponseYou've already chosen the best response.1
Ohh okay. So intead of 1.25, just t?
 one year ago

LibnizBest ResponseYou've already chosen the best response.1
that way you can find y for any t value you plug in
 one year ago

GOODMANBest ResponseYou've already chosen the best response.1
So on b, you would plug n as 5000 and y as 1500?
 one year ago

LibnizBest ResponseYou've already chosen the best response.1
exactly , this time you are finding the 't'
 one year ago

GOODMANBest ResponseYou've already chosen the best response.1
Because you divide by 5000 on both sides. Getting: \[\ln(3)=(2.02)\ln(e)\]
 one year ago

GOODMANBest ResponseYou've already chosen the best response.1
And then divide by ln(2.02) Did I do it right?
 one year ago

GOODMANBest ResponseYou've already chosen the best response.1
Thank God. lol. But would that be like 5 mins?
 one year ago

LibnizBest ResponseYou've already chosen the best response.1
it will take .5438 hours
 one year ago

GOODMANBest ResponseYou've already chosen the best response.1
Nice to meet you too. It was good working with you.
 one year ago
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