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anonymous
 3 years ago
A bacteria culture will grow from 400 to 5000 in 1 1/4 hours.
a) Find the constant k for this bacteria using growth formula, y=ne^kt, and write the growth equation.
b)Use your equation to predict how much longer it will take the 5000 bacteria to become 15000 bacteria.
anonymous
 3 years ago
A bacteria culture will grow from 400 to 5000 in 1 1/4 hours. a) Find the constant k for this bacteria using growth formula, y=ne^kt, and write the growth equation. b)Use your equation to predict how much longer it will take the 5000 bacteria to become 15000 bacteria.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0n is beginning y is end

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Correct. Dont know where to start on this problem.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so in beginning there was 400

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0t represent time , what time do you see there

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0k. so the equation is \[5000=400e ^{k(1.25)}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0your job is to find k

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Hmm...take ln of both sides and bring exponent down then solve for k?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\ln(5000)=k(1.25)\ln400e\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0How would you set it up?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I would divide both sides by 400 first

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[5000/400=e ^{k(1.25)}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now take ln of both sides

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\ln(25/2)=k(1.25)lne\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Wouldnt ln and e cancel eachother out though?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So basically, to get k, you would divide ln(25/2) by 1.25?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lol thanks. so to rewrite the equation, i would just plug everything in?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[5000=400e ^{2.02(1.25)}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0close but to be more general you use t instead of specific time

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ohh okay. So intead of 1.25, just t?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[y=400e ^{2.02(t)}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that way you can find y for any t value you plug in

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So on b, you would plug n as 5000 and y as 1500?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0exactly , this time you are finding the 't'

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Because you divide by 5000 on both sides. Getting: \[\ln(3)=(2.02)\ln(e)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0And then divide by ln(2.02) Did I do it right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thank God. lol. But would that be like 5 mins?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it will take .5438 hours

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Nice to meet you too. It was good working with you.
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