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GOODMAN
Group Title
A bacteria culture will grow from 400 to 5000 in 1 1/4 hours.
a) Find the constant k for this bacteria using growth formula, y=ne^kt, and write the growth equation.
b)Use your equation to predict how much longer it will take the 5000 bacteria to become 15000 bacteria.
 2 years ago
 2 years ago
GOODMAN Group Title
A bacteria culture will grow from 400 to 5000 in 1 1/4 hours. a) Find the constant k for this bacteria using growth formula, y=ne^kt, and write the growth equation. b)Use your equation to predict how much longer it will take the 5000 bacteria to become 15000 bacteria.
 2 years ago
 2 years ago

This Question is Closed

Libniz Group TitleBest ResponseYou've already chosen the best response.1
\[y=ne^{kt}\]
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
n is beginning y is end
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Correct. Dont know where to start on this problem.
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
so in beginning there was 400
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
so plug in 400 for n
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
plug in what for y?
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
\[5000=400 e^{kt}\]
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
t represent time , what time do you see there
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
t would go in as 1.5
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
I knew that.
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
let's go with that
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
k. so the equation is \[5000=400e ^{k(1.25)}\]
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
your job is to find k
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Hmm...take ln of both sides and bring exponent down then solve for k?
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
\[\ln(5000)=k(1.25)\ln400e\]
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
not what I would do
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
How would you set it up?
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
I would divide both sides by 400 first
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
\[5000/400=e ^{k(1.25)}\]
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
now take ln of both sides
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
\[\ln(25/2)=k(1.25)lne\]
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Wouldnt ln and e cancel eachother out though?
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
So basically, to get k, you would divide ln(25/2) by 1.25?
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
lol thanks. so to rewrite the equation, i would just plug everything in?
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
\[5000=400e ^{2.02(1.25)}\]
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
close but to be more general you use t instead of specific time
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Ohh okay. So intead of 1.25, just t?
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
\[y=400e ^{2.02(t)}\]
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
that way you can find y for any t value you plug in
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
So on b, you would plug n as 5000 and y as 1500?
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
exactly , this time you are finding the 't'
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
I got 0.5438
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Because you divide by 5000 on both sides. Getting: \[\ln(3)=(2.02)\ln(e)\]
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
And then divide by ln(2.02) Did I do it right?
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Thank God. lol. But would that be like 5 mins?
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
it will take .5438 hours
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
okie dokes.
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Thanks youuuu!!
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
nice to meet you
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Nice to meet you too. It was good working with you.
 2 years ago
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