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GiggleSquid

  • 2 years ago

simplify this (image attached)

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  1. GiggleSquid
    • 2 years ago
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  2. GiggleSquid
    • 2 years ago
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    how do i get the 125 down?

  3. lgbasallote
    • 2 years ago
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    well \[\huge 125 = 5^3\] does that help?

  4. GiggleSquid
    • 2 years ago
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    do i use that with the 6?

  5. lgbasallote
    • 2 years ago
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    yes

  6. lgbasallote
    • 2 years ago
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    actually...it depends on what you meant...

  7. GiggleSquid
    • 2 years ago
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    im a bit lost

  8. cwrw238
    • 2 years ago
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    (5^3)^(1/6) = 5 ^(3/6) = 5^(1/2) and (a^15)^(1/6) = ?

  9. cwrw238
    • 2 years ago
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    recall that 6th root = ^ (1/6)

  10. GiggleSquid
    • 2 years ago
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    so a^5/2 ?

  11. cwrw238
    • 2 years ago
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    yes

  12. lgbasallote
    • 2 years ago
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    dont forget to simplify the whole thing

  13. GiggleSquid
    • 2 years ago
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    how do i simplify 5^1/2 a^5/2

  14. GiggleSquid
    • 2 years ago
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    @lgbasallote

  15. lgbasallote
    • 2 years ago
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    \[\huge x^{1/2} \times y^{1/2} \implies (xy)^{1/2} \implies \sqrt{xy}\]

  16. GiggleSquid
    • 2 years ago
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    so i should put a square root over the five? err...

  17. GiggleSquid
    • 2 years ago
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    or is it liike 5a^?/2

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