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\[a ^{2}\sqrt{8} /\sqrt{16a^{2}}\]

\[\sqrt{8} = \sqrt{4}*\sqrt{2}\]
\[\sqrt{16a^{2}} = \sqrt{16}*\sqrt{a^{2}}\]
that should help

not really lol sorry

what is sqrt(4) ?

what??

do you know what the the square root of 4 is?

ok how about 16?

2 and 4...

yep, now a^2

\[\sqrt{16} = \sqrt{4^{2}} = 4\]
so for any number
\[\sqrt{a^{2}} = a\]

lol ur not hepling my question tho...

dont u just multiply the top by the bottom???

you want someone to answer your problem?
find the square root of 14 of a^2 and sqrt(4)*sqrt(2)

np :)
now just reduce to get final answer

lol thanks!!