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## katiebugg 3 years ago ok simplify

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1. katiebugg

$a ^{2}\sqrt{8} /\sqrt{16a^{2}}$

2. dumbcow

$\sqrt{8} = \sqrt{4}*\sqrt{2}$ $\sqrt{16a^{2}} = \sqrt{16}*\sqrt{a^{2}}$ that should help

3. katiebugg

not really lol sorry

4. dumbcow

what is sqrt(4) ?

5. katiebugg

what??

6. dumbcow

do you know what the the square root of 4 is?

7. dumbcow

ok how about 16?

8. katiebugg

2 and 4...

9. dumbcow

yep, now a^2

10. katiebugg

@dumbcow u lost me a long time ago

11. dumbcow

$\sqrt{16} = \sqrt{4^{2}} = 4$ so for any number $\sqrt{a^{2}} = a$

12. katiebugg

lol ur not hepling my question tho...

13. dumbcow

well to simplify the problem , you need to simplify or get rid of the radicals, that is what im trying to help you do

14. katiebugg

dont u just multiply the top by the bottom???

15. panlac01

you want someone to answer your problem? find the square root of 14 of a^2 and sqrt(4)*sqrt(2)

16. dumbcow

$\frac{\sqrt{8} a^{2}}{\sqrt{16a^{2}}} = \frac{\sqrt{4}\sqrt{2}a^{2}}{\sqrt{16}\sqrt{a^{2}}} = \frac{2\sqrt{2}a^{2}}{4a}$

17. katiebugg

@dumbcow ok now i seee ima sorry about that

18. dumbcow

np :) now just reduce to get final answer

19. katiebugg

lol thanks!!

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