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katiebugg Group TitleBest ResponseYou've already chosen the best response.1
\[a ^{2}\sqrt{8} /\sqrt{16a^{2}}\]
 one year ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
\[\sqrt{8} = \sqrt{4}*\sqrt{2}\] \[\sqrt{16a^{2}} = \sqrt{16}*\sqrt{a^{2}}\] that should help
 one year ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.1
not really lol sorry
 one year ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
what is sqrt(4) ?
 one year ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
do you know what the the square root of 4 is?
 one year ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
ok how about 16?
 one year ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.1
2 and 4...
 one year ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
yep, now a^2
 one year ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.1
@dumbcow u lost me a long time ago
 one year ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
\[\sqrt{16} = \sqrt{4^{2}} = 4\] so for any number \[\sqrt{a^{2}} = a\]
 one year ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.1
lol ur not hepling my question tho...
 one year ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
well to simplify the problem , you need to simplify or get rid of the radicals, that is what im trying to help you do
 one year ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.1
dont u just multiply the top by the bottom???
 one year ago

panlac01 Group TitleBest ResponseYou've already chosen the best response.0
you want someone to answer your problem? find the square root of 14 of a^2 and sqrt(4)*sqrt(2)
 one year ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{\sqrt{8} a^{2}}{\sqrt{16a^{2}}} = \frac{\sqrt{4}\sqrt{2}a^{2}}{\sqrt{16}\sqrt{a^{2}}} = \frac{2\sqrt{2}a^{2}}{4a}\]
 one year ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.1
@dumbcow ok now i seee ima sorry about that
 one year ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
np :) now just reduce to get final answer
 one year ago

katiebugg Group TitleBest ResponseYou've already chosen the best response.1
lol thanks!!
 one year ago
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