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typo, the log product should read log ((X+4)(x-4))

so now we can cgange the log by change of bass formula

change*

Hmm..thats where i got stuck. How do you do that?

\[\Large \log _{a}(b)=\frac{\ln(a)}{\ln{b}}\]

it is upto use to change it to any base .i used natural log whose base is e

Hmm...i think i get it.

ok

I had another one similar to it:
7^(5x-2)=5^(3-x)

I know you have to log both sides.

yes take ln of both sides

let me do the your question now using above property

now use calculator to find values of ln7 and ln5

ln7=1.946
ln5=1.609

ln(7)=1.94
ln(5)=1.60
(5x-2)*(1.69)=(3-x)1.609

can you solve this !!

a typo !
correct is
(5x-2)*(1.94)=(3-x)1.609

ok.
u mean this
\[\Large \sqrt{3x-2}-\sqrt{x}=1\]
??

Correct :)

ok
taking square of both sides

Waaiit.

Sorry, it was 3x-3

ok

Itsokay i will pretend the 2 was really 3

ok

Sorry :(

its ok :)
i am notorious for typo mistakes ask anyone here :P

Wow, thats good enough! Thank you soo much for your help. I learned a lot!

yw:)

\[\sqrt(3x-2)-\sqrt(x)=1\]
add \[\sqrt(x)\] in both sides