anonymous
  • anonymous
Please help! cos67degrees 30'= ?
Mathematics
schrodinger
  • schrodinger
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schrodinger
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anonymous
  • anonymous
0.890
anonymous
  • anonymous
Thanks!
anonymous
  • anonymous
You are welcome.

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anonymous
  • anonymous
\[a. \sqrt{2-\sqrt{2}} \] \[b. \sqrt{2+\sqrt{2}}/2\] \[c. \sqrt{2+\sqrt{2}}\] \[d. \sqrt{2-\sqrt{2}}/2\] @muhammad9t5 Your answer doesn't match with the options :/
anonymous
  • anonymous
wait
anonymous
  • anonymous
can you post screenshot of question?
anonymous
  • anonymous
b. \[(\sqrt{2+\sqrt{2}})/2\] d. \[(\sqrt{2-\sqrt{2}})/2\]
anonymous
  • anonymous
Sorry, I messed those two up
anonymous
  • anonymous
\[67^{\circ} 30' = 67 + \frac{1}{2} \implies (\frac{135}{2})^{\circ}\]
anonymous
  • anonymous
Is there only one cos in your question @IloveCharlie
anonymous
  • anonymous
you can check that b is a nearly answer.
anonymous
  • anonymous
Yes, @waterineyes, only one cos
anonymous
  • anonymous
Can I get more help for this one? sin67degrees 30'= a., b., c., or d.?
anonymous
  • anonymous
@muhammad9t5 @waterineyes
anonymous
  • anonymous
yes
anonymous
  • anonymous
is the answer 1.42?
anonymous
  • anonymous
Can you please show me how you got that?
anonymous
  • anonymous
yes sin67+30/60 0.920+1/2 0.920+0.5=1.42
anonymous
  • anonymous
and that matches with? :/ sorry
anonymous
  • anonymous
that's confusing me too.
anonymous
  • anonymous
:(
anonymous
  • anonymous
Do you know what 1.42 matches with? a., b., c., or d.? I can't figure it out @waterineyes
anonymous
  • anonymous
?
anonymous
  • anonymous
Ok... well... I guess I'll close the question then
anonymous
  • anonymous
Thanks guys

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