Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

uranium hexafluoride is a solid at room temperature, but it boils at \(56^o C\).determine the density of uranium hexafluoride at \(60^o C\) and 745 torr. i know d = m/v and PV = nRT but how can i use them here? or do i even use them here?

Chemistry
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
you can solve for n and get the mass using the periodic table and then you can solve for v
will you please elaborate?
Just get m and v :P

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

how to get V?
and m
Use the other formula to find them ^_^
how the heck can i get m o.O
and V
i dont think the "other formulas" can be applied
can you demonstrate how>
wats torr
if i remember right 760 torr = 1 atm...torr is a unit of measurement for pressure
p=745 torr v=? n=? R=? T=60-56 (i think) d=? (looking for) m=? v=?
Oh...Waht about Mm?
on what @zbay say.
but you still need m huh
do you know \[p =\rho \times r \times T \div M\] where rho is density and M is molecular mass
P is pressure
since n= m/M , you can get m/V = rho
uhhh could you rewrite that equation you wrote? kinda vague... \[\huge P = \frac{\rho RT}{M}\]
is that right?
ya
looks like it works :)
how did you get this formula again?
n=m/M right?
oh i see now
so \[\frac{PM}{RT} = \rho\] right? R = 0.0821
ya exactly
so which T am i going to use?
60?
probably, because that's the one that applies to this situation
the temperature at which u have to find density
so what's 56 for? just a distraction?
ya I guess
hmm then i need to convert torr into atm and C into K right
yup and 1 torr = 1 atm
i thought it was 760 torr = 1 atm o.O
oo idk
hmm okay thanks
what would be the unit?
i got the answer as 126.76 g/L is that right?
i dunno
set n to 1 and solve for V then you take the molar mass of the molecule you are looking at and calculate your density
R is a constant.

Not the answer you are looking for?

Search for more explanations.

Ask your own question