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schmidtdancerBest ResponseYou've already chosen the best response.0
dw:1343661876978:dw
 one year ago

agentx5Best ResponseYou've already chosen the best response.3
Ah! This is one best though of visually, let me make you a graph:
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
If you find the function continuous, then you may just plug 3 for \(x\) by the way.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Let's see how the graph is..
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
Ok. If I plug in 3, I get 3 sqrt(0)
 one year ago

agentx5Best ResponseYou've already chosen the best response.3
What you need are numbers slightly less than 3, like 2.9999999999999
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Looks like we can plug in values less than \(3\).
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Because it is a left handed limit, we may plug numbers like agentx5 said :)
 one year ago

agentx5Best ResponseYou've already chosen the best response.3
That  sign above the limit means "numbers from the left hand side limit" or the number slightly less than 3 (but as close as you can get)
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
ok! can you show how I would solve it
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
Ok i understand that
 one year ago

telliott99Best ResponseYou've already chosen the best response.0
About your graph, notice what happens to the function for x > 3
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
So how would I solve the limit?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
By plugging numbers slightly less than 3.
 one year ago

agentx5Best ResponseYou've already chosen the best response.3
@telliott99 , I know... look at the notation for imaginary and real...
 one year ago

telliott99Best ResponseYou've already chosen the best response.0
Just saying the graph is not correct. It doesn't have a hole in it. And do what @ParthKohli says
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
\[ \begin{array}{lr} x & f(x) \\ \hline 2.5 & \\ 2.9 \\ 2.999 \\ 2.99999\end{array} \] Fill the f(x)'s.
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
for 2.5, f(x) would be 4.145
 one year ago

agentx5Best ResponseYou've already chosen the best response.3
And and as you get closer and closer to 2.999999999999? Every closer to 3 from the "just under" side and you'll approach some limit.
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
Ok can you help find the limit now? Like I understand how to find that, i just dont haeve time to find them all
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Calculator, Schmidt.
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
so agentx5, I should just use 2.999999 to find the limit?
 one year ago

agentx5Best ResponseYou've already chosen the best response.3
Or if you prefer, 2.99999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999... Get the point? :P
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Looks like its getting closer to 7.5, but let's see it for more values.
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
Ok! I think its going to be 7.5
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Are you sure? Try for 2.9999999 and 2.999999999999999. So on.
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
I just tried for that
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
can someone tell me if im right
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
I am too lazy to do so :/
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
plz! i really need your help..
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
All right :) let me check it out on Wolfram.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
@agentx5 Where is the graph?
 one year ago

agentx5Best ResponseYou've already chosen the best response.3
Here's the algebra trick, you need to find what y would be when x=3. You can't do this normally but... \(x\sqrt{(3+x)(3x)}\) , For what solutions does y = 0? Well, 0, +3 and 3. So... ;) Replacing with a better graph (more accurate, real #'s only): dw:1343662913297:dw
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
ok thx @agentx5 so what would the limit be for this probb?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
I was actually surprised how I was plugging values and getting it approaching something else. Hence, I asked.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
The limit was getting smaller and smaller. ;)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
You may find from the graph, actually.dw:1343663313029:dw
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
What is \(y\) approaching in the graph? ^
 one year ago

agentx5Best ResponseYou've already chosen the best response.3
With the limit shown... dw:1343663226621:dw
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
like 2 or 3 right?
 one year ago

agentx5Best ResponseYou've already chosen the best response.3
I actually had my imaginary lines going the wrong way @telliott99 and the circles were too high in the original sketch (they're on the xaxis), I stand corrected. Although I'm not sure that's what you meant. ;)
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
Guys do you know the actual limit?
 one year ago

agentx5Best ResponseYou've already chosen the best response.3
And I'm trying to help you learn visually what's going on so you're not lost here
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
Yeah I do see it visually,
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
is the limit around 2 or 3
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
wait it looks around 0
 one year ago

agentx5Best ResponseYou've already chosen the best response.3
\[\lim_{x \rightarrow 3^}\] What is the output of the function approaching? The input gets closer to 3 from the "slightly less" side.
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
as 3 approaches 3 from the left, the y value is 0, right?
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
sorry i meant, as x approaches 3
 one year ago

agentx5Best ResponseYou've already chosen the best response.3
Or using the analytical method, as you plug in larger and larger 2.9999999999999999...'s you get smaller and smaller numbers. Infinitesimally small. To the point gets damned close to zero. Thus the limit is zero, correct.
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
ok so the limit for this function is 0? :D
 one year ago

agentx5Best ResponseYou've already chosen the best response.3
The reason you can't just substitute 3 in place of x, officially is because you might have one like this: \[\lim_{x \rightarrow 1} = \frac{1}{1x}\] Look what happens if you plug in 1?
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
But, limit is 0 right? and yes the ddenominator bneomes 0.. not possible
 one year ago

agentx5Best ResponseYou've already chosen the best response.3
In this case your left and your right hand limits are going in opposite directions, and the limit doesn't exist. dw:1343663845294:dw And yes, twice to the above post. :)
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
wait so the limit is DNE? or zero!?!
 one year ago

agentx5Best ResponseYou've already chosen the best response.3
For your original problem, Zero. For the one I just asked you, trying to get you to learn, Does Not Exist.
 one year ago

agentx5Best ResponseYou've already chosen the best response.3
You will see DNE problems, I can guarantee you.
 one year ago

schmidtdancerBest ResponseYou've already chosen the best response.0
Oh yeah, I know!:)
 one year ago
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