anonymous
  • anonymous
9x^2+30x+25=64
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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ParthKohli
  • ParthKohli
A good start is subtracting 64 from both sides.\[ \color{Black}{\Rightarrow 9x^2 + 3x + 25 - 64 = 0}\] Simplify, and solve the quadratic equation.
anonymous
  • anonymous
the 9x^2 is what I am confused about.
Ganpat
  • Ganpat
confused ??

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Ganpat
  • Ganpat
u can solve it by factorization...
anonymous
  • anonymous
(9x^2+3x)(25-64)
Ganpat
  • Ganpat
9x2+30x+25=64 9x2+30x+25-64 = 0 9x2+30x-39 = 0 9x2 -9x + 39x -39 = 0 9x(x-1) +39 (x-1) = 0 (9x +39) (x-1) = 0 so, x = -39/9 and x =1....
anonymous
  • anonymous
sorry, but I do know the answer involves imaginary numbers.
anonymous
  • anonymous
Actually no... The solutions for x as an answer does not involve imaginary #'s, and it's not 59/3
anonymous
  • anonymous
@Ganpat is correct.
anonymous
  • anonymous
ah..so my answer was wrong...sorry
anonymous
  • anonymous
With the imaginary line, it's the intersection: |dw:1343664593480:dw|
anonymous
  • anonymous
The answer in the back of the book is \[x=(-10+2i \sqrt14)/6, (-10-2i \sqrt14)/6 \] I just can't figure out how it got there.
anonymous
  • anonymous
The blue line is (3x+5)^2 The imaginary line is 64i
anonymous
  • anonymous
That answer is crazy, this has solvable real number values. Yes you can combine those to get X, but why?
anonymous
  • anonymous
In this case I'd say either the problem was written down for us incorrectly/incomplete-directions, or the book is making it a whole lot harder than it needs be...
anonymous
  • anonymous
i do not know.
anonymous
  • anonymous
:-S Go with what @Ganpat said, unless there's something missing or incorrect here with regards to the question and it's directions as you wrote it here. He's 100% correct.
anonymous
  • anonymous
Plug in those values for x and you'll it works.
Ganpat
  • Ganpat
@agentx5 : when did i say that ? :D.. lol
anonymous
  • anonymous
Huh? o_O
Ganpat
  • Ganpat
kidding dude !! :)

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