## a.galvan2 Group Title 9x^2+30x+25=64 2 years ago 2 years ago

1. ParthKohli Group Title

A good start is subtracting 64 from both sides.$\color{Black}{\Rightarrow 9x^2 + 3x + 25 - 64 = 0}$ Simplify, and solve the quadratic equation.

2. a.galvan2 Group Title

the 9x^2 is what I am confused about.

3. Ganpat Group Title

confused ??

4. Ganpat Group Title

u can solve it by factorization...

5. BougyMan Group Title

(9x^2+3x)(25-64)

6. Ganpat Group Title

9x2+30x+25=64 9x2+30x+25-64 = 0 9x2+30x-39 = 0 9x2 -9x + 39x -39 = 0 9x(x-1) +39 (x-1) = 0 (9x +39) (x-1) = 0 so, x = -39/9 and x =1....

7. a.galvan2 Group Title

sorry, but I do know the answer involves imaginary numbers.

8. agentx5 Group Title

Actually no... The solutions for x as an answer does not involve imaginary #'s, and it's not 59/3

9. agentx5 Group Title

@Ganpat is correct.

10. cornitodisc Group Title

11. agentx5 Group Title

With the imaginary line, it's the intersection: |dw:1343664593480:dw|

12. a.galvan2 Group Title

The answer in the back of the book is $x=(-10+2i \sqrt14)/6, (-10-2i \sqrt14)/6$ I just can't figure out how it got there.

13. agentx5 Group Title

The blue line is (3x+5)^2 The imaginary line is 64i

14. agentx5 Group Title

That answer is crazy, this has solvable real number values. Yes you can combine those to get X, but why?

15. agentx5 Group Title

In this case I'd say either the problem was written down for us incorrectly/incomplete-directions, or the book is making it a whole lot harder than it needs be...

16. a.galvan2 Group Title

i do not know.

17. agentx5 Group Title

:-S Go with what @Ganpat said, unless there's something missing or incorrect here with regards to the question and it's directions as you wrote it here. He's 100% correct.

18. agentx5 Group Title

Plug in those values for x and you'll it works.

19. Ganpat Group Title

@agentx5 : when did i say that ? :D.. lol

20. agentx5 Group Title

Huh? o_O

21. Ganpat Group Title

kidding dude !! :)