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agentx5
Group Title
Find the error?
Q: Find the distance traveled by a particle with position (x, y) as t varies in the given time interval.
x = 2sin\(^2\) t, y = 2cos\(^2\) t, 0 ≤ t ≤ 4π
I can't see what I did wrong here, posting image below. Any idea @TuringTest? The derivatives look ok...
 one year ago
 one year ago
agentx5 Group Title
Find the error? Q: Find the distance traveled by a particle with position (x, y) as t varies in the given time interval. x = 2sin\(^2\) t, y = 2cos\(^2\) t, 0 ≤ t ≤ 4π I can't see what I did wrong here, posting image below. Any idea @TuringTest? The derivatives look ok...
 one year ago
 one year ago

This Question is Open

agentx5 Group TitleBest ResponseYou've already chosen the best response.0
*Fixed the formatting syntax in the question
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=8pi
 one year ago

agentx5 Group TitleBest ResponseYou've already chosen the best response.0
It's a full two revolutions, obviously. What stumps me is what I could have done incorrect here when the other problem around it are ok... *goes to see your link*
 one year ago

agentx5 Group TitleBest ResponseYou've already chosen the best response.0
8\(\pi\)? o_O What about it?
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
why ... what is the answer?
 one year ago

amorim.fatec Group TitleBest ResponseYou've already chosen the best response.1
A smart way to see this problem is check that \[x ^{2}+y^{2}=4\]. This is an equation for the circunference with radius R=2. Since \[4 \pi \] means two revolutions, the length of the circunference is \[S=2\pi R\] then the distance traveled is \[8\pi \]. Note that the displacement is zero, because the initial and end position are same while the distance traveled is not zero in this case.
 one year ago
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