Let's go over the derivation of\[\sum_{i=1}^{n}i^2=\frac{n(n+1)(2n+1)}{6}\]

Let's go over the derivation of\[\sum_{i=1}^{n}i^2=\frac{n(n+1)(2n+1)}{6}\]

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This could follow from Gauss' assertion that\[\sum_{i=1}^{n}i=\frac{n(n+1)}{2}\]

i don't remember the details. but i'm pretty sure u can find this in Spivaks' Calculus

It's easy to prove this by induction with your eyes closed, but I'm wondering how it's derived.

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