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Calcmathlete
 3 years ago
Let the solution (x, y, z) satisfy the following equations: x + y + z = 1, xy + xz + yx = 17, xyz = 15. If x < y < z, what is the value of: x  2y + 4z?
Calcmathlete
 3 years ago
Let the solution (x, y, z) satisfy the following equations: x + y + z = 1, xy + xz + yx = 17, xyz = 15. If x < y < z, what is the value of: x  2y + 4z?

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Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0And this is supposed to be a speed math question as in you should be able to do this in like 30 seconds...not sure how to do it though...

NotTim
 3 years ago
Best ResponseYou've already chosen the best response.0its also...vector like...

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0Seriously? That's like 5 questions that pertain to vectors when I have not learned them... :/

swissgirl
 3 years ago
Best ResponseYou've already chosen the best response.2well for starter the biggest lead is xyz=15 that shows me that there has to be a 1,3 and 5 involved

swissgirl
 3 years ago
Best ResponseYou've already chosen the best response.2next x+y+z=1 5+3+1=1

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0But when you plug it into xy + xz + yx, it doesn't work...

Hero
 3 years ago
Best ResponseYou've already chosen the best response.0I think that also fails the x < y < z

swissgirl
 3 years ago
Best ResponseYou've already chosen the best response.2well no u wld just switch around the variables that is no big deal

Hero
 3 years ago
Best ResponseYou've already chosen the best response.0Maybe let x = 5, y = 1, z = 3

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1Did you mistype the problem? Or is it correct as written? Should it be "xy + xz + yz = 17" instead of "xy + xz + yx = 17?"

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0That's what it says on the document...thinking it's a typo though...

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0Alright. I think it is just a typo. Thanks swiss!
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