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Let the solution (x, y, z) satisfy the following equations: x + y + z = 1, xy + xz + yx = 17, xyz = 15. If x < y < z, what is the value of: x  2y + 4z?
 one year ago
 one year ago
Let the solution (x, y, z) satisfy the following equations: x + y + z = 1, xy + xz + yx = 17, xyz = 15. If x < y < z, what is the value of: x  2y + 4z?
 one year ago
 one year ago

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CalcmathleteBest ResponseYou've already chosen the best response.0
And this is supposed to be a speed math question as in you should be able to do this in like 30 seconds...not sure how to do it though...
 one year ago

NotTimBest ResponseYou've already chosen the best response.0
its also...vector like...
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
Seriously? That's like 5 questions that pertain to vectors when I have not learned them... :/
 one year ago

swissgirlBest ResponseYou've already chosen the best response.2
well for starter the biggest lead is xyz=15 that shows me that there has to be a 1,3 and 5 involved
 one year ago

swissgirlBest ResponseYou've already chosen the best response.2
next x+y+z=1 5+3+1=1
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
But when you plug it into xy + xz + yx, it doesn't work...
 one year ago

HeroBest ResponseYou've already chosen the best response.0
I think that also fails the x < y < z
 one year ago

swissgirlBest ResponseYou've already chosen the best response.2
well no u wld just switch around the variables that is no big deal
 one year ago

HeroBest ResponseYou've already chosen the best response.0
Maybe let x = 5, y = 1, z = 3
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.1
Did you mistype the problem? Or is it correct as written? Should it be "xy + xz + yz = 17" instead of "xy + xz + yx = 17?"
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
That's what it says on the document...thinking it's a typo though...
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
Alright. I think it is just a typo. Thanks swiss!
 one year ago
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