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lgbasallote Group Title

If 116.34 grams of butane reacts completely with O2 in STP conditions, what is the mass (grams) of CO2(g) formed? do i use PV = nRT here?

  • 2 years ago
  • 2 years ago

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  1. GOODMAN Group Title
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    Sorry, im taking chem next year.

    • 2 years ago
  2. GOODMAN Group Title
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    @Mimi_x3 Help poor LG.

    • 2 years ago
  3. lgbasallote Group Title
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    boohoo

    • 2 years ago
  4. GOODMAN Group Title
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    I thought you were smart! You should know this! lol jk.

    • 2 years ago
  5. lgbasallote Group Title
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    no im not. im dyslexic

    • 2 years ago
  6. Kryten Group Title
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    i just woke up so lets start slowly.... :) first lets write down the equation of the reaction: 2 C4H10 + 13 O2 --> 8 CO2 + 10 H2O now lets start: n=m/M n(C4H10)= 116,34 g/58,124 gmol-1 = 2 mol n(CO2)/n(C4H10)= 8/2 = 4 n(CO2)= 4* n(C4H10) = 4* 2 mol = 8 mol m(CO2)= n(CO2)*M(CO2)= 8 mol * 44,009 gmol-1 = 352,072 g

    • 2 years ago
  7. lgbasallote Group Title
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    okay...how did you get that equation o.O

    • 2 years ago
  8. Kryten Group Title
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    well it states that butane reacts with O2 so it is combustion of butane and it states that butane COMPLETELY reacts with O2 so it is combustion with infinite amount of O2 so reaction is as i wrote it...

    • 2 years ago
  9. lgbasallote Group Title
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    so im guessing c4H10 is butane

    • 2 years ago
  10. Kryten Group Title
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    yep

    • 2 years ago
  11. lgbasallote Group Title
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    so what happened after? in the "let's start"

    • 2 years ago
  12. Kryten Group Title
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    you must learn if you already dont know homologous series: http://en.wikipedia.org/wiki/Homologous_series

    • 2 years ago
  13. lgbasallote Group Title
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    well anyway the equation wasnt that important since it was a given :S

    • 2 years ago
  14. Kryten Group Title
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    it is not what happened after lets start but what happened before it! in chemistry key to solving any task is to read few times what the task says and understand what is your goal... if you can see from the task what is your goal and your start line only thing you need to do is to find simpliest equation to come to your goal...

    • 2 years ago
  15. lgbasallote Group Title
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    well okay that reaction was given...so now what?

    • 2 years ago
  16. lgbasallote Group Title
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    we never studied homologous thingies so i doubt it'll appear in our quiz

    • 2 years ago
  17. Kryten Group Title
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    ok so you have reaction, now you need to see what are you asked to do... (homologous series is general culture question more than chemistry question...) your task states that you have certain amount of reactant at certain conditions and that you need to calculate amount of product so you always start to calculate moles since moles are equivalent and masses are not! so you first calculate amount of that reactant in moles! get me so far?

    • 2 years ago
  18. lgbasallote Group Title
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    hmm maybe a demonstration will

    • 2 years ago
  19. lgbasallote Group Title
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    hmm sorry i just cant get this >.< maybe i'll come back to this once i have gained more experience...maybe then i can understand it...i'll try easier questions for now

    • 2 years ago
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