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anonymous
 4 years ago
all solutions to
\(x^2+y=xy^2\)
\(y^2+x=yx^2\)
\(x\) , \(y\) are real numbers
anonymous
 4 years ago
all solutions to \(x^2+y=xy^2\) \(y^2+x=yx^2\) \(x\) , \(y\) are real numbers

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If we subtract them then it will work or not ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[(yx)(((x+y)+ 1) = xy(yx)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\implies 1  x  y = xy\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0S={(a;a)/ a in B}.....B={1;0;(1+sqrt(5))/2;(1sqrt(5))/2}

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@waterineyes u forgot the case \(y=x\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x^2  y^2  (xy) = xy(xy) (xy)(x+y 1+xy) = 0 => x+y1+xy = 0 => y = (1x)/(1+x) 1 + x =/= 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yeah in that case we cannot divide both sides..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i can't get other points

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.03 solutions from \(x=y\) and any from \(x+y+xy=1\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0For x = y there are three solutions we will get @mukushla ?? Asking..
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