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all solutions to
\(x^2+y=xy^2\)
\(y^2+x=yx^2\)
\(x\) , \(y\) are real numbers
 one year ago
 one year ago
all solutions to \(x^2+y=xy^2\) \(y^2+x=yx^2\) \(x\) , \(y\) are real numbers
 one year ago
 one year ago

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waterineyesBest ResponseYou've already chosen the best response.2
If we subtract them then it will work or not ??
 one year ago

waterineyesBest ResponseYou've already chosen the best response.2
\[(yx)(((x+y)+ 1) = xy(yx)\]
 one year ago

waterineyesBest ResponseYou've already chosen the best response.2
\[\implies 1  x  y = xy\]
 one year ago

NeemoBest ResponseYou've already chosen the best response.1
S={(a;a)/ a in B}.....B={1;0;(1+sqrt(5))/2;(1sqrt(5))/2}
 one year ago

mukushlaBest ResponseYou've already chosen the best response.0
@waterineyes u forgot the case \(y=x\)
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
x^2  y^2  (xy) = xy(xy) (xy)(x+y 1+xy) = 0 => x+y1+xy = 0 => y = (1x)/(1+x) 1 + x =/= 0
 one year ago

waterineyesBest ResponseYou've already chosen the best response.2
Yeah in that case we cannot divide both sides..
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.1
i can't get other points
 one year ago

mukushlaBest ResponseYou've already chosen the best response.0
3 solutions from \(x=y\) and any from \(x+y+xy=1\)
 one year ago

waterineyesBest ResponseYou've already chosen the best response.2
For x = y there are three solutions we will get @mukushla ?? Asking..
 one year ago
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