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mukushla
Group Title
all solutions to
\(x^2+y=xy^2\)
\(y^2+x=yx^2\)
\(x\) , \(y\) are real numbers
 one year ago
 one year ago
mukushla Group Title
all solutions to \(x^2+y=xy^2\) \(y^2+x=yx^2\) \(x\) , \(y\) are real numbers
 one year ago
 one year ago

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waterineyes Group TitleBest ResponseYou've already chosen the best response.2
If we subtract them then it will work or not ??
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.0
it will work
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.2
\[(yx)(((x+y)+ 1) = xy(yx)\]
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.2
\[\implies 1  x  y = xy\]
 one year ago

Neemo Group TitleBest ResponseYou've already chosen the best response.1
S={(a;a)/ a in B}.....B={1;0;(1+sqrt(5))/2;(1sqrt(5))/2}
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.0
@waterineyes u forgot the case \(y=x\)
 one year ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
x^2  y^2  (xy) = xy(xy) (xy)(x+y 1+xy) = 0 => x+y1+xy = 0 => y = (1x)/(1+x) 1 + x =/= 0
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.2
Yeah in that case we cannot divide both sides..
 one year ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
x=1, y=0 y=1. x=0
 one year ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
i can't get other points
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.0
3 solutions from \(x=y\) and any from \(x+y+xy=1\)
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.2
For x = y there are three solutions we will get @mukushla ?? Asking..
 one year ago
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