For which of the following species are the intermolecular interactions entirely due to dispersion forces? A) C2H6 B) CH3OCH3 C) NO2 D) H2S E) CaNO3

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For which of the following species are the intermolecular interactions entirely due to dispersion forces? A) C2H6 B) CH3OCH3 C) NO2 D) H2S E) CaNO3

Chemistry
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im thinking it would be the nonpolar molecule...so A?
yup its A ...... because its non polar ..... we have hydrogen bonding in B, C and D
thus instantaneous-induced dipole forces are present between non polar molecule :D

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Other answers:

c d and e dont have h-bonding o.O
sorry //// C , D , and E are POLAR
i misread the question :( //// but the answer is A
when flourine , chlorine, oxygen and nitrogen are present in a non symetrical molecule ... then it is polar
and polar molecule have permanent dipole
THUS A IS 110 % correct
idk how to prove c d and e are polar though
how do i prove they are polar?
you know something about dipole moment >????
all i know is drawing lewis...and it seems tedious
you know something about dipole moment >????
yes i know dipole moment...somehow
or relative electronegativity of elements
when the directions of the electronegativity in the lewis cancel out then zero dipole moment
FLORINE, CHLORINE AND OXYGEN .. are the MOST ELECTRONEGATIVE ELEMENT
mmhmm
NO2 is polar because it has a lone electron
unbonded
yeah...i figured that one out already :D
H2S is polar because of 2 lone pairs
H2S i think looks something like |dw:1343732893300:dw|
yup its shape is bent
calcium nitrate...idk how that looks
you dont need the structure ..... just look at the oxygen ... secondly ... it is non symmetircal ... thus it must be polar
hmm i see
|dw:1343733005262:dw|
lol enough with H2S we've already confirmed it's polar :p
C2H6 looks like this right.. |dw:1343733047139:dw| that's why it's nonpolar?
lgbasallote ..its a basic question :D
well im not chemistry inclined -_-
i can call laplace transforms basic but you wont right? ;)
|dw:1343733096534:dw|
hmm bottomline they cancel hehe
yup :D
so wait....if there are no lone pairs then i's nonpolar?
it's*
not necessarily ...
oh
its must be symmetrical
|dw:1343733217757:dw|
|dw:1343733238479:dw|
you see the difference :D
ohhhh
anyway ..we are done with this question
yeah i think so too
CLOSSSSSSSEEEEEEEEEE IIIIITTTTT
|dw:1343733296219:dw|

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