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lgbasallote

For which of the following species are the intermolecular interactions entirely due to dispersion forces? A) C2H6 B) CH3OCH3 C) NO2 D) H2S E) CaNO3

  • one year ago
  • one year ago

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  1. lgbasallote
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    im thinking it would be the nonpolar molecule...so A?

    • one year ago
  2. Hashir
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    yup its A ...... because its non polar ..... we have hydrogen bonding in B, C and D

    • one year ago
  3. Hashir
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    thus instantaneous-induced dipole forces are present between non polar molecule :D

    • one year ago
  4. lgbasallote
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    c d and e dont have h-bonding o.O

    • one year ago
  5. Hashir
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    sorry //// C , D , and E are POLAR

    • one year ago
  6. Hashir
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    i misread the question :( //// but the answer is A

    • one year ago
  7. Hashir
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    when flourine , chlorine, oxygen and nitrogen are present in a non symetrical molecule ... then it is polar

    • one year ago
  8. Hashir
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    and polar molecule have permanent dipole

    • one year ago
  9. Hashir
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    THUS A IS 110 % correct

    • one year ago
  10. lgbasallote
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    idk how to prove c d and e are polar though

    • one year ago
  11. lgbasallote
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    how do i prove they are polar?

    • one year ago
  12. Hashir
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    you know something about dipole moment >????

    • one year ago
  13. lgbasallote
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    all i know is drawing lewis...and it seems tedious

    • one year ago
  14. Hashir
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    you know something about dipole moment >????

    • one year ago
  15. lgbasallote
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    yes i know dipole moment...somehow

    • one year ago
  16. Hashir
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    or relative electronegativity of elements

    • one year ago
  17. lgbasallote
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    when the directions of the electronegativity in the lewis cancel out then zero dipole moment

    • one year ago
  18. Hashir
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    FLORINE, CHLORINE AND OXYGEN .. are the MOST ELECTRONEGATIVE ELEMENT

    • one year ago
  19. lgbasallote
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    mmhmm

    • one year ago
  20. Hashir
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    NO2 is polar because it has a lone electron

    • one year ago
  21. Hashir
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    unbonded

    • one year ago
  22. lgbasallote
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    yeah...i figured that one out already :D

    • one year ago
  23. Hashir
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    H2S is polar because of 2 lone pairs

    • one year ago
  24. lgbasallote
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    H2S i think looks something like |dw:1343732893300:dw|

    • one year ago
  25. Hashir
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    yup its shape is bent

    • one year ago
  26. lgbasallote
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    calcium nitrate...idk how that looks

    • one year ago
  27. Hashir
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    you dont need the structure ..... just look at the oxygen ... secondly ... it is non symmetircal ... thus it must be polar

    • one year ago
  28. lgbasallote
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    hmm i see

    • one year ago
  29. Hashir
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    |dw:1343733005262:dw|

    • one year ago
  30. lgbasallote
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    lol enough with H2S we've already confirmed it's polar :p

    • one year ago
  31. lgbasallote
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    C2H6 looks like this right.. |dw:1343733047139:dw| that's why it's nonpolar?

    • one year ago
  32. Hashir
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    lgbasallote ..its a basic question :D

    • one year ago
  33. lgbasallote
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    well im not chemistry inclined -_-

    • one year ago
  34. lgbasallote
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    i can call laplace transforms basic but you wont right? ;)

    • one year ago
  35. Hashir
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    |dw:1343733096534:dw|

    • one year ago
  36. lgbasallote
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    hmm bottomline they cancel hehe

    • one year ago
  37. Hashir
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    yup :D

    • one year ago
  38. lgbasallote
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    so wait....if there are no lone pairs then i's nonpolar?

    • one year ago
  39. lgbasallote
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    it's*

    • one year ago
  40. Hashir
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    not necessarily ...

    • one year ago
  41. lgbasallote
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    oh

    • one year ago
  42. Hashir
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    its must be symmetrical

    • one year ago
  43. Hashir
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    |dw:1343733217757:dw|

    • one year ago
  44. Hashir
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    |dw:1343733238479:dw|

    • one year ago
  45. Hashir
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    you see the difference :D

    • one year ago
  46. lgbasallote
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    ohhhh

    • one year ago
  47. Hashir
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    anyway ..we are done with this question

    • one year ago
  48. lgbasallote
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    yeah i think so too

    • one year ago
  49. Hashir
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    CLOSSSSSSSEEEEEEEEEE IIIIITTTTT

    • one year ago
  50. Hashir
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    |dw:1343733296219:dw|

    • one year ago
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