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anonymous
 3 years ago
For which of the following species are the intermolecular interactions entirely due to dispersion forces?
A) C2H6 B) CH3OCH3 C) NO2 D) H2S E) CaNO3
anonymous
 3 years ago
For which of the following species are the intermolecular interactions entirely due to dispersion forces? A) C2H6 B) CH3OCH3 C) NO2 D) H2S E) CaNO3

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im thinking it would be the nonpolar molecule...so A?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yup its A ...... because its non polar ..... we have hydrogen bonding in B, C and D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thus instantaneousinduced dipole forces are present between non polar molecule :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0c d and e dont have hbonding o.O

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sorry //// C , D , and E are POLAR

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i misread the question :( //// but the answer is A

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0when flourine , chlorine, oxygen and nitrogen are present in a non symetrical molecule ... then it is polar

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and polar molecule have permanent dipole

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0THUS A IS 110 % correct

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0idk how to prove c d and e are polar though

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how do i prove they are polar?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you know something about dipole moment >????

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0all i know is drawing lewis...and it seems tedious

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you know something about dipole moment >????

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes i know dipole moment...somehow

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0or relative electronegativity of elements

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0when the directions of the electronegativity in the lewis cancel out then zero dipole moment

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0FLORINE, CHLORINE AND OXYGEN .. are the MOST ELECTRONEGATIVE ELEMENT

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0NO2 is polar because it has a lone electron

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah...i figured that one out already :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0H2S is polar because of 2 lone pairs

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0H2S i think looks something like dw:1343732893300:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yup its shape is bent

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0calcium nitrate...idk how that looks

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you dont need the structure ..... just look at the oxygen ... secondly ... it is non symmetircal ... thus it must be polar

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1343733005262:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lol enough with H2S we've already confirmed it's polar :p

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0C2H6 looks like this right.. dw:1343733047139:dw that's why it's nonpolar?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lgbasallote ..its a basic question :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well im not chemistry inclined _

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i can call laplace transforms basic but you wont right? ;)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1343733096534:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmm bottomline they cancel hehe

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so wait....if there are no lone pairs then i's nonpolar?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its must be symmetrical

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1343733217757:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1343733238479:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you see the difference :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0anyway ..we are done with this question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0CLOSSSSSSSEEEEEEEEEE IIIIITTTTT

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1343733296219:dw
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