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|dw:1343747395406:dw|
got \[2x \sqrt{2y}\]
y can be writen as root(y)*root(y)

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Other answers:

Let me first start off by saying that you have an amazingly original username. Anyways, the key simplification here has to do with rationalization of the denominator.
\[\LARGE{\frac{y}{x}\sqrt{\frac{1}{2y}}}\] \[\LARGE{\frac{y}{x}\frac{\sqrt{1}}{\sqrt{2y}}}\]
So as the guy above me showed, You get sqrt(y)/(x*sqrt(2)*sqrt(y))
@helpme9283 are u giving some test...... You should tell what u have tried so far.........
sqrt y 's cancel, and to rationalize the sqrt two you multiply the numerator and denom by root 2
@vf321 @mathslover Please wait untill he submits his own solution........... Our work is to help and not to answer....
got |dw:1343747583084:dw|
good job
Gud work............ :)
@vishweshshrimali5 review my answers. How was i not directing him?
@vf321 I am not blaming u....... I just want @helpme9283 to submit his own solution first so that we can see where is he going wrong........
\[\LARGE{\frac{y}{x}\frac{1}{\sqrt{2y}}}\] \[\LARGE{\frac{y}{x}(\frac{1*\sqrt{2y}}{2y})}\] \[\LARGE{\frac{y}{x}(\frac{\sqrt{2y}}{2y}})\] JUST A HINT .. @helpme9283 please upload what you got?
ok so u did .. sorry didn't see but good work
Lol @mathslover we beat you to it by like a minute...
..sorry was busy... :D @vf321

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