anonymous
  • anonymous
Can you explain how to do this? (2x^2y^3)(-3x^3y^4)(6xy)=?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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amistre64
  • amistre64
id stack them to keep track of it better
anonymous
  • anonymous
What do you mean?
amistre64
  • amistre64
2 x^2 y^3 -3 x^3 y^4 6 x y i mean, id stack them so that i could keep track of them better :/

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More answers

anonymous
  • anonymous
ohh okay
jiteshmeghwal9
  • jiteshmeghwal9
\[(2.-3.6)x^2y^3x^3y^4xy\]
anonymous
  • anonymous
my bad
amistre64
  • amistre64
like bases add exponents; and constants just get mulitplied together
jiteshmeghwal9
  • jiteshmeghwal9
multiply the constants & multiply the like terms to gt ur answer
jiteshmeghwal9
  • jiteshmeghwal9
gt it @maherman97 ???
anonymous
  • anonymous
no... haha what do you mean the constants?
jiteshmeghwal9
  • jiteshmeghwal9
constants=numerical terms
jiteshmeghwal9
  • jiteshmeghwal9
such as 3,5 etc.
anonymous
  • anonymous
well can you walk me through the steps?
anonymous
  • anonymous
i would start by multiplying (6xy) by 2x^2y^3) get the answer and the multiplying the answer by (-3x^3y^4)
anonymous
  • anonymous
how do you multiply the first part?
anonymous
  • anonymous
ok . (6xy)(2x^2y^3)= 12x^3y^4 using exponents rules.
anonymous
  • anonymous
okay so then why do i multiply that by (-3x^3y^4)
anonymous
  • anonymous
that what the operator dose.
anonymous
  • anonymous
the what???
anonymous
  • anonymous
im soooo confused!
anonymous
  • anonymous
(A)(B)(C) means A multiply B multiply C as an example .
anonymous
  • anonymous
rightt....
anonymous
  • anonymous
So then i multiply 12x^3y^4 by (-3x^3y^4)
anonymous
  • anonymous
SO THAS why we use the operator (multiplication) thats what i mean by "operator" hope that helps
anonymous
  • anonymous
okay so can you show me the steps into multiplying 12x^3y^4 by (-3x^3y^4)
anonymous
  • anonymous
sure.
anonymous
  • anonymous
so what do i do first?
anonymous
  • anonymous
1>multiply 12by -3 = -36 2> x^3by x^3 = x^6 3> y^4 by y^4= y^8
anonymous
  • anonymous
so it would be -36x^8y^8?
anonymous
  • anonymous
x^6* my badd
anonymous
  • anonymous
okay thanks soooo much!
anonymous
  • anonymous
ive got another for you
anonymous
  • anonymous
i would appreciate a "BEST REPONSE " if you think so?? :)
anonymous
  • anonymous
thanks
anonymous
  • anonymous
sooo if i have \[(3x)^{3}(4x)^{2}\] would the answer be 216?
anonymous
  • anonymous
no (3x)3(4x)2 thats not the same. be careful mate.. :)
anonymous
  • anonymous
so what would it be? and what did i do wrong?
anonymous
  • anonymous
\[(3x)^3\] is not the same as \[3x^2\] = henc \[(3x)^3\]=\[3^3 x^3= 27x^3\] and \[3x^3=3x^3\]

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