maherman97 3 years ago Can you explain how to do this? (2x^2y^3)(-3x^3y^4)(6xy)=?

1. amistre64

id stack them to keep track of it better

2. maherman97

What do you mean?

3. amistre64

2 x^2 y^3 -3 x^3 y^4 6 x y i mean, id stack them so that i could keep track of them better :/

4. maherman97

ohh okay

5. jiteshmeghwal9

\[(2.-3.6)x^2y^3x^3y^4xy\]

6. maherman97

7. amistre64

like bases add exponents; and constants just get mulitplied together

8. jiteshmeghwal9

multiply the constants & multiply the like terms to gt ur answer

9. jiteshmeghwal9

gt it @maherman97 ???

10. maherman97

no... haha what do you mean the constants?

11. jiteshmeghwal9

constants=numerical terms

12. jiteshmeghwal9

such as 3,5 etc.

13. maherman97

well can you walk me through the steps?

14. hal_stirrup

i would start by multiplying (6xy) by 2x^2y^3) get the answer and the multiplying the answer by (-3x^3y^4)

15. maherman97

how do you multiply the first part?

16. hal_stirrup

ok . (6xy)(2x^2y^3)= 12x^3y^4 using exponents rules.

17. maherman97

okay so then why do i multiply that by (-3x^3y^4)

18. hal_stirrup

that what the operator dose.

19. maherman97

the what???

20. maherman97

im soooo confused!

21. hal_stirrup

(A)(B)(C) means A multiply B multiply C as an example .

22. maherman97

rightt....

23. maherman97

So then i multiply 12x^3y^4 by (-3x^3y^4)

24. hal_stirrup

SO THAS why we use the operator (multiplication) thats what i mean by "operator" hope that helps

25. maherman97

okay so can you show me the steps into multiplying 12x^3y^4 by (-3x^3y^4)

26. hal_stirrup

sure.

27. maherman97

so what do i do first?

28. hal_stirrup

1>multiply 12by -3 = -36 2> x^3by x^3 = x^6 3> y^4 by y^4= y^8

29. maherman97

so it would be -36x^8y^8?

30. maherman97

31. maherman97

okay thanks soooo much!

32. maherman97

ive got another for you

33. hal_stirrup

i would appreciate a "BEST REPONSE " if you think so?? :)

34. hal_stirrup

thanks

35. maherman97

sooo if i have \[(3x)^{3}(4x)^{2}\] would the answer be 216?

36. hal_stirrup

no (3x)3(4x)2 thats not the same. be careful mate.. :)

37. maherman97

so what would it be? and what did i do wrong?

38. hal_stirrup

\[(3x)^3\] is not the same as \[3x^2\] = henc \[(3x)^3\]=\[3^3 x^3= 27x^3\] and \[3x^3=3x^3\]