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maherman97

  • 2 years ago

Can you explain how to do this? (2x^2y^3)(-3x^3y^4)(6xy)=?

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  1. amistre64
    • 2 years ago
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    id stack them to keep track of it better

  2. maherman97
    • 2 years ago
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    What do you mean?

  3. amistre64
    • 2 years ago
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    2 x^2 y^3 -3 x^3 y^4 6 x y i mean, id stack them so that i could keep track of them better :/

  4. maherman97
    • 2 years ago
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    ohh okay

  5. jiteshmeghwal9
    • 2 years ago
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    \[(2.-3.6)x^2y^3x^3y^4xy\]

  6. maherman97
    • 2 years ago
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    my bad

  7. amistre64
    • 2 years ago
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    like bases add exponents; and constants just get mulitplied together

  8. jiteshmeghwal9
    • 2 years ago
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    multiply the constants & multiply the like terms to gt ur answer

  9. jiteshmeghwal9
    • 2 years ago
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    gt it @maherman97 ???

  10. maherman97
    • 2 years ago
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    no... haha what do you mean the constants?

  11. jiteshmeghwal9
    • 2 years ago
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    constants=numerical terms

  12. jiteshmeghwal9
    • 2 years ago
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    such as 3,5 etc.

  13. maherman97
    • 2 years ago
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    well can you walk me through the steps?

  14. hal_stirrup
    • 2 years ago
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    i would start by multiplying (6xy) by 2x^2y^3) get the answer and the multiplying the answer by (-3x^3y^4)

  15. maherman97
    • 2 years ago
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    how do you multiply the first part?

  16. hal_stirrup
    • 2 years ago
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    ok . (6xy)(2x^2y^3)= 12x^3y^4 using exponents rules.

  17. maherman97
    • 2 years ago
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    okay so then why do i multiply that by (-3x^3y^4)

  18. hal_stirrup
    • 2 years ago
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    that what the operator dose.

  19. maherman97
    • 2 years ago
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    the what???

  20. maherman97
    • 2 years ago
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    im soooo confused!

  21. hal_stirrup
    • 2 years ago
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    (A)(B)(C) means A multiply B multiply C as an example .

  22. maherman97
    • 2 years ago
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    rightt....

  23. maherman97
    • 2 years ago
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    So then i multiply 12x^3y^4 by (-3x^3y^4)

  24. hal_stirrup
    • 2 years ago
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    SO THAS why we use the operator (multiplication) thats what i mean by "operator" hope that helps

  25. maherman97
    • 2 years ago
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    okay so can you show me the steps into multiplying 12x^3y^4 by (-3x^3y^4)

  26. hal_stirrup
    • 2 years ago
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    sure.

  27. maherman97
    • 2 years ago
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    so what do i do first?

  28. hal_stirrup
    • 2 years ago
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    1>multiply 12by -3 = -36 2> x^3by x^3 = x^6 3> y^4 by y^4= y^8

  29. maherman97
    • 2 years ago
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    so it would be -36x^8y^8?

  30. maherman97
    • 2 years ago
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    x^6* my badd

  31. maherman97
    • 2 years ago
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    okay thanks soooo much!

  32. maherman97
    • 2 years ago
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    ive got another for you

  33. hal_stirrup
    • 2 years ago
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    i would appreciate a "BEST REPONSE " if you think so?? :)

  34. hal_stirrup
    • 2 years ago
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    thanks

  35. maherman97
    • 2 years ago
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    sooo if i have \[(3x)^{3}(4x)^{2}\] would the answer be 216?

  36. hal_stirrup
    • 2 years ago
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    no (3x)3(4x)2 thats not the same. be careful mate.. :)

  37. maherman97
    • 2 years ago
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    so what would it be? and what did i do wrong?

  38. hal_stirrup
    • 2 years ago
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    \[(3x)^3\] is not the same as \[3x^2\] = henc \[(3x)^3\]=\[3^3 x^3= 27x^3\] and \[3x^3=3x^3\]

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