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id stack them to keep track of it better

What do you mean?

2 x^2 y^3
-3 x^3 y^4
6 x y
i mean, id stack them so that i could keep track of them better :/

ohh okay

\[(2.-3.6)x^2y^3x^3y^4xy\]

my bad

like bases add exponents; and constants just get mulitplied together

multiply the constants & multiply the like terms to gt ur answer

gt it @maherman97 ???

no... haha what do you mean the constants?

constants=numerical terms

such as 3,5 etc.

well can you walk me through the steps?

how do you multiply the first part?

ok . (6xy)(2x^2y^3)= 12x^3y^4 using exponents rules.

okay so then why do i multiply that by (-3x^3y^4)

that what the operator dose.

the what???

im soooo confused!

(A)(B)(C) means A multiply B multiply C as an example .

rightt....

So then i multiply 12x^3y^4 by (-3x^3y^4)

SO THAS why we use the operator (multiplication) thats what i mean by "operator" hope that helps

okay so can you show me the steps into multiplying 12x^3y^4 by (-3x^3y^4)

sure.

so what do i do first?

1>multiply 12by -3 = -36
2> x^3by x^3 = x^6
3> y^4 by y^4= y^8

so it would be -36x^8y^8?

x^6* my badd

okay thanks soooo much!

ive got another for you

i would appreciate a "BEST REPONSE " if you think so?? :)

thanks

sooo if i have \[(3x)^{3}(4x)^{2}\] would the answer be 216?

no (3x)3(4x)2 thats not the same. be careful mate.. :)

so what would it be? and what did i do wrong?

\[(3x)^3\] is not the same as
\[3x^2\] = henc \[(3x)^3\]=\[3^3 x^3= 27x^3\]
and \[3x^3=3x^3\]