Ingiee0118
Please help ...
Evaluate :
Sqr Rt Of 81 + 3^2 - 6 - Sqr Rt Of 16 .....
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lgbasallote
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what is \(\sqrt{81}\)?
lgbasallote
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what do you think is the value of that?
LemuelPogi
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its 5
xD
LemuelPogi
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9-4 = 5 ow im wrong 3^2 is not equal to 6 so its
\[\sqrt{84} - \sqrt{16}\]
I think its
\[2\sqrt{21} + 4 \]
I am not quite sure but it can be simplified the two will not exist and 4 will be 2
hal_stirrup
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8
lgbasallote
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?
lgbasallote
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go on...keep shooting random guesses...im sure you'll hit the right one someday
hal_stirrup
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\[\sqrt{81}+3^2-6-\sqrt{16}\]=9+9-6-4=8
hal_stirrup
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if thats the question then the answer is 8 for sure.... :)
Ingiee0118
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Thank you so muchh :) hal_stirrup :D
hal_stirrup
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welcome @ngiee0118
hal_stirrup
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@Ingiee0118
Ingiee0118
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So your good at math ...? Can you help me with another question ? pleaseeeeeee .?
:))
hal_stirrup
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i can try
hal_stirrup
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you can be my fan and so do i ?
Ingiee0118
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Which set of line segments with the given lengths form a right triangle?
A ) 9, 27, 81
B ) 10, 24, 38
C )14, 16, 22
D) 15, 36, 39
Ingiee0118
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There i am a fan :)
hal_stirrup
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nice
Ingiee0118
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So can you help me with that question ?
hal_stirrup
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its being some time since i did trig. i fine out.
Ingiee0118
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Huh ...?
hal_stirrup
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ok use pythagorean theorem, a^2 + b^2 = c^2
Ingiee0118
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Gur ... Okay thankyou (:
hal_stirrup
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the answer is D
hal_stirrup
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here is how its done.
A ) 9, 27, 81 let 9=a , b=27 and c=81
the pythagorean theorem, a^2 + b^2 = c^2
so plug in the values and see if a^2 + b^2=c^2 .
hal_stirrup
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if this hold the you have the right answer. If not then try the B and c and D. THATS what i did and found out D IS the right answer
Ingiee0118
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Thankyouu(: So much !
hal_stirrup
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welcome. is that happy or sad face?
Ingiee0118
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HAPPY (:
hal_stirrup
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ok thats my happy face :)
Ingiee0118
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:D