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Please help ... Evaluate : Sqr Rt Of 81 + 3^2 - 6 - Sqr Rt Of 16 .....

Mathematics
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what is \(\sqrt{81}\)?
what do you think is the value of that?
its 5 xD

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Other answers:

9-4 = 5 ow im wrong 3^2 is not equal to 6 so its \[\sqrt{84} - \sqrt{16}\] I think its \[2\sqrt{21} + 4 \] I am not quite sure but it can be simplified the two will not exist and 4 will be 2
8
?
go on...keep shooting random guesses...im sure you'll hit the right one someday
\[\sqrt{81}+3^2-6-\sqrt{16}\]=9+9-6-4=8
if thats the question then the answer is 8 for sure.... :)
Thank you so muchh :) hal_stirrup :D
welcome @ngiee0118
So your good at math ...? Can you help me with another question ? pleaseeeeeee .? :))
i can try
you can be my fan and so do i ?
Which set of line segments with the given lengths form a right triangle? A ) 9, 27, 81 B ) 10, 24, 38 C )14, 16, 22 D) 15, 36, 39
There i am a fan :)
nice
So can you help me with that question ?
its being some time since i did trig. i fine out.
Huh ...?
ok use pythagorean theorem, a^2 + b^2 = c^2
Gur ... Okay thankyou (:
the answer is D
here is how its done. A ) 9, 27, 81 let 9=a , b=27 and c=81 the pythagorean theorem, a^2 + b^2 = c^2 so plug in the values and see if a^2 + b^2=c^2 .
if this hold the you have the right answer. If not then try the B and c and D. THATS what i did and found out D IS the right answer
Thankyouu(: So much !
welcome. is that happy or sad face?
HAPPY (:
ok thats my happy face :)
:D

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