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matias.mingo
Group Title
Heres a good one ; ) :
A solution of sodium carbonate is made using 79.5 grams of sodium carbonate in 250 cm3 of solution. 36.0 cm3 of this solution will neutralise 42.0 cm3 of a solution of hydrochloric acid.
Calculate the molarity of the hydrochloric acid solution.
 one year ago
 one year ago
matias.mingo Group Title
Heres a good one ; ) : A solution of sodium carbonate is made using 79.5 grams of sodium carbonate in 250 cm3 of solution. 36.0 cm3 of this solution will neutralise 42.0 cm3 of a solution of hydrochloric acid. Calculate the molarity of the hydrochloric acid solution.
 one year ago
 one year ago

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matias.mingo Group TitleBest ResponseYou've already chosen the best response.1
Firs i found the amount of moles of sodium carbonate in the 79.5 grams of it and it gave me 0.76 moles aprox. Then i found the molarity of it in the 250 cm3 solution and it gave me 0.0304mol/dm3(liter) Then i got the amount of moles in the 36.0 grams of sodium carbonate and it gave me 0.11 moles So then i said: 0.11 moles of sodium carbonate will neutralise 42 cm3 of hydrochloric acid. After that i don't know how to finish it
 one year ago

Ala123 Group TitleBest ResponseYou've already chosen the best response.0
good one... :)
 one year ago

matias.mingo Group TitleBest ResponseYou've already chosen the best response.1
Anyone? : )
 one year ago

NotTim Group TitleBest ResponseYou've already chosen the best response.1
molarity? that's like molar mass right? or is this n?
 one year ago

matias.mingo Group TitleBest ResponseYou've already chosen the best response.1
Molarity is equal to moles of solute over dm3(or liters) of solution. M=moles of solute (g)/ decimeter cubed of solution (dm3)
 one year ago

NotTim Group TitleBest ResponseYou've already chosen the best response.1
i probably just failed my chem exam them....whooops
 one year ago

matias.mingo Group TitleBest ResponseYou've already chosen the best response.1
lol its ok
 one year ago

Ala123 Group TitleBest ResponseYou've already chosen the best response.0
M=mol/L ! @NotTim ya you probably would lol jk jk don't kill me :D
 one year ago

Kryten Group TitleBest ResponseYou've already chosen the best response.0
ok so you have sodium carbonate which is: Na2CO3 right? and you neutralize it with HCl right? so equation goes as follows: Na2CO3 + 2HCl > 2NaCl + CO2 + H2O so if you calculated amount of Na2CO3 in moles now you see the ratio and write following: n(HCl)/n(Na2CO3) = 2/1 > n(HCl) = 2 * n(Na2CO3) and i think you got it from here, if not just say and ill continue ;)
 one year ago

matias.mingo Group TitleBest ResponseYou've already chosen the best response.1
It was so simple. Thank you so much
 one year ago
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