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Kingjames1

  • 3 years ago

Solve: 10^x=1/3

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  1. panlac01
    • 3 years ago
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    pp 227 http://finedrafts.com/files/Larson%20PreCal%208th/Larson_Precalculus_8th_txtbk.pdf

  2. hal_stirrup
    • 3 years ago
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    how do you think you can bring down the x? what operator do you need to use?

  3. panlac01
    • 3 years ago
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    try it in a calculator, hal

  4. Kingjames1
    • 3 years ago
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    so does x=30

  5. panlac01
    • 3 years ago
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    \[10^{30}=1/3 (are you sure???)\]

  6. hal_stirrup
    • 3 years ago
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    am calling it a day . going to eat and sleep . sorry if confused you.

  7. panlac01
    • 3 years ago
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    you didn't confuse me. you confused yourself :)

  8. Kingjames1
    • 3 years ago
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    so x=2.095

  9. hal_stirrup
    • 3 years ago
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    ok . solve it.

  10. hal_stirrup
    • 3 years ago
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    x = -(log(3))/(log(10)) x=-0.477121

  11. Kingjames1
    • 3 years ago
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    i got x=0

  12. Kingjames1
    • 3 years ago
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    how did u get the negative 9

  13. Kingjames1
    • 3 years ago
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    i mean 0

  14. hal_stirrup
    • 3 years ago
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    ok 10^x = 1/3 Take the logarithm to the base 10 of both sides: x = -(log(3))/(log(10)) x=-0.477121

  15. Kingjames1
    • 3 years ago
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    ok i get it

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