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panlac01Best ResponseYou've already chosen the best response.1
pp 227 http://finedrafts.com/files/Larson%20PreCal%208th/Larson_Precalculus_8th_txtbk.pdf
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.2
how do you think you can bring down the x? what operator do you need to use?
 one year ago

panlac01Best ResponseYou've already chosen the best response.1
try it in a calculator, hal
 one year ago

panlac01Best ResponseYou've already chosen the best response.1
\[10^{30}=1/3 (are you sure???)\]
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.2
am calling it a day . going to eat and sleep . sorry if confused you.
 one year ago

panlac01Best ResponseYou've already chosen the best response.1
you didn't confuse me. you confused yourself :)
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.2
x = (log(3))/(log(10)) x=0.477121
 one year ago

Kingjames1Best ResponseYou've already chosen the best response.0
how did u get the negative 9
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.2
ok 10^x = 1/3 Take the logarithm to the base 10 of both sides: x = (log(3))/(log(10)) x=0.477121
 one year ago
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