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Kingjames1 Group Title

Solve: 10^x=1/3

  • 2 years ago
  • 2 years ago

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  1. panlac01 Group Title
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    pp 227 http://finedrafts.com/files/Larson%20PreCal%208th/Larson_Precalculus_8th_txtbk.pdf

    • 2 years ago
  2. hal_stirrup Group Title
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    how do you think you can bring down the x? what operator do you need to use?

    • 2 years ago
  3. panlac01 Group Title
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    try it in a calculator, hal

    • 2 years ago
  4. Kingjames1 Group Title
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    so does x=30

    • 2 years ago
  5. panlac01 Group Title
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    \[10^{30}=1/3 (are you sure???)\]

    • 2 years ago
  6. hal_stirrup Group Title
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    am calling it a day . going to eat and sleep . sorry if confused you.

    • 2 years ago
  7. panlac01 Group Title
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    you didn't confuse me. you confused yourself :)

    • 2 years ago
  8. Kingjames1 Group Title
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    so x=2.095

    • 2 years ago
  9. hal_stirrup Group Title
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    ok . solve it.

    • 2 years ago
  10. hal_stirrup Group Title
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    x = -(log(3))/(log(10)) x=-0.477121

    • 2 years ago
  11. Kingjames1 Group Title
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    i got x=0

    • 2 years ago
  12. Kingjames1 Group Title
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    how did u get the negative 9

    • 2 years ago
  13. Kingjames1 Group Title
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    i mean 0

    • 2 years ago
  14. hal_stirrup Group Title
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    ok 10^x = 1/3 Take the logarithm to the base 10 of both sides: x = -(log(3))/(log(10)) x=-0.477121

    • 2 years ago
  15. Kingjames1 Group Title
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    ok i get it

    • 2 years ago
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