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panlac01 Group TitleBest ResponseYou've already chosen the best response.1
pp 227 http://finedrafts.com/files/Larson%20PreCal%208th/Larson_Precalculus_8th_txtbk.pdf
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.2
how do you think you can bring down the x? what operator do you need to use?
 2 years ago

panlac01 Group TitleBest ResponseYou've already chosen the best response.1
try it in a calculator, hal
 2 years ago

Kingjames1 Group TitleBest ResponseYou've already chosen the best response.0
so does x=30
 2 years ago

panlac01 Group TitleBest ResponseYou've already chosen the best response.1
\[10^{30}=1/3 (are you sure???)\]
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.2
am calling it a day . going to eat and sleep . sorry if confused you.
 2 years ago

panlac01 Group TitleBest ResponseYou've already chosen the best response.1
you didn't confuse me. you confused yourself :)
 2 years ago

Kingjames1 Group TitleBest ResponseYou've already chosen the best response.0
so x=2.095
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.2
ok . solve it.
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.2
x = (log(3))/(log(10)) x=0.477121
 2 years ago

Kingjames1 Group TitleBest ResponseYou've already chosen the best response.0
i got x=0
 2 years ago

Kingjames1 Group TitleBest ResponseYou've already chosen the best response.0
how did u get the negative 9
 2 years ago

Kingjames1 Group TitleBest ResponseYou've already chosen the best response.0
i mean 0
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.2
ok 10^x = 1/3 Take the logarithm to the base 10 of both sides: x = (log(3))/(log(10)) x=0.477121
 2 years ago

Kingjames1 Group TitleBest ResponseYou've already chosen the best response.0
ok i get it
 2 years ago
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