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ash2326 Group TitleBest ResponseYou've already chosen the best response.1
@IloveCharlie what's 30' in degrees?
 2 years ago

GOODMAN Group TitleBest ResponseYou've already chosen the best response.1
Divide 30 seconds by 60. After that, add it to 67. Then take the cosine of it all.
 2 years ago

IloveCharlie Group TitleBest ResponseYou've already chosen the best response.0
Hmmm... I got .382. Can you please confirm?
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.1
yeah, it's right but could you use calculator for this? @IloveCharlie
 2 years ago

IloveCharlie Group TitleBest ResponseYou've already chosen the best response.0
I just don't know which one it matches up with :/ From the options given
 2 years ago

IloveCharlie Group TitleBest ResponseYou've already chosen the best response.0
Whoa @jim_thompson5910 you're typing a lot
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
Yes it's a lot, but it at least gives you the exact answer 67 degrees 30' = 67 degrees + 30/60 = 67+0.5 = 67.5 degress Notice how 2*67.5 = 135 and \[\Large \cos(135) = \frac{\sqrt{2}}{2}\] (using the unit circle) Now turn to the identity \[\Large \cos(x) = \sqrt{ \frac{ \cos(2x) + 1 }{2} }\] If we let x = 67.5, then \[\Large \cos(x) = \sqrt{ \frac{ \cos(2x) + 1 }{2} }\] \[\Large \cos(67.5) = \sqrt{ \frac{ \cos(2*67.5) + 1 }{2} }\] \[\Large \cos(67.5) = \sqrt{ \frac{ \cos(135) + 1 }{2} }\] \[\Large \cos(67.5) = \sqrt{ \frac{ \frac{\sqrt{2}}{2} + 1 }{2} }\] \[\Large \cos(67.5) = \sqrt{ \frac{ \frac{\sqrt{2}}{2} + \frac{2}{2} }{2} }\] \[\Large \cos(67.5) = \sqrt{ \frac{ \frac{\sqrt{2}+2}{2} }{2} }\] \[\Large \cos(67.5) = \sqrt{ \frac{ \frac{2\sqrt{2}}{2} }{2} }\] \[\Large \cos(67.5) = \sqrt{ \left( \frac{2\sqrt{2}}{2} \right)\left(\frac{1}{2}\right) }\] \[\Large \cos(67.5) = \sqrt{ \frac{(2\sqrt{2})*1}{2*2} }\] \[\Large \cos(67.5) = \sqrt{ \frac{2\sqrt{2}}{4} }\] \[\Large \cos(67.5) = \frac{\sqrt{2\sqrt{2}}}{\sqrt{4}}\] \[\Large \cos(67.5) = \frac{\sqrt{2\sqrt{2}}}{2}\]
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
sry i had a typo, but i fixed it
 2 years ago

IloveCharlie Group TitleBest ResponseYou've already chosen the best response.0
Wow, thanks so much for the awesome step by step explanation! Really helps!
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
you're welcome
 2 years ago
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