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mathsux4real
Group Title
Last problem I need help with! Please! Using the given data, find the values of sine, cosine, and tangent of 2 A and the quadrant in which 2 A terminates: angle A in Quadrant II, cos A = 7/25
cos 2 A =
a. 527/625
b. 336/625
c. 336/625
d. 527/625
 one year ago
 one year ago
mathsux4real Group Title
Last problem I need help with! Please! Using the given data, find the values of sine, cosine, and tangent of 2 A and the quadrant in which 2 A terminates: angle A in Quadrant II, cos A = 7/25 cos 2 A = a. 527/625 b. 336/625 c. 336/625 d. 527/625
 one year ago
 one year ago

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ajprincess Group TitleBest ResponseYou've already chosen the best response.1
\(\cos2A=2\cos A\sin A\) Find the value of sinA using \(\sin A=\sqrt{1\cos^2A}\). Can u do nw?
 one year ago

mathsux4real Group TitleBest ResponseYou've already chosen the best response.0
So 2(0.28)(0.276)
 one year ago

mathsux4real Group TitleBest ResponseYou've already chosen the best response.0
:/ It's not matching up
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.1
Find them in the fraction form. Vat do u get for sinA?
 one year ago

mathsux4real Group TitleBest ResponseYou've already chosen the best response.0
69/250
 one year ago

muhammad9t5 Group TitleBest ResponseYou've already chosen the best response.1
cos=Adjacent/Hypotenuse and sin=Opposite/Hypotenuse and tan=Opposite/ajacent so here you have given just adjacent and hypotenuse and you can fine opposite by Pythagourus Theorum.
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.1
\(\sin A=\sqrt{1\cos^2A}\) \(\sin A=\sqrt{1(\large\frac{7}{25})^2}\) \(\sin A=\sqrt{1\large\frac{49}{625}}\) \(\sin A=\sqrt{\large\frac{62549}{625}}\) \(\sin A=\sqrt{\large\frac{576}{625}}\) \(\sin A=\large\frac{24}{25}\) Nw can u find cos2A?
 one year ago

muhammad9t5 Group TitleBest ResponseYou've already chosen the best response.1
its hard method friend. find sin by sin=perp/hyp we need perp so from cos=base/hyp here base=7 and hyp=25 so now use Pythagoras theorem to find perp.
 one year ago

mathsux4real Group TitleBest ResponseYou've already chosen the best response.0
Yes! 336/625. Thank you so much for step by step explanation! @ajprincess Thank you to @muhammad9t5 as well. I appreciate the time and effort my friends
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.1
U r welcome.:)
 one year ago

muhammad9t5 Group TitleBest ResponseYou've already chosen the best response.1
hyp^2=base^+perp^2 25^2=7^2+perp^2 625=49+perp^2 62549=perp^2 576=perp^2 24=perp
 one year ago

muhammad9t5 Group TitleBest ResponseYou've already chosen the best response.1
thanks! you are always welcome friend.
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.1
I agree vth u @muhammad9t5. Ur method is easy.
 one year ago

muhammad9t5 Group TitleBest ResponseYou've already chosen the best response.1
yup. @ajprincess please fan me.
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.1
I fanned u. i fan all those who fan me.:)
 one year ago
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