A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
Last problem I need help with! Please! Using the given data, find the values of sine, cosine, and tangent of 2 A and the quadrant in which 2 A terminates: angle A in Quadrant II, cos A = 7/25
cos 2 A =
a. 527/625
b. 336/625
c. 336/625
d. 527/625
 2 years ago
Last problem I need help with! Please! Using the given data, find the values of sine, cosine, and tangent of 2 A and the quadrant in which 2 A terminates: angle A in Quadrant II, cos A = 7/25 cos 2 A = a. 527/625 b. 336/625 c. 336/625 d. 527/625

This Question is Closed

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.1\(\cos2A=2\cos A\sin A\) Find the value of sinA using \(\sin A=\sqrt{1\cos^2A}\). Can u do nw?

mathsux4real
 2 years ago
Best ResponseYou've already chosen the best response.0So 2(0.28)(0.276)

mathsux4real
 2 years ago
Best ResponseYou've already chosen the best response.0:/ It's not matching up

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.1Find them in the fraction form. Vat do u get for sinA?

muhammad9t5
 2 years ago
Best ResponseYou've already chosen the best response.1cos=Adjacent/Hypotenuse and sin=Opposite/Hypotenuse and tan=Opposite/ajacent so here you have given just adjacent and hypotenuse and you can fine opposite by Pythagourus Theorum.

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.1\(\sin A=\sqrt{1\cos^2A}\) \(\sin A=\sqrt{1(\large\frac{7}{25})^2}\) \(\sin A=\sqrt{1\large\frac{49}{625}}\) \(\sin A=\sqrt{\large\frac{62549}{625}}\) \(\sin A=\sqrt{\large\frac{576}{625}}\) \(\sin A=\large\frac{24}{25}\) Nw can u find cos2A?

muhammad9t5
 2 years ago
Best ResponseYou've already chosen the best response.1its hard method friend. find sin by sin=perp/hyp we need perp so from cos=base/hyp here base=7 and hyp=25 so now use Pythagoras theorem to find perp.

mathsux4real
 2 years ago
Best ResponseYou've already chosen the best response.0Yes! 336/625. Thank you so much for step by step explanation! @ajprincess Thank you to @muhammad9t5 as well. I appreciate the time and effort my friends

muhammad9t5
 2 years ago
Best ResponseYou've already chosen the best response.1hyp^2=base^+perp^2 25^2=7^2+perp^2 625=49+perp^2 62549=perp^2 576=perp^2 24=perp

muhammad9t5
 2 years ago
Best ResponseYou've already chosen the best response.1thanks! you are always welcome friend.

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.1I agree vth u @muhammad9t5. Ur method is easy.

muhammad9t5
 2 years ago
Best ResponseYou've already chosen the best response.1yup. @ajprincess please fan me.

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.1I fanned u. i fan all those who fan me.:)
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.