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anonymous
 3 years ago
Matrix Help!
anonymous
 3 years ago
Matrix Help!

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what type of math class is this?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It's math team :) But it is Algebra II

angela210793
 3 years ago
Best ResponseYou've already chosen the best response.2I guess this is what you wanted :) dw:1343828412416:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Wait, what? o.O I understand what you did when you did the cofactor part, but not after that.

angela210793
 3 years ago
Best ResponseYou've already chosen the best response.2tell me on my drawing wht didnt u understand please

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1343828609211:dw Also, that wasn't the answer they gave?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Or was that just a part of the process?

angela210793
 3 years ago
Best ResponseYou've already chosen the best response.2just calculations O.odw:1343828726092:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0How does that work? o.O Sorry, I just haven't done TOO much with matrices yet...

angela210793
 3 years ago
Best ResponseYou've already chosen the best response.2Hmmmm....im sorry i am not sure how to explain you why it is like that....:( it just is like that hmmmm....u can try these...they r pretty good http://www.khanacademy.org/math/algebra/algebramatrices?k

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well, the final answer is a matrix...can you tell me what topic for matrices to watch? I've watched all of them to the extent of Algebra II material.

angela210793
 3 years ago
Best ResponseYou've already chosen the best response.2Hmmmm....maybe I've misunderstood wht u want to find... hang on a sec

angela210793
 3 years ago
Best ResponseYou've already chosen the best response.2watch inverting matrices

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Wouldn't the inverse be \[\left[\begin{matrix}2 & 1 \\ 4 & 4\end{matrix}\right]\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Or do I multiply by the reciprocal of the determinant?

angela210793
 3 years ago
Best ResponseYou've already chosen the best response.2tell me smth u want to find the inverse of the dw:1343829407799:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Would I perform this: \[\frac1{12}\left[\begin{matrix}2 & 1 \\ 4 & 4\end{matrix}\right]\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes. I want to find the inverse of what's above in your picture.

angela210793
 3 years ago
Best ResponseYou've already chosen the best response.2learnt this At Khan's videos so jusat plug in the numbers now dw:1343829481250:dw

angela210793
 3 years ago
Best ResponseYou've already chosen the best response.2or read this...is very well explained http://dcann.myweb.uga.edu/lect08add.pdf

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Isn't that what I did above? dw:1343829681330:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Alright, so the answer would be: \[\left[\begin{matrix}\frac16 & \frac1{12} \\ \frac13 & \frac13\end{matrix}\right]\]

angela210793
 3 years ago
Best ResponseYou've already chosen the best response.2shouldnt it be dw:1343830119553:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Is there supposed to an aboslute value on the A? not sure...I thought that a and d switched places and that b and c negated...maybe I'm wrong?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So it would be correct what I did?

angela210793
 3 years ago
Best ResponseYou've already chosen the best response.2hang on a sec pls...im on the phone

angela210793
 3 years ago
Best ResponseYou've already chosen the best response.2i said so...from the second link i sent u

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Wait. Let me check the link...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I have not gone that far into matrices quite yet...haven't learned to transpose... _

angela210793
 3 years ago
Best ResponseYou've already chosen the best response.2it was as u said...sorry...it's too hot in here _'' I'm not thinking well :p dw:1343830633083:dw

angela210793
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1343830704511:dw
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