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Calcmathlete

  • 3 years ago

Matrix Help!

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  1. Calcmathlete
    • 3 years ago
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  2. agentc0re
    • 3 years ago
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    what type of math class is this?

  3. Calcmathlete
    • 3 years ago
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    It's math team :) But it is Algebra II

  4. angela210793
    • 3 years ago
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    I guess this is what you wanted :) |dw:1343828412416:dw|

  5. Calcmathlete
    • 3 years ago
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    Wait, what? o.O I understand what you did when you did the cofactor part, but not after that.

  6. angela210793
    • 3 years ago
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    tell me on my drawing wht didnt u understand please

  7. Calcmathlete
    • 3 years ago
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    |dw:1343828609211:dw| Also, that wasn't the answer they gave?

  8. Calcmathlete
    • 3 years ago
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    Or was that just a part of the process?

  9. angela210793
    • 3 years ago
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    just calculations O.o|dw:1343828726092:dw|

  10. Calcmathlete
    • 3 years ago
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    How does that work? o.O Sorry, I just haven't done TOO much with matrices yet...

  11. angela210793
    • 3 years ago
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    Hmmmm....im sorry i am not sure how to explain you why it is like that....:( it just is like that hmmmm....u can try these...they r pretty good http://www.khanacademy.org/math/algebra/algebra-matrices?k

  12. Calcmathlete
    • 3 years ago
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    Well, the final answer is a matrix...can you tell me what topic for matrices to watch? I've watched all of them to the extent of Algebra II material.

  13. angela210793
    • 3 years ago
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    Hmmmm....maybe I've misunderstood wht u want to find... hang on a sec

  14. angela210793
    • 3 years ago
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    watch inverting matrices

  15. Calcmathlete
    • 3 years ago
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    Wouldn't the inverse be \[\left[\begin{matrix}-2 & 1 \\ 4 & 4\end{matrix}\right]\]

  16. Calcmathlete
    • 3 years ago
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    Or do I multiply by the reciprocal of the determinant?

  17. angela210793
    • 3 years ago
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    tell me smth u want to find the inverse of the |dw:1343829407799:dw|

  18. Calcmathlete
    • 3 years ago
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    Would I perform this: \[-\frac1{12}\left[\begin{matrix}-2 & 1 \\ 4 & 4\end{matrix}\right]\]

  19. Calcmathlete
    • 3 years ago
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    Yes. I want to find the inverse of what's above in your picture.

  20. angela210793
    • 3 years ago
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    learnt this At Khan's videos so jusat plug in the numbers now |dw:1343829481250:dw|

  21. angela210793
    • 3 years ago
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    or read this...is very well explained http://dcann.myweb.uga.edu/lect08add.pdf

  22. Calcmathlete
    • 3 years ago
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    Isn't that what I did above? |dw:1343829681330:dw|

  23. angela210793
    • 3 years ago
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    yup :)

  24. Calcmathlete
    • 3 years ago
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    Alright, so the answer would be: \[\left[\begin{matrix}\frac16 & -\frac1{12} \\ -\frac13 & -\frac13\end{matrix}\right]\]

  25. angela210793
    • 3 years ago
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    shouldnt it be |dw:1343830119553:dw|

  26. Calcmathlete
    • 3 years ago
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    Is there supposed to an aboslute value on the A? not sure...I thought that a and d switched places and that b and c negated...maybe I'm wrong?

  27. angela210793
    • 3 years ago
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    no abs value

  28. Calcmathlete
    • 3 years ago
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    So it would be correct what I did?

  29. angela210793
    • 3 years ago
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    hang on a sec pls...im on the phone

  30. angela210793
    • 3 years ago
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    i said so...from the second link i sent u

  31. Calcmathlete
    • 3 years ago
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    Wait. Let me check the link...

  32. angela210793
    • 3 years ago
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    oh wait ...-_-

  33. Calcmathlete
    • 3 years ago
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    I have not gone that far into matrices quite yet...haven't learned to transpose... -_-

  34. angela210793
    • 3 years ago
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    it was as u said...sorry...it's too hot in here -_-'' I'm not thinking well :p |dw:1343830633083:dw|

  35. Calcmathlete
    • 3 years ago
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    lol ok. Thanks :)

  36. angela210793
    • 3 years ago
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    |dw:1343830704511:dw|

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