A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Shiming, Doreen, and Brian are studying independently for their driver’s license test. The probability Shiming will pass the test is 3/5, the probability Doreen will pass the test is 3/28, and the probability Brian will pass the test is 3/10. What is the probability at least one of these people passes the test?
anonymous
 3 years ago
Shiming, Doreen, and Brian are studying independently for their driver’s license test. The probability Shiming will pass the test is 3/5, the probability Doreen will pass the test is 3/28, and the probability Brian will pass the test is 3/10. What is the probability at least one of these people passes the test?

This Question is Closed

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1i think we can find probability for NONE of them will pass. and subtract it from 1

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1probability for none of them passing = (13/5)(13/28)(13/10)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So it's 2/5 * 25/28 * 7/10?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1pls do check if there is some flaw in my logic.. . im feeling slight dyslexic today...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Let's see...your logic is correct, but I don't understand it...

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1i thought like this : P(atleast one of them passing) + P(none of them passing) = 1

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1P(atleast one of them passing) = 1  P(none of them passing)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1P(none of them passing) = P(A') . P(B') . P(C') note that these are mutually exclusive evens. one guy passing doesnt depend on other guys passing...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But why did you have me subtract one form A, B, and C and then subtract again?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1becos, P(A) + P(A') = 1

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1we are given P(A) < p(A passing) we need P(A') < p(A not passing)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1P(atleast one of them passing) = 1  P(none of them passing) P(none of them passing) = P(A') . P(B') . P(C')

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1we have used both above equations

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh. ok...now I get it...first you subtract the pass rate from 1 to get the non pass rate individually. Then multiply them to get the combined no pass rate, then subtract from 1 again to get the combined pass rate?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1thats exactly what we did :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.