Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Calcmathlete Group Title

Shiming, Doreen, and Brian are studying independently for their driver’s license test. The probability Shiming will pass the test is 3/5, the probability Doreen will pass the test is 3/28, and the probability Brian will pass the test is 3/10. What is the probability at least one of these people passes the test?

  • one year ago
  • one year ago

  • This Question is Closed
  1. ganeshie8 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i think we can find probability for NONE of them will pass. and subtract it from 1

    • one year ago
  2. ganeshie8 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    probability for none of them passing = (1-3/5)(1-3/28)(1-3/10)

    • one year ago
  3. Calcmathlete Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    So it's 2/5 * 25/28 * 7/10?

    • one year ago
  4. ganeshie8 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    1- that

    • one year ago
  5. Calcmathlete Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    So it's 7/8?

    • one year ago
  6. ganeshie8 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    wolfram says 3/4

    • one year ago
  7. ganeshie8 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    pls do check if there is some flaw in my logic.. . im feeling slight dyslexic today...

    • one year ago
  8. Calcmathlete Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Let's see...your logic is correct, but I don't understand it...

    • one year ago
  9. ganeshie8 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i thought like this : P(atleast one of them passing) + P(none of them passing) = 1

    • one year ago
  10. ganeshie8 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    P(atleast one of them passing) = 1 - P(none of them passing)

    • one year ago
  11. ganeshie8 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    P(none of them passing) = P(A') . P(B') . P(C') note that these are mutually exclusive evens. one guy passing doesnt depend on other guys passing...

    • one year ago
  12. Calcmathlete Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    But why did you have me subtract one form A, B, and C and then subtract again?

    • one year ago
  13. ganeshie8 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    becos, P(A) + P(A') = 1

    • one year ago
  14. ganeshie8 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    we are given P(A) <---- p(A passing) we need P(A') <------ p(A not passing)

    • one year ago
  15. ganeshie8 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    P(atleast one of them passing) = 1 - P(none of them passing) P(none of them passing) = P(A') . P(B') . P(C')

    • one year ago
  16. ganeshie8 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    we have used both above equations

    • one year ago
  17. Calcmathlete Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Oh. ok...now I get it...first you subtract the pass rate from 1 to get the non pass rate individually. Then multiply them to get the combined no pass rate, then subtract from 1 again to get the combined pass rate?

    • one year ago
  18. ganeshie8 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    thats exactly what we did :)

    • one year ago
  19. Calcmathlete Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    ALright THank you :)

    • one year ago
  20. ganeshie8 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    np.. :)

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.