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gfields444

  • 2 years ago

Solve x2 – 3x = 1

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  1. ParthKohli
    • 2 years ago
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    Try to bring in that 1 to the other side leaving zilch on the right hand.

  2. mathslover
    • 2 years ago
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    \[\large{x^2-3x-1=0}\] \[\large{roots=\frac{-b\pm\sqrt{b^2-4ac}}{2a}}\]

  3. ParthKohli
    • 2 years ago
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    \[ \color{Black}{\Rightarrow x^2 - 3x - 1 = 0}\]You're all set for problem solving.

  4. mathslover
    • 2 years ago
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    what do you think for a = ? , b = ? , c = ?

  5. mathslover
    • 2 years ago
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    ax^2+bx+c=0 | | | x^2 -3x-1 =0 hence a = 1 , b = -3 and c = 1

  6. gfields444
    • 2 years ago
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    x=3plus/minus sqrt13/2?

  7. best.shakir
    • 2 years ago
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    u can see here the answer and steps http://www.wolframalpha.com/input/?i=x2+%E2%80%93+3x+%3D+1+

  8. mathslover
    • 2 years ago
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    \[\large{roots = \frac{3\pm \sqrt{9-4}}{2}}\] \[\large{roots=\frac{3\pm\sqrt{5}}{2}}\]

  9. mathslover
    • 2 years ago
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    oh wait .. sorry : \[\large{roots=\frac{3\pm \sqrt{13}}{2}}\] good

  10. best.shakir
    • 2 years ago
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    u can see in dat link

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