Here's the question you clicked on:
gfields444
Solve x2 – 3x = 1
Try to bring in that 1 to the other side leaving zilch on the right hand.
\[\large{x^2-3x-1=0}\] \[\large{roots=\frac{-b\pm\sqrt{b^2-4ac}}{2a}}\]
\[ \color{Black}{\Rightarrow x^2 - 3x - 1 = 0}\]You're all set for problem solving.
what do you think for a = ? , b = ? , c = ?
ax^2+bx+c=0 | | | x^2 -3x-1 =0 hence a = 1 , b = -3 and c = 1
x=3plus/minus sqrt13/2?
u can see here the answer and steps http://www.wolframalpha.com/input/?i=x2+%E2%80%93+3x+%3D+1+
\[\large{roots = \frac{3\pm \sqrt{9-4}}{2}}\] \[\large{roots=\frac{3\pm\sqrt{5}}{2}}\]
oh wait .. sorry : \[\large{roots=\frac{3\pm \sqrt{13}}{2}}\] good
u can see in dat link